Working fiddle : fiddle You should prevent the action to goto other page. //HTML <a href=”#” title=”Reply” class=”Classhref” onclick=”show_reply(‘<?php echo $row[‘id’]; ?>’)”> Reply</a> //Script $(‘.Classhref’).click(function(event){ event.preventDefault(); } 1 solved Make my script not to refresh the page [closed]
I have debugged with fiddle, thanks. I found a div that I was not closing. solved jQuery clone does not clone [closed]
$( function() { $(‘a’).on(‘click’, function() { $(‘#subs’).prop(‘title’, function() { return “I am a title”; }); }); }); use prop() instead if attr() is not working! Link to Fiddle 1 solved jQuery add attributes to div [closed]
The only logical reason for this is that jQuery(‘#main-content’) in your first line is not the actual jQuery object representation of the DOM element of your choice. You will have to figure that out yourself as to why things turn out this way. 1 solved jQuery css height not applying
Try this: $(“:checkbox”).on(“click”, function(){ if($(this).is(“:checked”)) { $(this).closest(“td”).siblings(“td”).each(function(){ $(“#seleted-rows”).append($(this).text()); }); } else { $(“#seleted-rows”).html(“”); $(“:checkbox:checked”).closest(“td”).siblings(“td”).each(function(){ $(“#seleted-rows”).append($(this).text()); }); } }) FIDDLE 1 solved Append checked checkboxes to a div
I’m sorry, I’m having trouble understanding your question. Do you just want to constantly rotate through the images you provide? Check out the fiddle below. http://jsfiddle.net/denniswaltermartinez/f8mVj/ function slider(id) { id = id || 0; var n_image = $(‘[class^=”img_”]’).length; if (n_image < id) id -= n_image; setTimeout(function () { $(‘img:not(.img_’+ id +’)’).fadeOut(‘slow’); $(‘.img_’ + id).fadeIn(‘slow’, function … Read more
So the issue here was that I was using the old fashion javascript onchange event with a JQuery script. Apparently the 2 don’t like to play together. As soon as I change it to use a JQuery $(‘#Branch’).on(‘change’, function() { in my document ready script it worked fine. solved JQuery script not working at all
This was the simplest I could get, its a circular gallery, it starts over when it reaches the end. Here is a fiddle: http://jsfiddle.net/KA4Zq/ var count = 1; setInterval(function() { count = ($(“.slideshow :nth-child(“+count+”)”).fadeOut().next().length == 0) ? 1 : count+1; $(“.slideshow :nth-child(“+count+”)”).fadeIn(); }, 2000); The only thing you should change is the 2000 value (2sec). … Read more
What you’re trying to achieve here is impossible without Javascript. You’ve changed the scrollTop but you need to do it after some milliseconds to get it working, e.g: $(“.nav a”).click(function(){ setTimeout(function() { $(window).scrollTop($(window).scrollTop() – 50); }, 10); }); If you don’t want to wait those milliseconds, you can also prevent the default behavior and simulate … Read more
jsFiddle Demo You could always implement a small observer to fix the case where a number input starts with . like this: $(‘body’).on(‘blur’,’input[data-val-number]’,function(){ if( this.value[0] == “.” ){ this.value = “0” + this.value; $(this).valid(); } }); 2 solved Why is .2 not a valid number for jquery.validate.js? [closed]
My god that is a lot of nested ifs. Have you considered using something called exceptions to generate your errors? I cannot check the return value of your PHP script. However, jQuery expects a json return (as you are setting the dataType to that) and will fail if it gets anything else…including an empty string. … Read more
Use filter and map, with a Set to remove the repeated values: var employee=[{“firstName”:”Zahir”,”lastName”:”Alam”,”Age”:25,”Company”:”Switchme”,”Role”:”Developer”,”Department”:”Tech”,”Head”:{“Id”:3,”Name”:”Sourasis Roy”}},{“firstName”:”Amith”,”lastName”:”Manniken”,”Age”:25,”Company”:”Switchme”,”Role”:”Developer”,”Department”:”Tech”,”Head”:{“Id”:3,”Name”:”Sourasis Roy”}},{“firstName”:”Sourasis”,”lastName”:”Roy”,”Age”:28,”Company”:”Switchme”,”Role”:”CTO”},{“firstName”:”Aditya”,”lastName”:”Mishra”,”Age”:29,”Company”:”Switchme”,”Department”:”Tech”,”Role”:”CEO”},{“firstName”:”Priti”,”lastName”:”Lata”,”Age”:24,”Company”:”Switchme”,”Role”:”HR”},{“firstName”:”Sumita”,”lastName”:”Nath”,”Age”:24,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”},{“firstName”:”Tarini”,”lastName”:”Khanna”,”Age”:22,”Company”:”Switchme”,”Role”:”Content Writer”},{“firstName”:”Abhisek”,”lastName”:”Soni”,”Age”:23,”Company”:”Switchme”,”Role”:”HLA”,”Department”:”Crm”,”Head”:{“Id”:5,”Name”:”Sumita Nath”}},{“firstName”:”Ankit”,”lastName”:”Pump”,”Age”:23,”Company”:”Switchme”,”Role”:”HLA”,”Department”:”Crm”,”Head”:{“Id”:5,”Name”:”Sumita Nath”}},{“firstName”:”Pogo”,”lastName”:”Laal”,”Age”:23,”Company”:”Switchme”,”Role”:”Designer”},{“firstName”:”Sabina”,”lastName”:”Sekh”,”Age”:28,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”},{“firstName”:”Sanjay”,”lastName”:”Poudal”,”Age”:24,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”,”Head”:{“Id”:10,”Name”:”Sabina Sekh”}}]; var repeated = […new Set(employee.map(({ Department }) => Department).filter(Boolean))]; $(“div.all”).text(repeated.join(“, “)); <script src=”https://code.jquery.com/jquery-3.3.1.js”></script> <h3>2. List out all department name </h3> <div class=”all”></div> 7 solved I want to print only the repeated values … Read more
Do this when you want to clear popupDiv and add span with class textbox2 $(“#popUpDiv”).empty().append(‘.textbox2’).show(“slow”); 1 solved I have a popup div with more than one span element how to display another span
I don’t know what do mean by “saving position of an element” and how can that be useful, but you can try jQuery position() and $.ajax() methods: Get the current coordinates of the first element in the set of matched elements, relative to the offset parent. var t = $(‘a.icon’).position().top; var l = $(‘a.icon’).position().left; $.ajax({ … Read more
This is what it seems you want What you want is a sticky menu which requires javascript to find the current position of the page in the viewport and change the CSS or class to make it fixed. This is a bad example because there is no div that is made visible after you scroll … Read more