I’m guessing you want something like this. List<ZipCode> myZips = // create all ZipCode’s somehow public ZipCode findZip(int zip){ //look at all zips for(ZipCode zipCode : myZips){ //if we find one that matches the one we want, return it if(zipCode.getZipCode() == zip){ return zipCode; } } // we checked all our zip’s and couldn’t find … Read more
These two loops are not the same: The first loop will never stop The second loop will run for a long time, until i overflows, at which point the loop will exit. Given that these two loops are not the same, the byte code, CPU usage, and speed for each would be different as well. … Read more
#include<stdio.h> int f,b; int x=0; int m=502; int n=3; int r=1; int main() { printf(“in main\n”); int loop=0; while(1) { printf(“in while %d %d %d\n”,m,n,r); printf(“if(m>n) %d\n\n”,m>n); if(m>n) { f=m/n; b=f*n; r=m-b; printf(“m>n 1\n”); } printf(“if(m<n) %d\n\n”,m<n); if(m<n) { f=n/m; b=f*m; r=n-b; printf(“m<n 2\n”); } printf(“if(r==0) %d\n\n”,r); if(r==0) { printf(“m=%i n=%i b=%i f=%i\n”,m,n,b,f); return(1); } … Read more
Let’s say that you pass the string XII to your function. That makes len(s) 3, which means that the body of your loop would (if the panic didn’t occur) execute 4 times (when i is 0, 1, 2 and 3 since your condition is i <= len(s). On the iteration where i is 2 (i.e. … Read more
If you only want to increment unless some condition is met, you should mention that in your code. Using the postfix foo() unless condition(); syntax means the condition will only refer to the previous statement, not the entire scope ( which would arguably be insane to parse ). So print ‘…’ unless $foo is the … Read more
If you really want to do this, it’s pretty trivial with lapply(), where we use it to “loop” over the other columns of df. A custom function takes each variable in turn as x and fits a model for that covariate. df <- data.frame(crim = rnorm(20), rm = rnorm(20), ad = rnorm(20), wd = rnorm(20)) … Read more
Note the line below with the comment about eating the input buffer. Since your scanf didn’t find what it is looking for in the input buffer, the wrong input just stays there and fails forever unless you do something to “eat” it. #include <stdio.h> #include <stdlib.h> int main(void) { printf(“Hello world!\n”); while (‘A’) { int … Read more
Start with this: var timer = setInterval(function () { doTask() }, 60000); function doTask() { while (condition) { } } 0 solved Javascript looping until condition met [closed]
you can’t “double compare” like that. try this for type int: (t != 0) && (arrivalTime[i] <= t) ..but you probably rather want t > 0 7 solved ERROR: The operator != is undefined for the argument type(s) boolean, int
Introduction This error occurs when the operator != (not equal to) is used with incompatible data types. The operator != is only valid for comparing two values of the same data type. In this case, the operator != is being used to compare a boolean value with an integer value, which is not allowed. To … Read more
Rather than trying to extend the syntax of the shell to do start: for …; do for …; do … done done if CONDITION; then goto start else SOMETHING fi you may do while true; do for …; do for …; do … done done if ! CONDITION; then SOMETHING break fi done or while … Read more
Because when a reaches 10 in the inner loop, the outer loop also exits, so you only see 012345678910 Because after the 1st time the outer loop is executed, b is already 11 and the inner loop is no longer executed. For your desired output, you should reset b to zero every time the outer … Read more
The problem occurs on the price Method not the number, if the user enters 50 , you are checking the matrix seatsArray[][] for available seats : Solution: you need to add a boolean when seat gets reserved so you can set it true and escape the loop which is on the for not the the … Read more
You can retrieve the fields of each line using str_getcsv(). http://www.php.net/manual/en/function.str-getcsv.php Or just explode a second time: foreach( explode( “\n”, $text ) as $line ) { $fields = explode( ‘,’, $line ); var_dump( $fields ); } solved converting phone numbers to vcf format algorithm [closed]
Neither iteration of the loop will be executed. In fact this loop (provided that the condition has no side effects) for(i = 2; i < 2; i++) { /* … */ } is equivalent to this statement i = 2; solved In C, what happens when the condition for a for loop aren’t met at … Read more