[ad_1] /\d{1,2}\/\d{1,2}\/(?:\d{2}){1,2} \d{1,2}:\d{2}(:?:\d{2})?/gm For a few pieces: \d{1,2} matches 1 or two digits. (?:\d{2}){1,2} matches a group of two digits once or twice. (therefore, 2 or 4 digits) (?:\d{2}:)? allows the seconds to be optional 2 [ad_2] solved How to find any date format in a string [closed]
[ad_1] You can use a text datatype to store dates within SQLite while table creation. Storing dates in UTC format, the default if you use datetime(‘now’) (yyyy-MM-dd HH:mm:ss) will then allow sorting by the date column. Retrieving dates as strings from SQLite table you can then convert them as required into formats using the Calendar … Read more
[ad_1] Jain, it looks like you are trying to adapt the code in the answer here to your own situation. What Andomar did there was to select the information from a subquery which contained only a single value, since he didn’t have access to the original poster’s source and tables. Doing it that way allows … Read more
[ad_1] ZoneId defaultZoneId = ZoneId.systemDefault(); String issueDate1=”01/01/2017″; Date issueDate2=new SimpleDateFormat(“dd/MM/yyyy”).parse(issueDate1); String dateTo1=”31/12/2018″; Date dateTo2=new SimpleDateFormat(“dd/MM/yyyy”).parse(dateTo1); here year month days can find easily.This giving ans of all question. Instant instant = issueDate2.toInstant(); LocalDate localDatestart = instant.atZone(defaultZoneId).toLocalDate(); Instant instant1 = dateTo2.toInstant(); LocalDate localDateend = instant1.atZone(defaultZoneId).toLocalDate().plusDays(1); Period diff = Period.between(localDatestart, localDateend); System.out.printf(“\nDifference is %d years, %d months and … Read more
[ad_1] Try this should help: $datedb = “2018-03-01 11:54:33”; $date = date(‘d-m-Y’, strtotime($datedb)); echo $date; // will print 01-03-2018 And read about date() function of php: http://php.net/manual/en/function.date.php; https://www.w3schools.com/php/func_date_date.asp 0 [ad_2] solved SQL Timestamp format in PHP [duplicate]
[ad_1] You should look at the DateTime object and its related functions in the documentation. If your input date is already in a string format, DateTime::createFromFormat() will help you create an epoch-type integer date the object can work with. After that, it’s just getTimezone() and setTimezone(). 0 [ad_2] solved How to convert a datetime string … Read more
[ad_1] If MyClass expects a DateTime, you should use the value from the DatePicker‘s SelectedDate property. It returns a Nullable<DateTime> that can be converted to a DateTime using the GetValueOrDefault() method: newObject = new Classes.MyClass(datePicker.SelectedDate.GetValueOrDefault()); If there is no date selected, GetValueOrDefault() will return DateTime.MinValue. The DatePicker doesn’t store the date in any particular format. … Read more
[ad_1] DateTime.Now would give you current time for your time zone. DateTime.UtcNow gives you current date and time on this computer, expressed as the Coordinated Universal Time (UTC). [ad_2] solved How do I get the correct time in C#
[ad_1] This doesn’t work because you compare a DateTime object with a string. You need to use two DateTime objects: $store_closed = DateTime::createFromFormat (‘H:i:s’, ‘1:00:00’); echo ($store_closed > $set_time) ? ‘yes’ : ‘no’; 1 [ad_2] solved Need help comparing times using datetime [closed]
[ad_1] There was a typo:[dateFormatter setDateFormat:@”HH:mm:ss”]; should be:[formatter setDateFormat:@”HH:mm:ss”]; To compare two dates use: NSDate *date1 = [NSDate date]; NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; [formatter setDateFormat:@”HH:mm:ss”]; NSDate *date2 = [formatter dateFromString:@”05:00:00″]; NSComparisonResult result = [date1 compare:date2]; if(result == NSOrderedDescending) { NSLog(@”date1 is later than date2″); } If you only want to compare the hours: … Read more
[ad_1] start_date and stop_date are strings, which don’t support the – operator. If you want to compute their (numerical) difference, define them as integers, i.e. start_date = 20151231171500 stop_date = 20151231174500 or cast them to int: test = int(stop_date) – int(start_date) Caveat: the difference of these numbers would be 3000, not 30. Not sure why … Read more
[ad_1] EDIT From SQL Server 2012 and later you might use the FORMAT function if you want to force a date into a formatted text: https://msdn.microsoft.com/en-us/library/hh213505.aspx With earlier versions you might use something like this: DECLARE @d DATETIME=GETDATE(); DECLARE @TargetFormat VARCHAR(100)=’DD/MM/YYYY’; SELECT CONVERT(VARCHAR(100),@d, CASE @TargetFormat WHEN ‘MM/DD/YYYY’ THEN 101 WHEN ‘DD/MM/YYYY’ THEN 103 –add all … Read more
Introduction [ad_1] This article provides a solution to the problem of converting a string in the format of “yyyyMMdd” to a datetime object. This is a common issue encountered when dealing with date and time data, and can be solved using a variety of methods. This article will discuss the different approaches to solving this … Read more
[ad_1] Use DateTime.ParseExact to specify the format and invariant culture: var date = DateTime.ParseExact(date, “yyyyMMdd”, CultureInfo.InvariantCulture); [ad_2] solved String not valid as a datetime string – Convert “yyyyMMdd” to datetime [closed]
[ad_1] The year does automatically change with adding and subtracting months. See This Example. 0 [ad_2] solved +/- 1 month to the datetime