To retrieve the data from the file.txt: data = {} with open(‘file.txt’, ‘r’) as f: # opens the file for line in f: # reads line by line key, value = line.split(‘ : ‘) # retrieves the key and the value data[key.lower()] = value.rstrip() # key to lower case and removes end-of-line ‘\n’ Then, data[‘name’] … Read more
Very simple Use the str.split() function transform your alphabet soup, then split the single elements further by directly accessing them. For example: text=””‘ A1 A10 A10 B14 C1 C14 C14 C8 ”’ for t in text.split(): print( {t[0]: t[1:]} ) prints: {‘A’: ‘1’} {‘A’: ’10’} {‘A’: ’10’} {‘B’: ’14’} {‘C’: ‘1’} {‘C’: ’14’} {‘C’: ’14’} … Read more
You haven’t told us the expected format for the data or shown any existing code, so it’s impossible to know what you’re looking for, but this should get you at least 90% of the way there: use strict; use warnings; use Data::Dumper; my %config; my $group = ”; while (<DATA>) { chomp; next unless /\S/; … Read more
Let me try to answer your questions. Yes. There is no reason why you can’t. You need to write some sort of lexer to turn the expression into tokens. Then you can use the shunting yard algorithm to turn the expression into something you can easily evaluate. Use the result from (2) and evaluate it … Read more
import json import requests response = requests.get(…) json_data = json.loads(response.text) solved how to parse the response in python?
Use dateutil.parser.parse() parse the date string into a timezone aware datetime object, then use strftime() to get the format you want. For better explanation goto solved How to convert datetime string to another format [duplicate]
No, it’s a syntax error. It can’t be part of a multiplication since there cannot be an identifier with the name of a keyword. The only way to make this a valid part of a C program is as part of a string literal as part of a multibyte character constant as part of a … Read more
Use from this link and in doInBackground method you must have these code: if (jsonStr != null) { try { JSONObject jsonObj = new JSONObject(jsonStr); JSONObject data = jsonObj.getJSONObject(“data”); // Getting JSON Array node JSONArray ambulance = jsonObj.getJSONArray(“ambulance”); // looping through All ambulance for (int i = 0; i < ambulance.length(); i++) { JSONObject c … Read more
Easy as a one-liner: perl -lane ‘print join “,”, map qq(“$_”), @F[0, 1]’ -l handles newlines in print -n reads the input line by line -a splits each line on whitespace into the @F array @F[0, 1] is an array slice, it extracts the first two elements of the @F array map wraps each element … Read more
You need to set the delimiter to csv.reader function: csvreader = csv.reader(textfile, delimiter=”\t”) You didn’t do it in your code, so Python doesn’t split the line of your CSV file. That’s why it gives the error. If you have the file with all the columns of MySQL table, you can use LOAD DATA INFILE command. … Read more
try this convert the response json into NSDictionary NSDictionary *receivedDataDic = [NSJSONSerialization JSONObjectWithData:operation.responseObject options:kNilOptions error:&error]; now access the values which you want by using key names , like NSString * id = [receivedDataDic valueForKey:@”id”]; NSString * name = [receivedDataDic valueForKey:@”name”]; use those variables where you want make these changes in your code @interface ViewController () … Read more
Integer.parseInt couldn’t do the job, unless you were happy to lose data. Think about what you’re asking for here. Try Long.parseLong(String) or new BigInteger(String) for really big integers. solved In Java, how do I parse a string bigger than int size
Since the purpose of the question has become more clear now, an edit: var a = [“1”, ‘car’, 2]; a = a.map(function(element) { //check if element is a number and not NaN or empty string if (!isNaN(element) && element != “”) { return parseInt(element, 10); } else { return element; } }); document.body.textContent = a; … Read more
System.FormatException: The string ‘3/1/2013’ is not a valid AllXsd value. According to the XML Schema Specification, date time values should be in ISO8601 Format, For Eg : 2013-01-03T22:16:00 solved What is mistake in below code in iphone [closed]
The user asked for something simple, so I gave him something simple. $input = “[link=http://www.google.com]test[/link]”; $replacement = preg_replace(‘/\[link=(.*?)\](.*?)\[\/link\]/’, ‘<a href=”https://stackoverflow.com/questions/10458103/”>$2</a>’, $input); Where /\[link=(.*?)\](.*?)\[\/link\]/ is the regex, <a href=”https://stackoverflow.com/questions/10458103/”>$2</a> is the format, $input is the input/data, and $replacement is the return. 1 solved How to make PHP BB Codes with RegExp?