[ad_1] You can use the dict constructor d = dict(key1=val1, key2=val2) or __setitem__ method d = {} d[‘key1’] = val1 d[‘key2’] = val2 There are other, even more flexible ways, but those are the basics. [ad_2] solved Generate Dictionary in Python at run time [closed]
[ad_1] You could use a simple list comprehension here : S = [x[0] for x in content_E.most_common(3)] or, if you need to generate from E, then: S = [x[0] for x in E] 0 [ad_2] solved get most common keys from list
[ad_1] Because in general l[n] returns a sublist (possibly of length one), whereas l[[n]] returns an element: > lfile[2] [[1]] [1] “file2.xls” # returns SUBLIST of length one, not n’th ELEMENT > lfile[[2]] [1] “file2.xls” # returns ELEMENT From R intro manual: 6.1 Lists: It is very important to distinguish Lst[[1]] from Lst[1]. ‘[[…]]’ is … Read more
[ad_1] Assuming that sorted_indices contains only integers: tmaxima = [t[i] for i in sorted_indices] ag_maxima = [a_g[i] for i in sorted_indices] [ad_2] solved how to turn this python lines code into a list comprehension?
[ad_1] do list(range(4)). The range() function returns a generator (only produces one value at a time). You have to convert that generator to a list. 1 [ad_2] solved How to get a list using the range function? [closed]
[ad_1] from itertools import chain l = [[‘password’, ‘_rev’, ‘_id’, ‘username’], [‘password’, ‘_rev’, ‘_id’, ‘username’, ‘name’], [‘password’, ‘_rev’, ‘_id’, ‘username’],[‘password’, ‘_rev’, ‘_id’, ‘username’,’country’]] list(set(chain(*l))) Output – [‘username’, ‘_rev’, ‘_id’, ‘name’, ‘password’, ‘country’] [ad_2] solved merge list of nested list to a single list which has lakhs of data python [duplicate]
[ad_1] If you have constant pool of Excersises, and you only need to access them by index, then you can use array instead: Excersise[] excersises = new Excersise[EXCERSIZE_SIZE]; //fill excersises //use excersises workout.add(excersises[index]); ArrayList is designed to have fast access to element by index, and it is using array underneath, but it has range check … Read more
[ad_1] import random lst = [‘a’,’b’,’c’] print(random.choice(lst)) (Use the random module to get random values instead of going through the long process of creating a randomizer) [ad_2] solved How to chose a random word from a list with a condition in python [closed]
[ad_1] I suppose the aim of the assignment is to teach you about list comprehensions, filter and similar constructs, and not to have you write functions that test for primality or create the list of divisors in any sensible way. Therefore what you need is a predicate divides, divides :: Int -> Int -> Bool … Read more
[ad_1] If you want to have separate method in the Author class like you asked in the question, it could look like: public class Author { public Author() { } public int _AuthorID { get; set; } public string _AuthorName { get; set; } public List<Paper> _Papers { get; set; } public bool HasPapersForYear(int year) … Read more
[ad_1] Here you go: add_to_elements = [1, 2] for i in range(len(list_)): if i in add_to_elements: list_[i] += 50 [ad_2] solved How to add an integer to certain elements in a list? [closed]
[ad_1] Now that you’ve fixed the original problem, and fixed the next problem with doing the check backward, and renamed all of your variables, you have this: for match in dictionary: if any(match in value for value in sentences): print match And your problem with it is: The way I have the code written i … Read more
[ad_1] The problem is obvious now you’ve said on which line the code crashes. Consider these lines… char *word = NULL; int i = 0; //index FILE *dictionaryTextFile; dictionaryTextFile = fopen(dictionary, “r”); //scan for word while(fscanf(dictionaryTextFile, “%s”, word) != EOF) You’ve got 2 problems there. Firstly, you don’t check that the call to fopen worked. … Read more
[ad_1] Your question really leaves a fair amount up in the air as to what is really required but as I understand it through reading the comments… You have 4 Items within your List (A, B, C, and D). You want to create a List pertaining to each particular Item. If there are 10 data … Read more
[ad_1] How about using some flags to track where you are in the checking process and some variables to hold historical info? This is not super elegant code but it is fairly simple to understand I think and fairly robust for the use case you gave. My code cross = [7,5,8,0,0,0,0,2,5,8,0,0,0,0,8,7,9,3,0,0,0,3,2,1,4,5,0,0,0,7,5] foundstart = False foundend … Read more