Even though this question is Way too broad, and actually not asking anything, i’ll give it a few minutes of attention. 1) You backup the current state and work on a Sandbox! 2) if your only need is few reports, i guess you can generate them query the different databases independently and maybe post processing … Read more
Your SQL CTE syntax is incorrect: you have a comma after the last CTE’s close-paren. The only time you need a comma there is if you have another CTE following it. Try changing to with unit as ( select t.RefDate, … ), — yes comma here, between CTEs agg as ( select u.RefDate, … ) … Read more
If you are looking to search, you need to use the LIKE syntax, not WHERE $sql=”SELECT * FROM members WHERE FirstName LIKE ‘”. $fname .”%'”; The LIKE & % make it a wildcard. Now you said you want to search by first and last, but you only pass in your first variable and you only … Read more
All you need to do is remove the < and > characters: SELECT r1.rnr, r1.anaam FROM regisseur r1, regisseur r2 WHERE r2.anaam = ‘input last name director’ AND r1.gdatum < r2.gbdatum Here’s a working demo on SQLFiddle. Presuming you don’t have a good reason to SELECT from regisseur twice, this can be further condensed down … Read more
You can try ActiveAndroid, it is opensource and easy to implement 🙂 https://www.activeandroid.com/ solved Android persistance package? [closed]
If you really want to parse and store into the database so better way is to load in some range like 0-50-100-150 or 0-100-200. So You can achieve this by using ListView with load Button. You can make it like it will load automatically while scrolling to position say 50 or 100 what ever its … Read more
select cat_id, count(1) cnt from category join topic on cat_is = cat_id join comment on topic_is = topic_id group by cat_id solved How to count total comment in a category not a topic
First change the method signature to return a value: public static boolean checkUSPASS(String a,String b) Then return a value from within the method: return true; or: return false; Note that all code paths must return some value. So you have this in your try block: if (rs.next()) { return true; } else { return false; … Read more
I’m using MYSQL Workbench right now to build my database, do I need to build my database differently now to use MYSQLI or is MYSQLI just the syntax for connecting to the database. No. You do not need to build your database again. MYSQLI is a set of functions to establish a relation with any … Read more
From your code – assuming the function stats is being executed one per game iteration. the gamesStruct local variable is being destroyed at end of stats and being declared (and initialized) again and again. this is why the previous result is cleared. you should declare the gamesStruct at tge calling API and pass it by … Read more
First of all you want to show user data (name etc.), so select from user. You want to show their friends status related to user 1 with it, so join accordingly. As they can have a friends status related to user 1 or not, but you want to show them anyway, you cannot use an … Read more
Label[] lbl1 = new Label[25]; should really be Label[] lbl1 = new Label[DataTable1.Rows.Count]; AND you need to do lbl1[I] = new Label(..) before you call lbl1[I].Text = …` 13 solved C# data from database to label
You’re most likely going to need to develop a web service architecture and use the network connection on the android phone to post requests to the website. You’ll have to look into this, nobody is going to just give you all the code you need. try looking at tutorials like this (using java REST) : … Read more
Try using http://wordnet.princeton.edu/ WordNet® is a large lexical database of English. Nouns, verbs, adjectives and adverbs are grouped into sets of cognitive synonyms (synsets), each expressing a distinct concept. Synsets are interlinked by means of conceptual-semantic and lexical relations. http://wordnet.princeton.edu/wordnet/license/ solved link for free data base contains all words in English? [closed]
This Following Query Worked For Me : SELECT *, orders.id AS id, orders.name AS name FROM orders LEFT JOIN cart ON orders.authID = cart.authID WHERE orders.id != ‘0’ GROUP BY orders.authID solved joining two related tables in mysql