[ad_1] String.replaceAll() returns a new string with the specified replacement. You need to do: myString = myString.replaceAll( “old”, “new” ); 1 [ad_2] solved String replaceAll not working with string object [duplicate]
[ad_1] Here is some code that utilizes the functions found by sambi: public static void main(String[] args) { Display display = new Display(); final Shell shell = new Shell(display); shell.setLayout(new FillLayout(SWT.VERTICAL)); shell.setText(“StackOverflow”); Monitor primary = display.getPrimaryMonitor(); /* Get the available screen size (without start menu) */ Rectangle area = primary.getClientArea(); shell.pack(); /* Set the shell … Read more
[ad_1] First thing I noticed Book constructors are the main issue. Your first constructor has two parameters title and year. Book b1 = new Book(title, year); But in the second constructor has one parameter title and you have missed the year. That’s why you didn’t get year. Book b2 = new Book(title); You can correct … Read more
[ad_1] I suggest A* Pathfinding. It’s a really neat algorithm that should do what you want. 2 [ad_2] solved Shortest path on a grid with obstacles [closed]
[ad_1] You have to check if the currentDigit is even, not n. if(currentDigit % 2 == 0) [ad_2] solved 14 – Project Euler – Java – Incorrect Answer – Bug?
[ad_1] The direct approach to this problem is to count the number of places where bit at the position i is different from bit at the position i+1. This can be done by XOR-ing the number with itself after a single right shift with sign extension: Integer.bitCount(n ^ (n >> 1)) XOR operator ^ will … Read more
[ad_1] I’ll help with understanding the logic behind such game and give you the testing code but advice you to do it on your own. First, you’ll need a flag to tell you if the game is finished. When does the game finish? 2 possible answers : One of the players wins The cells are … Read more
[ad_1] your code problem is int i = 0 start with 0 and next line if (N%i==0) so 10/0 is not possible throw a error something like java.lang.ArithmeticException: / by zero is not possible and you loop through result.length, you need to loop through i your parent loop and put condition inside if (N%i==0) and … Read more
[ad_1] I would not recommend a regex for this. But it is possible: boolean foundMatch = subjectString.matches( “(?x) # Verbose regex:\n” + “(?!.*(AB|CD|EF).*\\1) # Make sure there are no dupes in the string\n” + “\\s* # Match optional whitespace.\n” + “(?:AB|CD|EF) # Match one of the three candidates\n” + “(?: # Try to match…\n” + … Read more
[ad_1] Try doing something like this… done.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { ClassB b = new ClassB(); ClassB.SimpleThread sx = b.new SimpleThread(); sx.start(); } 0 [ad_2] solved issue:Null Pointer Exception In Android
[ad_1] I’m guessing you have all of your textures on on image? Near the edge of the block, OpenGL is sampling nearby pixels to make it smooth, so on the edge of your dirt block you can see it slightly fading into a stone block try the lwjgl version of this: glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_NEAREST) glTexParameteri(GL_TEXTURE_2D, … Read more
[ad_1] You can use either “0|5” or “[05]”. The first is an alternative, the second is a character class. They will behave identically. See the documentation for Pattern for more information on the building blocks for regular expressions. [ad_2] solved Java – Regex only 0 or 5 [closed]
[ad_1] Try this System.out.println(“originaltext”.replaceAll(“.{1}”,”$0ry”)); The above is using the String replaceAll(String regex, String replacement) method – “Replaces each substring of this string that matches the given regular expression with the given replacement.” “.{1}” – The regular expression used to find exactly one occurrence({1}) of any character(.) “$0ry” – The replacement string with “$0” for the … Read more
[ad_1] That’s because BufferedReader.readLine() reads only a line not the whole file. I assume that the line break characters \r and \n are not part of the normal content you interested in. Maybe that helps. // … StringBuilder sb = new StringBuilder(); String line; while ((line = inputStream.readLine()) != null) { sb.append(line); // if enough … Read more
[ad_1] You can achieve this by doing the following: alist.stream() .flatMap(i -> i == 0 ? Stream.of(i, 0) : Stream.of(i)) .limit(alist.size()) .collect(Collectors.toList()); This basically: flatmaps your integer to a stream of itself if non-zero, and a stream of itself and an additional zero if equal to zero limits the size of your list to the … Read more