/\d{1,2}\/\d{1,2}\/(?:\d{2}){1,2} \d{1,2}:\d{2}(:?:\d{2})?/gm For a few pieces: \d{1,2} matches 1 or two digits. (?:\d{2}){1,2} matches a group of two digits once or twice. (therefore, 2 or 4 digits) (?:\d{2}:)? allows the seconds to be optional 2 solved How to find any date format in a string [closed]
You can use a text datatype to store dates within SQLite while table creation. Storing dates in UTC format, the default if you use datetime(‘now’) (yyyy-MM-dd HH:mm:ss) will then allow sorting by the date column. Retrieving dates as strings from SQLite table you can then convert them as required into formats using the Calendar or … Read more
Jain, it looks like you are trying to adapt the code in the answer here to your own situation. What Andomar did there was to select the information from a subquery which contained only a single value, since he didn’t have access to the original poster’s source and tables. Doing it that way allows everyone … Read more
ZoneId defaultZoneId = ZoneId.systemDefault(); String issueDate1=”01/01/2017″; Date issueDate2=new SimpleDateFormat(“dd/MM/yyyy”).parse(issueDate1); String dateTo1=”31/12/2018″; Date dateTo2=new SimpleDateFormat(“dd/MM/yyyy”).parse(dateTo1); here year month days can find easily.This giving ans of all question. Instant instant = issueDate2.toInstant(); LocalDate localDatestart = instant.atZone(defaultZoneId).toLocalDate(); Instant instant1 = dateTo2.toInstant(); LocalDate localDateend = instant1.atZone(defaultZoneId).toLocalDate().plusDays(1); Period diff = Period.between(localDatestart, localDateend); System.out.printf(“\nDifference is %d years, %d months and %d … Read more
Try this should help: $datedb = “2018-03-01 11:54:33”; $date = date(‘d-m-Y’, strtotime($datedb)); echo $date; // will print 01-03-2018 And read about date() function of php: http://php.net/manual/en/function.date.php; https://www.w3schools.com/php/func_date_date.asp 0 solved SQL Timestamp format in PHP [duplicate]
You should look at the DateTime object and its related functions in the documentation. If your input date is already in a string format, DateTime::createFromFormat() will help you create an epoch-type integer date the object can work with. After that, it’s just getTimezone() and setTimezone(). 0 solved How to convert a datetime string to UTC?
If MyClass expects a DateTime, you should use the value from the DatePicker‘s SelectedDate property. It returns a Nullable<DateTime> that can be converted to a DateTime using the GetValueOrDefault() method: newObject = new Classes.MyClass(datePicker.SelectedDate.GetValueOrDefault()); If there is no date selected, GetValueOrDefault() will return DateTime.MinValue. The DatePicker doesn’t store the date in any particular format. That’s … Read more
DateTime.Now would give you current time for your time zone. DateTime.UtcNow gives you current date and time on this computer, expressed as the Coordinated Universal Time (UTC). solved How do I get the correct time in C#
This doesn’t work because you compare a DateTime object with a string. You need to use two DateTime objects: $store_closed = DateTime::createFromFormat (‘H:i:s’, ‘1:00:00’); echo ($store_closed > $set_time) ? ‘yes’ : ‘no’; 1 solved Need help comparing times using datetime [closed]
There was a typo:[dateFormatter setDateFormat:@”HH:mm:ss”]; should be:[formatter setDateFormat:@”HH:mm:ss”]; To compare two dates use: NSDate *date1 = [NSDate date]; NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; [formatter setDateFormat:@”HH:mm:ss”]; NSDate *date2 = [formatter dateFromString:@”05:00:00″]; NSComparisonResult result = [date1 compare:date2]; if(result == NSOrderedDescending) { NSLog(@”date1 is later than date2″); } If you only want to compare the hours: NSCalendar … Read more
start_date and stop_date are strings, which don’t support the – operator. If you want to compute their (numerical) difference, define them as integers, i.e. start_date = 20151231171500 stop_date = 20151231174500 or cast them to int: test = int(stop_date) – int(start_date) Caveat: the difference of these numbers would be 3000, not 30. Not sure why you … Read more
EDIT From SQL Server 2012 and later you might use the FORMAT function if you want to force a date into a formatted text: https://msdn.microsoft.com/en-us/library/hh213505.aspx With earlier versions you might use something like this: DECLARE @d DATETIME=GETDATE(); DECLARE @TargetFormat VARCHAR(100)=’DD/MM/YYYY’; SELECT CONVERT(VARCHAR(100),@d, CASE @TargetFormat WHEN ‘MM/DD/YYYY’ THEN 101 WHEN ‘DD/MM/YYYY’ THEN 103 –add all formats … Read more
Introduction This article provides a solution to the problem of converting a string in the format of “yyyyMMdd” to a datetime object. This is a common issue encountered when dealing with date and time data, and can be solved using a variety of methods. This article will discuss the different approaches to solving this problem, … Read more
Use DateTime.ParseExact to specify the format and invariant culture: var date = DateTime.ParseExact(date, “yyyyMMdd”, CultureInfo.InvariantCulture); solved String not valid as a datetime string – Convert “yyyyMMdd” to datetime [closed]
The year does automatically change with adding and subtracting months. See This Example. 0 solved +/- 1 month to the datetime