You cannot use a regular int declaration for an array unless you include brackets in the variable name answer[]. Also, array values are defined with curly braces: int count = 0; int[] answer = {2,4,3,2,1}; or int count = 0, answer[] = {2,4,3,2,1}; 3 solved Array answer[i] to if Java
Make sure to use replaceAll(). Also you could put all of the terms and replacements in an array. Like so: String text = “ALTER DATABASE, ALTER TABLE, ALTER VIEW, CREATE DATABASE, CREATE PROCEDURE, CREATE SCHEMA, CREATE TABLE”; String[] terms = {ALTER DATABASE, ALTER TABLE, ALTER VIEW, CREATE DATABASE, CREATE PROCEDURE, CREATE SCHEMA, CREATE TABLE}; String[] … Read more
Map is an interface, it does not make sense to speak about efficiency or performance without a specific implementation. But let’s take HashMap as one of the common implementations. HashMap.containsKey is amortized O(1). Map.keySet().stream().anyMatch(predicate) is O(N) as you iterate over keys. And we don’t even mention all the objects created by this statement. 5 solved … Read more
Android edittext.getText().toString() is always empty.. Because you assigning it as empty. public String Setphase2(Button r,Button l,TextView t,EditText i) { i.setText(“”); // See this line************** r.setText(R.string.upload); l.setText(R.string.edit); t.setText(R.string.key_task); String inputText = i.getText().toString(); Log.d(“UserText”, “Entry text is:” + inputText); i.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD); return inputText; } Remove the following line in the above method. i.setText(“”); 1 solved edittext.getText().getString() is always … Read more
Just call all of the functions on your image file at once, then combine the results using something like zip in RXJava. Alternatively, you could nest the results (e.g. call FirebaseVision.getInstance().onDeviceTextRecognizer.processImage(image) inside the onSuccessListener of another function), although this will take much longer to complete all. If you provide code of your existing attempts, StackOverflow … Read more
One way is to override the paintComponent(…) method of a JPanel to paint the image using the drawImage(….) method. Another option is use a JLabel with an Icon as the background for the frame. Then you can use the Stretch Icon which will automatically scale based on the space available to the label. This is … Read more
java.time and Year.atDay() public static void startEndDate(int endDay) { LocalDate date = Year.of(2020).atDay(endDay); System.out.println(“For the given end day of ” + endDay + ” the date returned is : ” + date); } Let’s try it out: startEndDate(35); startEndDate(49); startEndDate(70); Output is: For the given end day of 35 the date returned is : 2020-02-04 … Read more
This “Insertion sort” code in “Atom” ide using “C++” gives ouput properly but in “Intellij Idea” using “java” the same code gives index out of bound solved This “Insertion sort” code in “Atom” ide using “C++” gives ouput properly but in “Intellij Idea” using “java” the same code gives index out of bound
You are trimming the string and turning it into an invalid JSON. Your JSON starts with a “[” that indicates it is an array. If it starts with “{” you can assume that is an object. So, as your JSON is an array, you can parse this exact content you mentioned with: JSONArray jsonArray = … Read more
How to gather timezone of operating system from Oracle database in string format? (Migrate/convert date to ts with tz) solved How to gather timezone of operating system from Oracle database in string format? (Migrate/convert date to ts with tz)
Probably something along these lines; public int getMaxSum(int[] numbers) { //this stores the highest sum we have found so far //Integer.MIN_VALUE is the smallest possible value, //but your assignment would work with maxSum = -10000; int maxSum = Integer.MIN_VALUE; //starting at the 1st number in the list, then the 2nd, etc for (int pos = … Read more
You are try with the below code for your search. import java.io.File; import java.util.ArrayList; import java.util.List; public class SearchFiles { public static void main(String[] args) { SearchFiles searchFilesObj = new SearchFiles(); searchFilesObj.searchFiles(new File(“/YourFolder/”), “TempFileName”); } private List<String> searchFiles(File file,String fileNameToSearch) { // Directory name should be passed here private List<String> listOfFiles = new ArrayList<String>(); if … Read more
I would strongly consider breaking up your logic into smaller, readable methods. You also don’t need to store the numbers as fields. I.e. Remove this whole block of code… double num1, num2, prod1; double num3, num4, prod2; double num5, num6, prod3; double num7, num8, prod4; double num9, num10, prod5; double grandt = prod1 + prod2 … Read more
String serachkeyword; FileFilter fileFilter = new WildcardFileFilter(serachkeyword); File[] files = new File(path).listFiles(fileFilter); List<File> list = new ArrayList<File>(Arrays.asList(files)); serachkeyword are TBC*IGAXML*1* , *1.0, IGAXMLService etc Its working fine. Thanks for answering my question. solved Java : Wild card File search in Folder
public Employee2[] ePlus(Employee2[] input) { Employee2[] output = new Employee2[input.length + 1]; System.arraycopy(input, 0, output, 0, input.length); return output; } 0 solved How to return an array with one element larger? [duplicate]