You can json_decode that json string and then use array_filter method to filter regions $regions = json_decode(‘{“regions”: [ { “id”: 1, “name”: “Region 1”, “state_id”: 1, “areas” :[ { “id”: 1, “name”: “area 1”, “region_id”: 1 },{ “id”: 2, “name”: “area 2”, “region_id”: 1 }] },{ “id”: 2, “name”: “Region 2”, “state_id”: 1, “areas” :[{ … Read more
You can put the array through Array.protoype.map, which replaces each value in the array with whatever the callback function returns. In the callback function you can return an array version of the object. For example: var result = yourArray.map(function (item) { return [item.text, item.count]; }); More array methods can be found on the MDN docs … Read more
The fundamental issue is that you’re creating multiple JSON strings (json_data = (json.dumps(response, indent=2))) and then adding them to an array (json_arr.append(json_data)), and then converting that array to JSON (json.dump(json_arr,outline)). So the result is a JSON array of strings (containing JSON). You don’t want to create a string before adding to the array, just include … Read more
LocalDate and ThreeTenABP String dateString = “2019-11-27”; LocalDate date = LocalDate.parse(dateString); int epochDay = (int) date.toEpochDay(); System.out.println(epochDay); This snippet outputs: 18227 The documentation explains: The Epoch Day count is a simple incrementing count of days where day 0 is 1970-01-01 (ISO). So my suggestion is that this number is fine for feeding into your BarEntry … Read more
Since this seemed to be the correct answer, and I’ve just set a bounty I could do with the rep of an accepted answer: either google, or RTM -> $parsed[0][‘data’][‘attr’][‘href’] 2 solved Parser Json PHP [closed]
You can use next with a generator comprehension. res = next(i[‘name’] for i in json_dict[‘ancestors’] if i[‘subcategory’][0][‘key’] == ‘province’) # ‘Lam Dong Province’ To construct the condition i[‘subcategory’][0][‘key’], you need only note: Lists are denoted by [] and the only element of a list may be retrieved via [0]. Dictionaries are denoted by {} and … Read more
One way is to use PropertyNamingStrategy http://wiki.fasterxml.com/PropertyNamingStrategy Here is nice simple demo how you can use it Link to How to Use PropertyNamingStrategy in Jackson The other is use MixInAnnotations http://wiki.fasterxml.com/JacksonMixInAnnotations with MixInAnnotations you can create just one Person class and Mixin for any other alternative property name setup. public static void main(String[] args) throws … Read more
Missing a final single quote here: data[‘playerInfo’][‘username’] + ‘</h2>’ + nomeserver + ‘</div>); Change to: data[‘playerInfo’][‘username’] + ‘</h2>’ + nomeserver + ‘</div>’); 29 solved Unterminated String Literal error with jQuery [closed]
json1_text = [v for i in json_data for k,v in i.items() if isinstance(v,str)] print (json1_text) Result: [‘Salam’, ‘Hello Friend’] 0 solved .get() returning letters rather than strings
ShopCollectionObject.h #import <Foundation/Foundation.h> @interface ShopCollectionObject : NSObject @property (nonatomic) int message_id; @property (strong, nonatomic) NSString *Name; @property (nonatomic) int TimeAsPrice; @property (strong, nonatomic) NSString *Avathar;//user,Name_User,LocationOfUser,message_id @property (strong, nonatomic) NSString *user; @property (strong, nonatomic) NSString *Name_User; @property (strong, nonatomic) NSString *LocationOfUser; -(instancetype) initWithID: (int)msgID Name:(NSString *)Profile_name TimeAsPrice:(int) GivenTimeAsPrice Avathar:(NSString *) PhotoOfAvathar user:(NSString *)UserAvathar Name_User: (NSString *) … Read more
if you use SOAP do sth like this : String namespace = “http://tempuri.org/” ; String soapAction = “http://tempuri.org/MyMethod”; String methodName = “MyMethod”; String url = “http://192.168.1.2:8686/WebService/MyWebService.asmx” ; // my local or valid ip for webservice location SoapObject request = new SoapObject(namespace, methodName); // your webservice argument String username = “your username”; PropertyInfo usernameProp = new … Read more
Try to use this JSONObject jsono = new JSONObject(data); jarray = jsono.getJSONArray(“posts”); for (int i = 0; i < jarray.length(); i++) { JSONObject object = jarray.getJSONObject(i); JSONObject bigImage = object.getJSONObject(“thumbnail_images”); JSONObject tiMed = bigImage.getJSONObject(“medium”); String imageURL = tiMed.getString(“url”); } } actor = new Actors(); actor.setName(object.getString(“title”)); actor.setDescription(object.getString(“url”)); actor.setImage(imageURL); actor.setDob(object.getString(“content”)); actorsList.add(actor); } 5 solved Android: Parse the … Read more
You should really look into How to parse JsonObject / JsonArray in android. Please put your code of also what you have tried because people are here to help solve error/problem not to do coding. Here is code from which you can Parse your json JSONObject jsonObject = new JSONObject(); JSONObject dataObject = jsonObject.getJSONObject(“data”); JSONArray … Read more
As your code seems really unclear, here’s a pointer on how you could implement it: You read the OData response into a JSONModel: var oModel2 = new sap.ui.odata.ODataModel(); var oODataJSONModelDLSet = new sap.ui.json.JSONModel(); this.getView().setModel(oODataJSONModelDLSet, “jsonmodel”); // etc oModel2.read(“/SEARCH_DLSet” + filterString, null, null, false, function (oData, oResponse) { oODataJSONModelDLSet.setData({ DLSet: oData }); }); …you then bind … Read more
I think you should develop more on your fundamentals, and try out your own code before asking a question here. I guess what you are trying to achieve can be done like this. import json with open(“example.json”, “r”) as f: json_content = json.load(f) message = json_content[“message”] variable = “var” print(message.format(variable=variable)) # prints # this is … Read more