You don’t necessarily have to create a Document in order to change an XML document. You can quite easily set up streaming XML parser to do this in an efficient manner. Have a look at the javax.xml.stream package. solved Find a xml element with Regex and replace its value
String.trim() method remove trailing and leading white spaces from the string. but since the string you are testing doesn’t have any trailing or leading white spaces, the below two will certainly return the same string. str.replaceFirst(“(.*)<?xml”,”<?xml”); str.trim().replaceFirst(“(.*)<?xml”,”<?xml”) However, your regular expression only removes leading white spaces, so if the testing string has trailing white spaces … Read more
It will print out 5. It doesn’t even approach to the second if-else, because doesn’t pass the first condition x!=5 and the else statement is missing and it goes to the last line where you print the variable out. It’s the same as: int x=5, y=5, z=5; if (x!=5) { if (y<=7) { z=z+4; } … Read more
There would be no “empty space”, no null. This is the general contract for all lists (List<E>) in Java Collections API. solved Java LinkedList remove
Here’s one way: public static void main(String[] args) { String s = “abc,xyz,lmn,ijk”; char[] ch = s.toCharArray(); int counter = 0; int place = 2; for (int i = 0; i < ch.length-2; i++) { if(ch[i] == ‘,’) { counter++; } if(counter == place && ch[i] != ‘,’) { System.out.print(ch[i]); } } } It prints … Read more
No, example 2 and 3 are not correct. It clearly states, that A extends B and C, besides you have it drawn. 0 solved Java inheritance multiple some questions [closed]
Putting your arraylist inside a method means it can only be accessed by the method it is in and is lost when the method is finished running. You have two options. Change the return type of your method as an arraylist and return and manipulate your arraylist Create the arraylist outside of a method global … Read more
map is a two-dimensional array. map.length specifies the length of the first dimension defined by row. map[0].length in turn specifies the length of the first array of the second dimension. 3 solved Java doesn’t understand the logic of this code
this is almost what you need 🙂 using tabs List<String> l = new ArrayList<String>(Arrays.asList(ss)){; @Override public String toString(){ Iterator<String> it = iterator(); if (! it.hasNext()) return “”; StringBuilder sb = new StringBuilder(); int i = 0; for (;;) { i++; String e = it.next(); sb.append(e); if (! it.hasNext()) return sb.toString(); sb.append(‘\t’); if (i%4==0){ sb.append(“\n”); } … Read more
You can use the time libraries, depending on your minimum API level, to get the times. You can look closer into the documentation to get a better idea of how to use it. Both the code snippets I have below are very similar. http://developer.android.com/reference/android/text/format/Time.html I would try using these two functions (copied and pasted from … Read more
To set any value to label : label.setText(YourValue); so , in your case use this line: tfm.setText(meter+””); solved error while parsing value using Double.parseDouble [closed]
You might want to check to see if “homesConfig.contains(“Homes.” + user.getName() + )” before you try to use it. I think getting something that the config file doesn’t contain will just return null. Here’s how you could check it if (!homesConfig.contains(“Homes.” + user.getName() + “.world”) || <just copy the first condition but for the different … Read more
For starters, you are trying to cast between an Object, String, and a primitive, int. This simply will not work. Objects cannot be cast to primitives, and vice-versa. A String, comprises of an array of char‘s wrapped into an Object. An int, comprises of a single signed decimal number. When you attempt to run a … Read more
The answer is here: http://stackoverflow.com/questions/15699101/get-the-client-ip-address-using-php Easy solution is: $IP = $_SERVER[‘REMOTE_ADDR’]; 2 solved Finding out who sent data to my website [closed]
Before you do anything check for an empty List or a 0 divisor. if(divisor==0||array1.isEmpty()){ return false; } Then you can check the list. for(Integer i: array1){ if(i%divisor!=0){ return false; } } Finally. return true; solved logical OR in Java not working?