java

[Solved] want to perform something untill button is pressed Android

by

Try this: android.os.Handler mHandler = new Handler(); Runnable rUpdateTextView = new Runnable() { @Override public void run () { yourTextView.setText(returndate()); // Update your TextView every 200ms mHandler.postDelayed(this, 200); } }; @Override protected void onCreate(Bundle savedInstanceState) { […] mHandler.post(rUpdateTextView); button.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { mHandler.removeCallbacks(rUpdateTextView); } }); } solved want to perform … Read more

[Solved] How to implement and fire an event when a change occurs in a property of `T` in `List` within the owning class in Java

by

I just ported ItemPropertyChangedNotifyingList to ItemChangeList. In code, I changed this part. Used ‘ArrayList’ to hold elements instead of ‘List` in C# In copyTo, I used Java 8 Stream. Since you tag ‘android’, I used Lightweight-Stream-API to achieve same feature of copyTo. Java doesn’t support get, set syntax, i divide to two methods. import com.annimon.stream.Stream; … Read more

[Solved] Condition for loops in java [closed]

by

Sounds like you are asking how to take a Predicate (BiPredicate<String, String> to be precise) as a parameter. public void bubbleSort(String[] part, BiPredicate<String, String> predicate) { while(predicate.test(part[i], part[i-1])) { // Do bubblesort stuff } } public void bubbleSort(String[] part) { if (isText) { bubbleSort(part, (l, r) -> l.compareToIgnoreCase(r) < 0); } else { bubbleSort(part, (l, … Read more

[Solved] unexpected results: null next to the string [closed]

by

Basically what is happening is you are creating an array of Strings. And you are only initialising the first element of the array to “” sArr[0] = “”; That is why every other element but the first element has a null preceding it. So this statement sArr[test] += c; is going to add a null … Read more

[Solved] How to sort list of objects? [duplicate]

by

You can use interface java.lang.Comparable in java Example (pseudo code) assuming object.distance(player) returns an Integer value class Distance implements Comparable<Distance>{ /** * Compare a given Distance with this object. */ public int compareTo(Distance o) { return this.distance(player).compareTo(o.distance(o.player)); } } now you can sort your list like Collections.sort(YourListOfDistance) here some reference When should a class be … Read more

[Solved] Java 8 not visible [closed]

by

You can’t run javac since the system only has a JRE, not a Java SE (JDK). This means, you can run Java programs but not compile new ones (so far). You need to install a separate Java to be able to compile. You can have multiple JVMs. I have Java 6, Java 7, and Java … Read more

[Solved] Why do we use * in the end of java.sql.* package [closed]

by

By doing import java.sql.* you import all classes from the package java.sql at once, so that you don’t have to import them one by one. It’s more convenient to write when you’re importing many classes from some package. For example, instead of: import java.sql.Statement; import java.sql.ResultSet; import java.sql.Connection; // …etc. you can just write: import … Read more

[Solved] Converting char to string [closed]

by

Character.toString(data) This fragment should not compile because this method accepts only single character. Use this call instead: String.valueOf(data) Also, new String(dataB) is redundant. Replace it with simply dataB 0 solved Converting char to string [closed]

[Solved] If statement not comparing strings properly

by

Use this if (!bedSize.equals(“SINGLE”) && !bedSize.equals(“DOUBLE”) && !bedSize.equals(“KING”)) (If the bed size is different than “SINGLE” and different that “DOUBLE” and different than “KING”) solved If statement not comparing strings properly