[Solved] infinite loop until one of three conditions is True. Python

You can add an if condition inside an infinite while loop to break out of it. Also your run_test() function must return the score, see below: class Question: def __init__(self, prompt, answer): self.prompt = prompt self.answer = answer def run_test(questions): score = 0 for question in questions: while True: answer = input(question.prompt) if answer in … Read more

[Solved] JS condition change class

You need just innerHTML/innerText method and set of conditions. No jQuery needed. var el = document.getElementById(‘polIndice’); var val = parseInt(el.innerText); var class_name; if (val < 50) { class_name=”indiceLow”; } else if (val < 100) { class_name=”indiceMedium”; } else { class_name=”indiceHigh”; } el.className += ‘ ‘ + class_name; http://jsfiddle.net/hyuu5w5z/ 1 solved JS condition change class

[Solved] If x = 2 y = 5 z = 0 then find values of the following expressions: a. x == 2 b. x != 5 c. x != 5 && y >= 5 d. z != 0 || x == 2 e. !(y < 10) [closed]

There are several differences between Java and Python. One of which is the use of ‘if’ statements. In python, an ‘if’ statement follows this structure: if CONDITION: elif CONDITION: else: The operators are also slightly different. Rather than || it’s or Rather than & it’s and Boolean works similarly, except python capitalizes the first letter. … Read more

[Solved] Print message if a certain condition meet on a dataframe

import pandas as pd, numpy as np # filter results by showing records that meet condition # sample df d = {‘SBP’: [111, 100], ‘DBP’: [81, 40], ‘HEARTRATE’:[1,50]} df = pd.DataFrame(data=d) df # if an alert is found, prints alert, else normal if len(df[(df[ ‘SBP’ ] > 110) & (df[ ‘DBP’ ] > 80) & … Read more

[Solved] How to choose proper if statements in linked list?

Consider the following Linked List: HEAD —> [“value2” | -]–> [“value3” | -]–> [“last_value” | null] Assuming current points to “value3”: HEAD —> [“value2” | -]–> [“value3” | -]–> [“last_value” | null] ↑ then current.next != null is true, since current.next is actually the “next” node. Now let’s assume current moved to “last_value”, now we’ll … Read more