[Solved] Using JSON Decodable in Swift 4.1

Your previous question is quite close but you have to add the struct for the root object Declare the struct members non-optional as much as possible. The URLs can be decoded as URL struct Root : Decodable { let count : Int let recipes : [Recipe] } struct Recipe : Decodable { // It’s highly … Read more

[Solved] Cannot implicitly convert type ‘Systems.Collections.Generic.List C# JSON [duplicate]

Your JSON string is for an array of Songs’s. So you should try to deserialize to that var songs = Newtonsoft.Json.JsonConvert.DeserializeObject<List<Songs>>(reponse); Assuming reponse is a string which has the JSON string you have in your question 10 solved Cannot implicitly convert type ‘Systems.Collections.Generic.List C# JSON [duplicate]

[Solved] How Can i Change the style of my angularjs object?

Here’s a plunker(just JS) :http://plnkr.co/edit/h3EndN8F6milHF2h1gAj?p=preview var array = [ { 9 : “Alfreds Futterkiste”, 10 : “Berlin”, Room : “201” }, { 9 : “Vaffeljernet”, 10: “Ã…rhus”, Room : “204” } ]; var result = {}; array.forEach(function(obj) { //function runs once for each element in the array, obj = element at current index result[obj.Room] = … Read more

[Solved] org.json.JSONException: Value Exception of type java.lang.String cannot be converted to JSONArray

Assuming your PHP script is producing correct JSON. Try changing this part JSONArray jArray = new JSONArray(result); to this. JSONObject jObject = new JSONObject(result); JSONArray jArray = jObject.getJSONArray(“NomTableau”); 2 solved org.json.JSONException: Value Exception of type java.lang.String cannot be converted to JSONArray

[Solved] JSON parsing in android using inbuilt json library? [closed]

Try this way,hope this will help you to solve your problem. try{ String jsonRespone=”{\”From\”:\”13-06-2014\”,\”To\”:\”19-06-2014\”,\”Employee\”:[{\”EmpId\”:\”1\”,\”EmpCode\”:\”101\”,\”EmpName\”:\”abc\”,\”EmpLName\”:\”def\”,\”Job\”:[{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”}]},{\”EmpId\”:\”1\”,\”EmpCode\”:\”101\”,\”EmpName\”:\”abc\”,\”EmpLName\”:\”def\”,\”Job\”:[{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”},{\”ID\”:\”1\”,\”JobName\”:\”abc\”,\”Time\”:\”12:00\”}]}]}”; JSONObject responeJson = new JSONObject(jsonRespone); String From = responeJson.getString(“From”); String To = responeJson.getString(“To”); ArrayList<HashMap<String,Object>> data = new ArrayList<HashMap<String, Object>>(); JSONArray employeeJsonArray = responeJson.getJSONArray(“Employee”); for (int i=0;i<employeeJsonArray.length();i++){ HashMap<String,Object> row = new HashMap<String, Object>(); row.put(“EmpId”,employeeJsonArray.getJSONObject(i).getString(“EmpId”)); row.put(“EmpCode”,employeeJsonArray.getJSONObject(i).getString(“EmpCode”)); row.put(“EmpName”,employeeJsonArray.getJSONObject(i).getString(“EmpName”)); row.put(“EmpLName”,employeeJsonArray.getJSONObject(i).getString(“EmpLName”)); JSONArray jobJsonArray = employeeJsonArray.getJSONObject(i).getJSONArray(“Job”); ArrayList<HashMap<String,String>> … Read more

[Solved] Adding data dynamically from one json object to another

You’re pretty much going to need a server-side process if you want to save your changes. You can load the JSON via ajax: $.ajax({ url: “/path/to/friends.json”, dataType: “json”, success: function(data) { // Here, `data` will be the object resulting from deserializing the JSON // Store `data` somewhere useful, perhaps you might have a `friends` // … Read more

[Solved] Asking the user for a URL to receive a JSON

Create a constructor in your async Task private class JSONTask extends AsyncTask<String, String, String> { String url; public JSONTask(String url){ this.url=url; } use the url string in place of params[0] And wherever you call your async task do it like this new JSONTask(textView.getText()).execute() This should solve it. Else you can directly use the do in … Read more

[Solved] Serializing in Json.net [closed]

There is no question here but I am assuming you want to serialize that json string into an object? Also I would at least post what you have tried and what errors you are receiving if any. This is per the JSON.net web site found here http://james.newtonking.com/pages/json-net.aspx string json = “<you json string>”; JObject o … Read more

[Solved] Get new JSON array from difference of to JSON array [closed]

Many ways to do this, here’s a functional one explicitly comparing the ‘id’ keys: $ids = array_map(function ($i) { return $i[‘id’]; }, $array2); $outarray = array_filter($array1, function ($i) use ($ids) { return !in_array($i[‘id’], $ids); }); More beginner friendly implementation, doing the same thing: $ids = array(); foreach ($array2 as $value) { $ids[] = $value[‘id’]; } … Read more

[Solved] How to write REST web service in cakephp using Post ..? [closed]

you can sent json through Http post in cakephp <?php $data = array(‘Users’=>array(‘id’=>’1′,’username’=>’xyz’,’password’=>’pass’,’email’=>’[email protected]’,’age’=>’28’,’gender’=>’male’)); $url = “http://localhost/appname/Controllername/functionname”; $content = json_encode($data); $curl = curl_init($url); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_POST, true); curl_setopt($curl, CURLOPT_POSTFIELDS, ‘data=”.$content); $json_response = curl_exec($curl); echo $json_response;?> 2 solved How to write REST web service in cakephp using Post ..? [closed]