The following is related to the JSON.simple library. You need a JSONParser instance to get a JSONObject value from your String object. JSONObject data; try { JSONParser helper = new JSONParser(); data = (JSONObject)helper.parse(String); } catch (ParseException parse) { // Invalid syntax return; } // Note that these may throw several exceptions JSONObject node = … Read more
Replace private static final String TAG_CARID = “car_id”; with private static final String TAG_CARID = “CarID”; You JSONArray has key “CarID”, whereas you are searching for “car_id”. Hope this helps 🙂 1 solved JSONException No value for..Android app
Here is your code, which sets the data you are receiving from backend, here I have stored it in a variable data. Please notice, this is a shortened version of your form, but the basics are there, you only need to add the few missing properties in corresponding form arrays. The build of the empty … Read more
Please, add your convert code here. The code below works fine. type BaseModel struct { Id string `json:”id”` CreatedTime time.Time `json:”createdTime”` UpdatedTime time.Time `json:”updatedTime”` Deleted bool `json:”deleted”` } type Category struct { BaseModel Parent string `json:”parent”` Name string `json:”name”` IconClass string `json:”iconClass”` Mark string `json:”mark”` } func main() { data, err := json.Marshal(Category{}) if err … Read more
What you need to do is use JSONSerialization to get your JSON object from data. Also in Swift 3 use URLRequest and URL instead of NSMutableURLRequest and NSURL. func requestPost () { var request = URLRequest(url: URL(string: “https://oakkohost.000webhostapp.com/test.php”)!) request.httpMethod = “POST” let postString = “numQue” request.httpBody = postString.data(using: .utf8) let task = URLSession.shared.dataTask(with: request) { … Read more
First your json is invalid. Here is the same one but with fixes. {“data”:[{“name”:”123″,”pwd”:123},{“name”:”456″,”pwd”:456},{“name”:”789″,”pwd”:789}],”duration”:5309,”query”:”myquery”,”timeout”:300} And with this json model should look like this: public class Rootobject { public Datum[] data { get; set; } public int duration { get; set; } public string query { get; set; } public int timeout { get; set; } … Read more
You need do it in following manner:- <?php $data=”{ “metrics”: { “timers”: [ { “name”: “com.android.timer.launchtime”, “startTime”: 1232138988989, “duration_ms”: 1900 }, { “name”: “com.android.timer.preroll-load-time”, “startTime”: 1232138988989, “duration_ms”: 1000 } ] } }”; $new_array = json_decode($data); //convert json data into array echo “<pre/>”;print_r($new_array); //print array foreach ($new_array->metrics->timers as $new_arr){ // iterate through array echo $new_arr->name.'<br/>’; // … Read more
Depends on what you want to do when there’s more than one value in change[‘Errors’]. Currently the value is a list of one element (u’DELETED’). If you want to print just the text, you need: print error[0] But maybe just in case it would be better to do: print u’, ‘.join(error) 2 solved Json output … Read more
I’ll be utilizing C# rather than Visual Basic, but you could essentially do this: Code Behind: JavaScriptSerializer serializer = new JavaScriptSerializer(); List<Address> deserialize = serializer.Deserialize<List<Address>>(address); foreach(Address address in deserialize) { // Do something with Exposed Properties: } The Address Class will be very, very basic: public class Address { public int Id { get; set; … Read more
Simple and straight. <?php ini_set(‘display_errors’, 1); $json = file_get_contents(“https://api.sunrise-sunset.org/json?lat=51.507351&lng=-0.127758&date=today”); $array=json_decode($json,true); echo $SunRiseTime=$array[“results”][“sunrise”]; echo $SunSetTime=$array[“results”][“sunset”]; Output: 4:21:35 AM 7:32:34 PM 3 solved decode json into php variables [duplicate]
This is the simplest way to parse your JSON String. I would suggest your to read JSON documents. But, here is a sample code. try { String jsonString = new String(“[{\”id\”: \”1\”,\”name\”: \”abc\”,\”type\”: \”consumer\”}]”); JSONArray jsonArray = new JSONArray(jsonString); for(int index = 0;index < jsonArray.length(); index++) { JSONObject jsonObject = jsonArray.getJSONObject(index); String id = jsonObject.getString(“id”); … Read more
Well @Fencer300, Simply make a simple bean class (Model class with getter setter methd ) // make a city bean class public class cityModel implements Serializable { private String fajr; // do for more same ass public String getFajr() { return fajr; } public void setFajr(String fajr) { this.fajr= fajr; } } protected void outputTimings(JSONArray … Read more
As your individual response come through, you can create a list of the values using extend (vs append). Then create your final dictionary. Here’s a mockup of one way to implement -collect all the response, then iterate over the list. Otherwise you can parse each response as they come in. response1 = { “@odata.context”: “https://example.com/services/api/x/odata/api/views/$metadata#vw_rpt_review_response_comment”, … Read more
<!DOCTYPE html> <html> <head> <title>kek</title> <link rel=”stylesheet” type=”text/css” href=”https://stackoverflow.com/questions/30492466/css/kek.css”> <script src=”http://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js”></script> <script src=”https://stackoverflow.com/questions/30492466/js/kek.js”></script> </head> <body> <table id=”personDataTable”> <tr> <th>Id</th> <th>First Name</th> <th>Last Name</th> </tr> </body> </html> 2 solved $.ajax $ is not defined with json
this is the correct sytnax of your JSON Object. [ { “id”: 1, “type”: “group” }, { “id”: 2, “type”: “text”, “label”: “Name”, “group_id”: 1 }, { “id”: 3, “type”: “text”, “label”: “Address”, “group_id”: 1 }, { “id”: 4, “type”: “text”, “label”: “City”, “value”: “Lahore”, “group_id”: 1 }, { “id”: 5, “type”: “text”, “label”: “State”, … Read more