json

[Solved] need help android Json Currency Converter

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i tried an activity that converts the data and displays it in a textview import java.io.BufferedReader; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import org.apache.http.HttpEntity; import org.apache.http.HttpResponse; import org.apache.http.client.ClientProtocolException; import org.apache.http.client.HttpClient; import org.apache.http.client.methods.HttpGet; import org.apache.http.impl.client.DefaultHttpClient; import org.json.JSONException; import org.json.JSONObject; import android.app.Activity; import android.app.ProgressDialog; import android.os.AsyncTask; import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.TextView; public class CurrencyActivity … Read more

[Solved] How to search for values inside Json file

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how about using ObjectMapper final String json = “{\”yourjson\”: \”here\”, \”andHere\”: … }”; final ObjectNode node = new ObjectMapper().readValue(json, ObjectNode.class); if (node.has(“ID”)) { System.out.println(“ID: ” + node.get(“ID”)); } This is one of the many ways: Adding for GSON, String json = “your json here” // you can also read from file etc Gson gson = … Read more

[Solved] org.json.JSONObject$1 cannot be converted to JSONObject error while parsing json string

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After reading JsonArray and JsonObject doc i understand how to sort out this problem. protected void parseJson() { JSONObject object=null; try { object=new JSONObject(json); myArray=object.getJSONArray(MY_ARRAY); Log.e(“Array Length”,””+myArray.length()); key_id=new String[myArray.length()]; key_name=new String[myArray.length()]; for (int i=0;i<=myArray.length();i++) { JSONObject fetchObject=myArray.optJSONObject(i); if(fetchObject==null) { //do nothing } else { key_id[i] = fetchObject.getString(KEY_ID); key_name[i] = fetchObject.getString(KEY_NAME); } } } catch (JSONException … Read more

[Solved] -[__NSArrayI length]: unrecognized selector sent to instance 0x7f1e9f90

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From the NSLog it seems like your array contains another array in it and that inside array has the elements that you want to show in your tableview. So change: cell.phoneLbl.text = [array6 objectAtIndex:indexPath.row]; to: cell.phoneLbl.text = array6[0][indexPath.row]; 4 solved -[__NSArrayI length]: unrecognized selector sent to instance 0x7f1e9f90

[Solved] How to consume a json object in PHP

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There are two steps to take: 1. load the JSON data 2. understand the JSON data 3. load the data in a database Your code appears to load the JOSN data using curl. In my experience, curl is powerful but complex for beginners. Probable file_get_contents() http://php.net/manual/en/function.file-get-contents.php works as well and is more easy. e.g. $json_data … Read more

[Solved] json.Unmarshal interface pointer with later type assertion

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An empty interface isn’t an actual type, it’s basically something that matches anything. As stated in the comments, a pointer to an empty interface doesn’t really make sense as a pointer already matches an empty interface since everything matches an empty interface. To make your code work, you should remove the interface wrapper around your … Read more

[Solved] Android JSON parse this, how?

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I have tried to parse that JSON string and I got one solution please try this also: String parse = “[{\”hotelid\”:[{\”hotelid\”:\”1\”,\”name\”:\”aaa\”,\”code\”:\”111\”,\”price\”:\”111\”},{\”hotelid\”:\”2\”,\”name\”:\”bbb\”,\”code\”:\”112\”,\”price\”:\”211\”},{\”hotelid\”:\”4\”,\”name\”:\”ccc\”,\”code\”:\”42\”,\”price\”:\”411\”}]}]”; try { JSONArray menuObject = new JSONArray(parse); for(int i=0;i<menuObject.length();i++){ String hotel = menuObject.getJSONObject(i).getString(“hotelid”).toString(); System.out.println(“hotel=”+hotel); JSONArray menuObject1 = new JSONArray(hotel); for(int j=0; j<menuObject1.length();j++){ String hotelid = menuObject1.getJSONObject(j).getString(“hotelid”).toString(); System.out.println(“hotelid==”+hotelid); String name = menuObject1.getJSONObject(j).getString(“name”).toString(); System.out.println(“name==”+name); String code … Read more

[Solved] i don’t understand what’s wrong with this JSON

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Assuming: You are pasting the “url” in the jsonformatter to validate the json. Your JSON is structurally valid. The errors shown are related to the missing metadata about content that your service should expose. Typically the client that would consume any resources you may expose over the network might/would like to know (among other things): … Read more

[Solved] Add onclick Event to a jQuery.each()

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You can parse the json to an object: var obj = JSON.parse(text); and then retrieve the values from the object: obj[“1”][0].RequestId if you want to display them all, you need to iterate through the array and print the values you want: for (var i = 0; i<output.length; i++) { $(“#YOURDIV”).append(“Request id: ” + obj[i][0].RequestId); $(“#YOURDIV”).append(“Customer … Read more

[Solved] json_encode with object oriented PHP [closed]

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You don’t need Object Oriented to do that : $array = array(“usa” => array( “label”=>”USA”, “data” => array( array(“1988″,”483994”), array(“1989″,”457645”) //etc ) ) ); echo json_encode($array); The same works back with the json string like this : $string = ‘{ “usa”: { label: “USA”, data: [[1988, 483994], [1989, 479060], [1990, 457648], [1991, 401949], [1992, 424705], … Read more

[Solved] How to convert string to array in react js?

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I’ve figured out that the JSON is already valid, I was just too confused and irritated by the errors with different usages of Object.keys etc.! I’ve solved the issue with: const arr = Object.entries(this.props.user); const mapped = []; arr.forEach(([key, value]) => mapped.push(value)); This way I am cutting out the {} entries inside the object and … Read more