As mentioned in the tutorial you shared: The reason we can use this shorter, simpler form_for declaration to stand in for either of the other forms is that @article is a resource corresponding to a full set of RESTful routes, and Rails is able to infer which URI and method to use. Also, from the reference given there: For an … Read more
Can I invent my own HTTP Status Code for when an entity is updated and the server returns a representation of the updated entity? solved Can I invent my own HTTP Status Code for when an entity is updated and the server returns a representation of the updated entity?
you can sent json through Http post in cakephp <?php $data = array(‘Users’=>array(‘id’=>’1′,’username’=>’xyz’,’password’=>’pass’,’email’=>’[email protected]’,’age’=>’28’,’gender’=>’male’)); $url = “http://localhost/appname/Controllername/functionname”; $content = json_encode($data); $curl = curl_init($url); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_POST, true); curl_setopt($curl, CURLOPT_POSTFIELDS, ‘data=”.$content); $json_response = curl_exec($curl); echo $json_response;?> 2 solved How to write REST web service in cakephp using Post ..? [closed]
It’s not possible to get variables from the URL as POST, you need to use GET. This is how they built it. POST variables are not accessible from the URL, its more secure, and are used for sending Usernames, Passwords. Refer this for more info. solved How to get variables using POST in PHP
Spring Rest support is based on MVC and its not actual implementation of JAX-RS.If your application is already on spring and you don’t have any constraint to use Jersey,Spring Rest will make sense. JAX-RS is just specification and you can replace jersey with apache cxf or RestEasy. refer : Spring MVC and JAX-RS compliant frameworks … Read more
How can i create the correct JSON data in an Android app required for a Java Jax RS REST POST Api accepting a List of JSON Objects solved How can i create the correct JSON data in an Android app required for a Java Jax RS REST POST Api accepting a List of JSON Objects
The quotes in your query param seem to be causing the error at the server. Try something like this apiURL := “http://localhost:8080/api/history/resources/count” req, err := http.NewRequest(“GET”, apiURL, nil) if err != nil { log.Fatal(err) } apiParams := req.URL.Query() apiParams.Add(“startedAfter”, “2021-03-06T15:27:13.894415787+0200”) req.URL.RawQuery = apiParams.Encode() res, err := http.DefaultClient.Do(req) try that and revert. solved Getting 400 after … Read more
I think it is better store it in a database’s table. If you store it in a enum, when you add, change or delete a fruit you have to compile your code again. In case of change, you will have to update all places (tables columns) where this fruit’s name is store. In the database … Read more
All frameworks are by definition slower than no-code as there’s more going on. i.e. <?php echo ‘metro’; is going to be much faster than a Slim application with this code: use \Slim\App; $config = include ‘Config/Container.php’; $app = new App($config); $app->get(‘/metro’, function($request, $response){ return $response->write(“metro”); }); $app->run(); This is because the Slim application is doing … Read more
The top level object in your JSON file is an array so: class letsRead { public static void main(String [] args) { String inline = “”; try { URL url = new URL(“https://gist.githubusercontent.com/anubhavshrimal/75f6183458db8c453306f93521e93d37/raw/f77e7598a8503f1f70528ae1cbf9f66755698a16/CountryCodes.json”); HttpURLConnection conn = (HttpURLConnection)url.openConnection(); conn.setRequestMethod(“GET”); conn.connect(); int responsecode = conn.getResponseCode(); System.out.println(“Response code is: ” +responsecode); if(responsecode != 200) throw new RuntimeException(“HttpResponseCode: ” … Read more