At issue here is your use of the zip() function. It produces a list of tuples up front. You created a copy of the original list with numbers added. From the documentation: This function returns a list of tuples, where the i-th tuple contains the i-th element from each of the argument sequences or iterables. … Read more
Performing tests i discover that the for loop is the better option for this situation: for(var i = 0; i < 1000000; ++i){ // Each iteration of the loop will make i // have a different value inside the loop } And for measure the time i’m using console.time() and console.timeEnd() solved Which is the … Read more
var arr = [{“code”:1000,”day”:”Sunny”,”night”:”Clear”,”icon”:113,”languages”: [{“lang_name”:”Arabic”,”lang_iso”:”ar”,”day_text”:”مشمس”,”night_text”:”صافي”}] }] arr.forEach(function(obj){ //loop array obj.languages.forEach(function(language) { //loop languages console.log(language); //language object console.log(language.lang_name); //language property }); }); 1 solved How to parse or loop this [closed]
I assume a typo here, where e should be i… var isLastElement = e == diff.length -1; But anyway, don’t use the loop index. You will save yourself a lot trouble if you use a variable declared outside of the loop… And increment the value of this variable in the ajax callbacks. var callCount = … Read more
The answers that others have put forwards helped me to create a program that every time the .py file is called it counts the number of files in the sub-directory and adds it to a file name and creates the file The Code I Used: path, dirs, files = next(os.walk(“C:/xampp/htdocs/addfiles/text/”)) file_count = len(files) save_path=”C:/xampp/htdocs/addfiles/text/” name_of_file=”text” … Read more
reproducible data which YOU should provide: df <- mtcars df[c(1,5,8),1] <-NA code: IND <- is.na(df[,1]) df[IND,1] <- df[dplyr::lag(IND,1L, F),1] * 3 since you use lag I use lag. You are saying “previous”. So maybe you want to use lead. What happens if the first value in lead case or last value in lag case is … Read more
It has to do with how the program source code is interpreted. range(a) will be executed before the body of the loop, producing an iterable object which yields 3, 4, 5. a will be modified later but it will not affect range(a) cause it has already been executed. The following will do what you want, … Read more
you got the whole list of objects in comments so give try following: foreach( $yourObj->stream->comments as $comment){ echo sprintf(‘%s: %s’, $comment->from->name, $comment->message); } 1 solved How to access object data and display the comments
You don’t change the value of a (which is true by default) to false, you just call a method that will return false but nothing is set to this returned value. Change your code to this: package files; public class EndLoopWithBooleanMethod { static boolean a = true; public static void main(String[] args){ while(a) { //This … Read more
The values of your variables throughout the loops are like follows: x y result ———- 0 0 1 0 1 2 0 2 3 1 0 4 1 1 5 1 2 6 2 0 7 2 1 8 2 2 9 3 0 10 3 1 11 3 2 12 So that’s why result … Read more
The problem is that you return the inputed string at the end of the loop no matter the validation done. You can use a boolean to check this validity. Also you don’t need to parse all the string and you can break the inner loop on the first invalid char. I renamed the string as … Read more
You can create a separate method: for task in self.tasks: task = randomTask() … def randomTask(): while True: num1 = random.randint(0, 10) num2 = random.randint(0, 10) if num1 + num2 <= 10: break return “{} + {} =”.format(num1, num2) solved I can’t make this in to a for loop
Well the loop seems to be this one (at the end of the code): for i,j in itertools.combinations([a,b,c],2): all_diffs=alldiffs(i,j) total=count_total(i,j) zero=count_zero(all_diffs) total=np.array(total) union=map(sub,total,zero) zero=np.array(zero).tolist() union=np.array(union).tolist() union=[list(x) for x in union] sim=[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \ for (aa, bb) in itertools.izip(zero, union)] sim_comb=sum(sim,[]) sum_of_sim=sum(sim_comb) number_sum=len(sim_comb) ave=sum_of_sim/number_sum one_ave=1-ave print one_ave One possible … Read more
The following block should generate the series as you described it. int numberOfLines = 4; int numberOfDigitsPerLine = 5; for (int i=1; i<numberOfLines+1; i++){ for(int j=1; j<=numberOfDigitsPerLine; j++) { if(j>=i) { System.out.print(j); } else { System.out.print(i); } } System.out.println(); } Change numberOfLines and numberOfDigitsPerLine as necessary. Elaboration: First you must analyze the series, by the … Read more
When you do cin >> divers; the end-of-line character is not removed from the input, just the number leading up to it. Then, the next time you ask for a line with std::getline() it returns just the end-of-line character that is already there and does not wait for your new input. So when you do … Read more