[Solved] How can I access each value from an array?
Try using foreach loop. foreach($resultData2 as $resultData) { echo $resultData[’email’]; } solved How can I access each value from an array?
Try using foreach loop. foreach($resultData2 as $resultData) { echo $resultData[’email’]; } solved How can I access each value from an array?
After reviewing your updated question, what I think you really want is a function that will accept a template and an object of values to replace with. Here’s a working example. function PropertyAccess(template, values) { for (key in values) { template = template.replace(‘${‘ + key + ‘}’, values[key]) } return template; } console.log(PropertyAccess(‘hello ${val}’, {val: … Read more
You should have at least one attribute in your Grades class. You cant cast Grade to Integer. Calculate grades in your main/test or other class via get method. solved Cast a special java object to an integer [closed]
Here’s some code that works with recursion. It first finds all the options for the first query, and then recursively calls itself with the array of the objects with the same value for the given query, and at the deepest point, if there is no more queries, it returns the array of objects that meet … Read more
Create a class student with variables for each of the fields: public class Student { public String strFirstName; public String strLastName; public String strMajor; public int intGPA; public int intUIN; public String strNetID; public String strAge; public String strGender; public static void Student(String strFirstName, String strLastName, String strMajor, int intGPA, int intUIN, String strNetID, String … Read more
Like you said, class is a blueprint; objects are made using those blueprints. Its like you have a blueprint of a car – you have one blueprint, but many cars based on that blueprint. solved Java, why are objects known as instances of a class?
When I enter a variable that is storing an object, it keeps returning the instance of that object rather than the list that I want it to solved When I enter a variable that is storing an object, it keeps returning the instance of that object rather than the list that I want it to
my solution. I like just using the ES6(es2015+) way. const test_array = [ { “name”: “AnyManagedFundsRow”, “columnMeta”: { “a0”: “STRING”, “a1”: “STRING”, “a2”: “STRING”, “a3”: “DATE”, “a4”: “DATE”, “a5”: “DOUBLE”, “a6”: “INT” }, “rows”: [ [ “华夏基金管理有限公司”, “华夏大中华企业精选灵活配置混合(QDII)”, “其他型基金”, “2016-01-20”, “”, 21.877086009428236, 65135 ], [ “华夏基金管理有限公司”, “华夏大盘精选混合”, “混合型基金”, “2015-09-01”, “2017-05-02”, 10.307680340705128, 2944 ] ] } … Read more
Shoe roshe = new Nike(“roshe”, 11, “black”, “fashion”, 129.0, false) String literals should be enclosed in double quotes. As for your change in size type, pass int array instead of int int s[] = {11,12,13}; Shoe roshe = new Nike(“roshe”, s, “black”, “fashion”, 129.0, false) or Shoe roshe = new Nike(“roshe”,new int[]{11, 12, 13} , … Read more
This can be done for instance with two imbricated .forEach(): var obj = { “name”: { 0: ‘name0’, 1: ‘name1’, 2: ‘name2’ }, “xcoord”: { 0: ‘xcoord0’, 1: ‘xcoord1’, 2: ‘xcoord2’ }, “ycoord”: { 0: ‘ycoord0’, 1: ‘ycoord1’, 2: ‘ycoord2’ } }; var res = []; Object.keys(obj).forEach(k => { Object.keys(obj[k]).forEach(v => { (res[v] = (res[v] … Read more
Assuming that your Person has member functions like getFirst() you would use the dereference operator (-> or *) like this: Person1->getFirst(); // equivalent to (*Person1).getFirst() solved How do I use get and set methods in c++ with an object that is initialised with new [closed]
In ECMAScript 6 Map type is an ordered list of key-value pairs, where both the key and the value can have any type. A Map object iterates its elements in insertion order. The forEach method executes a provided function once per each key/value pair in the Map object, in insertion order. var a = new … Read more
I agree that it’s tricky. What teases in methodThree is that t is changed in the course of the call to methodTwo. So when you are looking at t.sum before and after that call, you are not looking at the same t. How is t changed? This happens when methodTwo calls methodOne, which in turn … Read more
In rare cases the thing that you want could be reasonably, but normally the class is not aware of all it’s elements. A total Score is for a Collection of Score elements, maybe a List or a Set. So you would do: class Score { int value; // … public static int totalScore(Collection<Score> scores){ int … Read more
let dt = { “cars” : [ { “id”: 0, “color”: “blue” }, { “id”: 3, “color”: “-” }, { “id”: 0, “color”: { “id”: 0, “color”: “yellow” } } ] }; dt.cars = dt.cars.map(it=> { it.color = typeof it.color == “string” ? it.color : it.color.color; return it; } ) console.log(dt); solved How to transform … Read more