[ad_1] The reason it works this way is because C and C++ used << for left shift and >> for right shift long before Java. Those languages have both signed and unsigned types, and for signed types the sign bit was propagated in the right-shift case. Java does not have unsigned types, so they kept … Read more
[ad_1] First take the words of str in an array. Then check whether the words in the forward order and the reverse order are same. String[] words = str.split(” “); //splits at spaces boolean flag = true; int i, last = words.length – 1; for(i = 0; i <= last/2; i++){ if(!words[i].equalsIgnoreCase(words[last – i])){ flag … Read more
[ad_1] If you want a function that will return the same garbage for the same input string, this would work fine. public String rubbish(String input) { String result = “”; long seed = 0; long size = 0; for(int i = 0; i < input.length(); i ++) { seed += input.charAt(i); } seed %= Long.MAX_VALUE; … Read more
[ad_1] You can just combine all four conditions into one using logical operators. For example by using logical and && and logical or ||. It could then look like: if ((first && second) || (third && fourth)) { return true; } Or with all conditions substituted: if ((Obj.getSource().equals(“abc”) && Obj.getDest().equals(“bcd”)) || (Obj.getSource().equals(“abd”) && Obj.getDest().equals(“gdc”))) { … Read more
[ad_1] Since you only want the average of the HourlyEmp’s, you need to keep track of how many there are: double avg=0; int numHourlies = 0; //number of hourlyEmps you have found so far for(int i=0; i < Emp.length; i++) { if (Emp[i] instanceof HourlyEmp) { //just add up all the values for now … … Read more
[ad_1] You should not use == when comparing objects including strings. Generally == compares references, so it return true only of same objects. You should use equals() method instead: str1.equals(str2) It occasionally works for you in first case because java caches string constants, so “java” in both cases is represented by same instance of String. … Read more
[ad_1] The service locator pattern can be used for looking up services as described in Core J2EE Patterns. Please notice that this pattern can be considered a bit “outdated” and arguably dependency injection should be preferred in most cases (see here for a more elaborate discussion). [ad_2] solved j2ee pattern for centralizing the process of … Read more
[ad_1] It’s unclear what the problem is but your for loop doesnt over the letters in word as the termination condition is based on the empty List size passed to the buildAL method. Replace for (int i = 0; i < arr2.size(); i++) with for (int i = 0; i < word.length(); i++) { [ad_2] … Read more
[ad_1] A solution: Scanner input = new Scanner(System.in); int l; // it should be int if read int l = input.nextInt(); if (l <= 30) { System.out.println(“40 Sinas”); } if (l > 30 && l < 50) { System.out.println(“55 Sinas”); } if (l > 50 && l < 100) { System.out.println(“70 Sinas”); } if (l … Read more
[ad_1] Based on the example you provided, it seems to me that you want to repeatedly add the same elements (plural) into your array a particular N number of times. Because arrays are fixed in size, you can’t declare int[] a1 = {1,2,3};and then attempt to add more elements to it. That is why I … Read more
[ad_1] Immutable means, that class does not contain any method that would change it’s internal state. Example of immutable class: class ImmutableInteger { private final int value; public ImmutableInteger(int value) {this.value = value;} public int value() {return value;} public ImmutableInteger add(int a) { // instead of changing this state, we will create new instance with … Read more
[ad_1] You need to convert the int to String using pointsAvailable.setText(“C”+String.valueOf(pointsAmount)); And to save the points, you need to store them in the SharedPreferences in onRewarded: saveCoins.edit().putInt(“C”,pointsAmount).commit() [ad_2] solved How to save and update points in a share preferences
[ad_1] It is as simple as: “The Shawshank’s Redemption”.replaceAll(“\\S”, ” _”); We replace all non white-space characters \S with an underscore followed by a space. This would automatically make what is a space originally, 2 spaces. Note that a trailing space will be produced. 2 [ad_2] solved Java replace with regex [closed]
[ad_1] Well may be because of the following reasons ArrayList already extends AbstractList and you can extends only one class in java All the functions of Collections are static They do not want anyone to override the methods in case in was not static If one argues that they can be converted into final non … Read more
[ad_1] To answer your question “How to return the matrix”: you are already doing it the right way. As you can see from the comments so far, the problem lies in the declaration of A. A is declared and initialized inside the for-loop: int [][]A = new int [size_num][size_num]; Hence its visibility is limited to … Read more