I have come to realize that my problem really came out of stuffing two concepts into the AbstractA/ConcreteA hierarchy that didn’t belong together. Though maybe not interesting to very many, I am posting this insight for two reasons: (1) I feel I owe Chris Wohlert the answer I have found myself (2) more importantly, I’d … Read more
They are abstract classes/methods and need to be overridden. You can choose to override the functionality or just let it do what the parent classs is doing. An abstract class is a class that is declared abstract—it may or may not include abstract methods. Abstract classes cannot be instantiated, but they can be subclassed. An … Read more
public static void main(String[] args){ ArrayList<Integer> list = new ArrayList<Integer>(); list.add(5);list.add(2);// to be continued … int randomInt = list.get((int) (Math.random() * list.size())); System.out.println(randomInt); } You’ll get your List of values, and then you just need to pick randomly an index and get back the value Math.random() will pick a value in [0;1[, if you multiply … Read more
Introduction Generating random numbers is a common task in programming, and it can be useful for a variety of applications. However, sometimes it is desirable to generate random numbers that are weighted towards certain numbers. This can be useful for creating a more realistic random distribution, or for creating a game with a higher chance … Read more
You can use regex and Pattern matching to extract it, e.g.: String s = “If this is good and if that is bad”; Pattern pattern = Pattern.compile(“if(.*?)is”); Matcher m = pattern.matcher(s); if(m.find()){ System.out.println(m.group(1).trim()); } 3 solved Extracting a substring based on second occurence using Java – substringBetween() function [closed]
Introduction The substringBetween() function in Java is a useful tool for extracting a substring based on the second occurrence of a given character or string. This function is part of the Apache Commons Lang library, and it can be used to extract a substring from a larger string. This tutorial will explain how to use … Read more
You can do this with the help of selenium.setup selenium in your eclipse first. below is the code for login.similarly you can write program for your profile from. public void login(){ SeleniumUtils.setTextFieldValue(“input#username”, “userName”); SeleniumUtils.setTextFieldValue(“input#password”, “password”); SeleniumUtils.clickOnElement(“div#btnLogin”); } public static void setTextFieldValue(String cssSelector, String value) { WebDriver driver = new FirefoxDriver(); WebElement field =driver.findElement(By.cssSelector(cssSelector)); field.sendKeys(value); } … Read more
Are you sure the definition is actually defining function onChar in class Game and not in class Screen? If you accidentally wrote this as the definition for onChar (which I can imagine could easily happen): void Screen::KeyListener::onChar(char c) {} then you are defining function in class Screen. solved is there an equivalent to ‘classname.this’ from … Read more
Thank you all for the answers. This has helped me understand how to use intents and I was able to solve my problem with this: Activity 1 String json= textViewResult.getText().toString(); Intent i = new Intent(Activity1.this, Activity2.class); i.putExtra(“Data”,json); startActivity(i); Activity 2 Bundle b = getIntent().getExtras(); String json = b.getString(“Data”); TextView jData = (TextView) findViewById(R.id.textView1); jData.setText(json); solved … Read more
You should use dp[count] insted of dp[count+1] in this line: dp[count+1] = new DataPoint(count+1, db.getDetails().getWeight()); because indices in dp will be 0 to count solved Array[index + 1] causing the program FATAL error [duplicate]
There are multiple ways to approach this problem (REST, WebSocket, etc.) I recommend using sockets in this case but I’ll leave it up to you to read up on the pros/cons of different approaches. Socket.IO has a popular Android library for real-time bidirectional event-based communication between two nodes. At a high level, to use Socket.IO … Read more
Is regex necessary for this? substring() gets you want you want easily. Update I saw a comment where you’re also wanting a case where the data looks like, “0|0|0|0|abdc|ghyft|rtyu”. I’ve modified my answer to account for that case and a case where the data could be, “0|0|0|0|abdc|ghyft|rtyu|0|0|0|” Either way: public static void main(String[] args) throws … Read more
That’s because Thread.join() doesn’t release any locks. You’ve designed a perfectly working deadlock, where Thread-1 is waiting for Thread-2 to die having locked on Foo, and Thread-2 is waiting to lock on Foo. (Technically speaking the current implementation does release locks, as it uses internally wait() while synchronized on Thread. However that’s an internal mechanism … Read more
Lots of errors in the code.This works check it. Instead of using 5 different variables i have used an array of size 5 to take input. for(int i=0;i<5;i++) { System.out.print(“Please, Enter a number between 1 – 30 “); nb[i]=input.nextInt(); } As you need to print the nb[i] number of asterisks where nb[i] is ith number … Read more
You this method public String getShortName(String name){ String[] token=name.split(” “); if(token.length>1){ String value=””; for(int i=0;i<token.length;i++){ value+=token[i].substring(0,1); } return value; }else{ return token[0].length()>1?token[0].substring(0,2):token[0]; } } I have tested it, For array of names use this method in for loop 2 solved How to get first and second character from String in multiple conditions