In case to signal “failed to create object” C++ class constructs throws exceptions for this purpose. Some languages / projects prefer to use exceptions more to keep happy-pass happier while others may not. solved good practises null object return [closed]
[ { ‘one’: ‘8b45544b-6d35c53c3d423’ }, { ‘two’: ‘5a509481-a43k4d40r4c44’ } ].map(o => Object.keys(o)[0]) 1 solved turn array with object to array [closed]
JavaScript : How can I sort values in a dictionary to output matched values and ouput the values that don’t match showing an empty result solved JavaScript : How can I sort values in a dictionary to output matched values and ouput the values that don’t match showing an empty result
Did you defined leg, lat and lgn ? Are you using this script in environment with EcmaScript6 (ES2015) or newer version of JavaScript ? If not, this script doesn’t work. EcmaScript6 and newer : var leg = “leg”, lat = “lat”, lgn = “lgn” var waypoints_legs = [{leg,latlgn:{lat,lgn}}] EcmaScript5 and older : ‘use strict’; var … Read more
issues solved with the answer of @drewish Source: ReflectionClass Code: function accessProtected($obj, $prop) { $reflection = new ReflectionClass($obj); $property = $reflection->getProperty($prop); $property->setAccessible(true); return $property->getValue($obj); } solved Get php array from object
Here’s a plunker(just JS) :http://plnkr.co/edit/h3EndN8F6milHF2h1gAj?p=preview var array = [ { 9 : “Alfreds Futterkiste”, 10 : “Berlin”, Room : “201” }, { 9 : “Vaffeljernet”, 10: “Århus”, Room : “204” } ]; var result = {}; array.forEach(function(obj) { //function runs once for each element in the array, obj = element at current index result[obj.Room] = … Read more
your generateNewGreedySolution method returns an array of Object Type In the 5th line you are doing Object[] values = new Object[ins.getDimension()]; So here values is an object array and hence you are returing the same. If you are confused of what to return in methods then please note that if your method signaure is int … Read more
Here is an object version. This is not really what you’re after, but along the same lines and honestly, a bit neater as it’s a data structure. var myArray = [ “Apple: 10”, “Apple: 3”, “Banana: 3”, “Pear: 7”, “Pineapple: 7” ]; var newArray = {}; myArray.forEach(function(val) { var item = val.split(“:”); var key = … Read more
Yes, you are correct. By calling new you are creating a reference to an object, you are doing a similar operation when you declare a new String. 5 solved What is the error in each Java Statement?
Change public Circle(radius,x, y){ this(5, 3, 6); } To public Circle(int radius,int x, int y){ //need to add types to parameters this.radius=radius; this.x=x; this.y=y; } Or if you plan to use 5,3,6 as constant values add public Circle(){ this.radius=5; this.x=3; this.y=6; } 1 solved I’m not understanding what the error comment is trying to tell … Read more
You need to use reflection. Here’s a sample: static void Main(string[] args) { string obj1 = “a string”; int obj2 = 12; DateTime obj3 = DateTime.Today; object[] obj_array = { obj1, obj2, obj3 }; foreach (object obj in obj_array) { //Print value Console.WriteLine(“Value: ” + obj.ToString()); //Print property names Console.WriteLine(“Property Names:”); foreach (PropertyInfo prop in … Read more
So it looks like you have this: struct Obj { int x_; }; template <typename T> struct Struct { std::vector<T> items_; }; So to access an element (assuming you added it to the vector): int main() { Struct s; s.items_.resize(10); s.items_[0].x_ = 5; // Access the object memeber of element 0 in the vector. } … Read more
If that is the exact solution that you want. Following code snippet may help you. const arr = [ { type: ‘type’, fields: [‘field1’]}, { type: ‘type2’}, { type: ‘type’, fields: [‘field2’]} ] const modifyArr = (data) => { let res = []; arr.map((item) => { if(item.type == data.type){ if(Object.keys(item).includes(‘fields’)){ res = res.concat(item.fields); } } … Read more
At first your code: var obj = {[“Value1”]: “Value2”}; is wrong. You have to write: var obj = {“Value1”: “Value2”}; or var obj = {Value1: “Value2”};. And then if I understood you correctly: in your comment you wrote: I wana get Value1 in double quotes too dynamic means I want dynamic index too in double … Read more
Simply add a getter method int get_x() to Class1 #include <iostream> #include <conio.h> using namespace std; class Class1{ private: int x; public: Class1(); void Display(); int get_x(); }; int Class1::get_x() { return x; } class Class2{ private: double z; public: Class2(); void Display(); Class2 Add(Class1); }; Class1::Class1(){ x = 1; } Class2::Class2(){ z = 5; … Read more