Strings are comparable in a lexicographic order (i.e., the order they’d appear in a dictionary). If you want to implement a Comparator for clothes sizes, you’d have to write the logic yourself. E.g.: public class ClothesSizeComparator implements Comparator<String> { private static final List<String> SIZES = Arrays.asList(“XS”, “S”, “M”, “L”, “XL”, “XXL”, “3XL”); @Override public int … Read more
after you’ve sorted the director list…. just take one director as an key value in outer loop and then start comparing each and every movie name in inner loop… How can I sort a List alphabetically? this would be helpful… do some searching next time….it is easy to find such solutions… 🙂 😉 3 solved … Read more
Rules for a.compareTo(b) returns negative value : a is before b returns 0 : a equal to b return positive value : a is after b Because the parameter are first, second and you compare like second.compareTo(first) you’ll get reverse order : (second+first) 344 first+ second 434 comparing : -1 >> 4 is before 34 … Read more
You should change Collections.sort(array, new j()); to Arrays.sort(array, new j()); solved Java error :- “no suitable method found for sort(Student[],j)”
Don’t use getClass().toString() to compare types. Use instanceof and try to group types by common interfaces when possible. For example CharSequence is a common interface for String, StringBuilder, and StringBuffer. Here is one way. You may want to rework the compare method to compare whatever types you have such as Date or URL or custom … Read more
The comparator seems correct. The problem seems to be in your filter clause, where you compare the event id to the device id lastDeviceEvent = deviceEvents .stream() .filter (o -> o.getDeviceId().equals(deviceId)) // Original code used getId() .sorted(comparing((DeviceEvent de) -> de.getId()).reversed()) .findFirst() .get(); solved Java 8 comparator not working
CompareTo method does have an implementation. The method is implemented in all the classes such as Integer, Double etc. In your case you are using String’s compareTo method. If you want it to be customized as per your class, you do so by overriding the compareTo method. 1 solved how comparable interface return int value, … Read more
You should provide inner class instance into Arrays.sort to compare points from view of parent class instance. To do it you should not create new instance in main() function, but get it from Point instance. So, in main function you should use something like this: Point pivot; … // set up pivot point here Arrays.sort(myPoints, … Read more
You must create a comparator: Comparator<String> comparator = new Comparator<String>() { public int compare(String s1, String s2) { return s1.compareTo(s2); } }; With this comparator you will be able to sort your data in alphabetical order. After that create sorter and pass this comparator and model of your JTable. Then: sorter.sort(); I think after that … Read more
If you want to know just if an object is equal to another you have to implemet the equals method (which doesn’t requiere you to declare any interface, every class can do it) @Override public boolean equals(Object o) { CompararListas other = (CompararListas) o; return … } with this method you can return what makes … Read more