[Solved] How “java.util.Comparator.compare(String o1, String o2) ” method works

[ad_1] Strings are comparable in a lexicographic order (i.e., the order they’d appear in a dictionary). If you want to implement a Comparator for clothes sizes, you’d have to write the logic yourself. E.g.: public class ClothesSizeComparator implements Comparator<String> { private static final List<String> SIZES = Arrays.asList(“XS”, “S”, “M”, “L”, “XL”, “XXL”, “3XL”); @Override public … Read more

[Solved] Java 8 comparator not working

[ad_1] The comparator seems correct. The problem seems to be in your filter clause, where you compare the event id to the device id lastDeviceEvent = deviceEvents .stream() .filter (o -> o.getDeviceId().equals(deviceId)) // Original code used getId() .sorted(comparing((DeviceEvent de) -> de.getId()).reversed()) .findFirst() .get(); [ad_2] solved Java 8 comparator not working

[Solved] how comparable interface return int value, if an interface having only method declaration

[ad_1] CompareTo method does have an implementation. The method is implemented in all the classes such as Integer, Double etc. In your case you are using String’s compareTo method. If you want it to be customized as per your class, you do so by overriding the compareTo method. 1 [ad_2] solved how comparable interface return … Read more

[Solved] How to have jtables values which are strings in alphabetical order using comparator and tablerowsorter? [closed]

[ad_1] You must create a comparator: Comparator<String> comparator = new Comparator<String>() { public int compare(String s1, String s2) { return s1.compareTo(s2); } }; With this comparator you will be able to sort your data in alphabetical order. After that create sorter and pass this comparator and model of your JTable. Then: sorter.sort(); I think after … Read more