Make a toString method and customize the way you want to build your string. An example of this can be the following public String toString() { String s = “”; `//building the string you want to return like so ‘s = //How you want it. ‘` return s; } 1 solved Instances: How to I … Read more
Actually no clue what exactly you wanted to achieve with your code, since several variables are undefinied (dateString and s for example). Also is the array m[] definied in a wrong way (double ” within the data part) – however, I “fixed” your code with the given information: String[] m = {“01”, “02”, “03”}; String[] … Read more
The main problem is these lines: int val = t.compare(arr[j – 1], arr[j]); System.out.println(val); if (val > 1) t.swap(arr[j – 1], arr[j]); Since your compare and swap methods actually take array indices, these should be: int val = t.compare(j – 1, j); System.out.println(val); if (val > 0) t.swap(j – 1, j); Otherwise, you are using … Read more
Please use this InterviewStatus findByInterviewId(Interviews interviewId); where interviewId is gotten by running Interviews findById(Long id). Due to the datatype conflict, it is ok that you pass in as parameter the expected datatype. so it is expecting Interviews not Integer, but you have integer. in this case, you get Interviews using the integer then pass the … Read more
#include <stdio.h> int main() { int myArray[] = {0,1,2,3}; int myArrayLength = sizeof(myArray)/sizeof(*myArray); int i, j; for(j=i=0;i<myArrayLength;++i){ printf(“(%d,%d)”, myArray[j], myArray[i]); if(i == myArrayLength -1){ i = j++;//++j – 1; printf(“\n”); } } return 0; } 5 solved Get all subarrays from an array using a single loop
Your problem is that you’re asking it to print the whole string repeatedly in this line: System.out.print(arr[j]+” “);. Changing that to print only an individual character will fix it: public class roughWork { public static void main(String[] args) { String str= “Test the product”; String arr[]=str.split(” “); for(int i=0;i<arr.length;i++) { for(int j=arr[i].length()-1;j>=0;j–) { System.out.print(arr[i].charAt(j)); } … Read more
Let father’s current age = f son’s current age = s let x years back, father was twice as old as son. then 2(s-x) = (f-x) => x = 2*s – f Note: if x comes negative, then after x years , father will be twice as old as son(test for input[25,5]) public static void … Read more
This is frankly as basic a question as it gets, and google could have helped you with this easily. Here’s your entire method if you want to design your own. public static int getCount(ArrayList A){ return A.size(); } solved How do I use on method to get the sizes of two different-sized arrayslists?
I’m not sure if I understand you correctly but in case you just want to get the first 255 characters of an existing string you can use: String message; //String that holds your message String previewMessage = “”; //String to store your pewview message if(message.length() >= 255) { previewMessage = message.substring(0, 254); } solved How … Read more
Can u try this ? I added to logical solution to code.I changed only starting game and ending game properties’s lines. public class ChoHan { public static void main(String[] args) { final int MAX_ROUNDS = 5; String player1Name; String player2Name; Scanner keyboard = new Scanner(System.in); char repeat; do { System.out.println(” Enter the first player name … Read more
Actually this works fine with Jackson. The NPE is thrown by my own constructor. solved Get NPE reading null object field when deserializing using Jackson [closed]
String str = “aaabbcc”; char c; ArrayList<String>count=new ArrayList(); for(int i = 0; i < str.length(); i++){ if(!count.contains(str.charAt(i)+””)){ count.add(str.charAt(i)+””); } } int [] dd = new int [count.size()]; for (int i = 0; i < str.length(); i++) { c=str.charAt(i); for(int j=0;j<count.size();j++){ if(count.get(j).equals(c+””)){ dd[j]++; } } } String newS=””; for(int i=0;i<count.size();i++){ newS+=count.get(i)+dd[i]; } str = newS; System.out.println(str); … Read more
No it will not execute the else statement if the if condition is satisfied 0 solved Will my program execute “else” even if it executed my “if”?
You’re returning List<Integer>, but you’re creating an int[]. They’re completely different things! try this instead: private static List<Integer> randomIntegerArray(int n) { List<Integer> list = new ArrayList<>(); for(int i = 0; i < n; i++) { list.add((int) Math.random()); // always returns 0 } return list; } Or if you definitely want to use an array, change … Read more
Use this : one_next_diaspora_bt.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { final String Name = name_diaspora_edt.getText().toString().trim(); if(Name.matches(“”)){ Toast.makeText(getApplicationContext(),”Make sure that you have filled your name please !!!”,Toast.LENGTH_LONG).show(); } else{ Intent i = new Intent(Diaspora.this,DiasporaTwo.class); i.putExtra(“Name”,Name); i.putExtra(“Age”,Age); i.putExtra(“Gender”,Gender); i.putExtra(“MaritalStatus”,MaritalStatus); startActivity(i); } } }); } solved IF Condition doesnt work