continue will cause the remaining portion of the enclosing for or while loop body to be skipped. In your case, the for is the “enclosing” loop of continue and the while loop is the “enclosing” scope of the for loop. According to (unofficial) documentation The continue statement causes a jump, as if by goto to … Read more
You can use the while loop as follows: int i=1; while(i<=7) { sal = load(); rate = calcRate(sal); calcRaise(sal, rate, &raise, &totraise); calcNewSal(sal, raise, &newsal, &totnewsal); calcTotSal(&sal, &totsal); print(sal, rate, raise, newsal, totsal, totraise, totnewsal); fflush(stdin); i++; } And the do-while as follows: int i=1; do { sal = load(); rate = calcRate(sal); calcRaise(sal, rate, … Read more
The < is an html entity that represents the less than (<) sign. Your for(int i=0;i < 1000; i++) is just for(int i=0;i < 1000; i++) in html. solved What’s the meaning of this kind of loop: for(int i=0;i < 1000; i++)
First iteration, j is 0, i is 1. j is set to 0+1 == 1. Second interation, j is 1, i is 3. j is set to 1+3 == 4. Third iteration, j is 4, i is 5. j is set to 4+5 == 9. Fourth iteration, j is 9, i is 7. j is … Read more
You could use 2 for loops, you just have to understand the problem correctly then you could convert it to code easily. from my understanding you want to have n rows and in ith row you want to have multiple of i with every number less than or equal 2*i-1 so just use one for … Read more
You copied the statement wrong. In the program you cited in your comment there’s only one for statement which approximates what you posted above: for(time=0,count=0;remain!=0;) In this case the “initialization” portion of the for statement is time=0,count=0 Note that the character between the initialization of time and count is a comma, not a semicolon. This … Read more
@RodyOldenhuis basically answered your question, and I’m flattered he hasn’t made this into an actual answer! Simply take your code and change the inner for loop index so that it matches the outer loop index. In other words, do this: syms l %// Why are you doing this? a = [0 1 0 0 1 … Read more
In your for loop, the variable result Is created outside of the for loops scope. Essentially, you are just changing the result variable that has already been created. If you attempted to create a new variable within the for loop such as “newResult = base * result”, it would fail if you attempted to use … Read more
For a consider this : /*Outputs a serious of 5 numbers, starting at 1. The difference between one number to the next one is a sequence of numbers, starting at 1 and incremented by 1 i.e: 1,2,3,4,5 */ //represents the difference between one number and the next one. //the first difference is 1. int step … Read more
Not quite equilateral but as close as you’re likely to get with character graphics. The main things are that you need an odd number of asterisks on each line for centering to work and you need to calculate an offset. (And, even so, you need output in a monospaced font for this to look right.) … Read more
I am afraid not. But you can use IDE such as JetBrains which makes it easier to have proper indendation. solved Python loop syntax
You can do it like this to iterate the whole array column-wise: // Get the maximum number of columns among all rows. int maximumColumns = 0; for (double[] row : multi) { if (row.length > maximumColumns) { maximumColumns = row.length; } } for (int column = 0; column < maximumColumns ; column++) { for (int … Read more
Answering the literal question as stated… The reason for the warning is simply because the left side of the comma in the for loop, third section, will have no effect. i+8 does not change anything, but rather returns a value. Instead, you are wanting the compound assignment addition operator, += i+=8, which will add 8 … Read more
You could try using ternary operators. It makes the readability of your code more difficult (my opinion, but some people like it), but you put everything inside your for statement. For the numbers that can be divided by 3, for instance: for (int i = 1; i < N; i = (((i+1)%3 == 0) ? … Read more
You got the initialization (first) part of the loop right. The termination or condition (second) part of the loop should be evaluated to a boolean, so assuming you require an AND relation between the conditions on a and b, it becomes a<101 && b<102. You might want || (OR) instead, depending on your logic. The … Read more