You can try this one : s = “H!i I am f.rom G3?ermany” l = [] for i in s.split(): k = [j for j in i if j.isalpha()] for m in i: if not m.isalpha(): k.append(m) l.append(”.join(k)) print(‘ ‘.join(l)) It will o/p like : “Hi! I am from. Germany3? In python 2x you can … Read more
Not doing something to the outcome of both sub‘s relies on the byte wraparound and can only works as long as unsigned logic is used via jbe and friends. This is the simplest code you can write to differentiate between any case letters and all the rest: sub al, ‘A’ cmp al, ‘Z’-‘A’ jbe Letter … Read more
On the coding side, since this is C++, don’t store lists of strings in a two-dimensional array of char. Try std::vector<std::string> instead. And don’t read your file one character at a time; read larger blocks of characters. If you can guarantee that there are never spaces embedded within first names, you can write something like … Read more
On my Debian/Sid/x86-64 the below program (in source file itsols.cc compiled with the command g++ -Wall itsols.cc -o itsols) #include <iostream> #include <string> int main(int, char**) { std::string s = “Hello”; std::cout << s[3] << std::endl; return 0; } displays a single lower-case l (compiled with g++ -Wall itsols.cc -o itsols, both with GCC 4.7.2 … Read more
public static String swap (String entry){ char[] characters = entry.toCharArray(); if (entry.length() < 6){ return null; // cannot swap if length is under 6! } char tempchar; tempchar = characters[0]; characters[0] = characters[characters.length-1]; characters[characters.length-1] = tempchar; tempchar = characters[1]; characters[1] = characters[characters.length-2]; characters[characters.length-2] = tempchar; tempchar = characters[2]; characters[2] = characters[characters.length-3]; characters[characters.length-3] = tempchar; return … Read more
If you have a string: a=”hi how \\are you” you can remove it by doing: a.replace(‘\\’,”) >’hi how are you’ If you have a specific context where you are having trouble, I recommend posting a bit more detail. 2 solved I want to remove ‘\’ from a string in python [duplicate]
This will shift chars to the right, making room for insertion. void rshift( char *s ){ int n = strlen( s); s[ n + 1] = 0; while( n ){ s[ n ] = s[ n-1 ]; n–; } } int main(){ char *p = strchr(sentence , replace); if( p ) { p++; // insert … Read more
“How can a pointer to a character data type can hold a string data type?” Well, it’s partly true that in C, type ‘pointer to char’ is the string type. Any function that operates on strings (including printf) will be found to accept these strings via parameters of type char *. “How can printf() print … Read more
See the code snippet for your understanding: #include <iostream> #include <string> using namespace std; int main() { string name; char arr[10] = { ‘a’, ‘b’, ‘c’, ‘d’, ‘e’, ‘f’, ‘g’, ‘h’, ‘i’, ‘j’ }; bool found_a = false; bool found_b = false; bool found_c = false; for (int x = 0; x < 10; x++) … Read more
Check Regex and Substring For your example it would be something like public boolean isValid(String h) { return h.substring(1).matches(“^[A-H0-9]+$”); } 2 solved Check the characters of a string
The question is asking you to create a function(def) named generate_n_chars() that takes an integer(int) value,n and character(char) value,c as parameters. Here, c is any character input by user,lets say user inputs x and n is how many times the character(c) should be printed so lets say user wants it to print 5 times and … Read more
With java 8 it is much easy. You could use something like this return string.chars().distinct().count(); solved How to find number of distinct characters in a string
For Windows, there is the _getch function, which returns the bytes of a key code, one by one. You can get a function key that way, detecting it by the presence of certain codes: 0x00 or 0xe0 as shown in the example in [C\C++] – how get arrow keys(correctly) using getch()?. When _getch returns one … Read more
Javadoc of Properties.load(InputStream inStream) says: The input stream is in a simple line-oriented format as specified in load(Reader) and is assumed to use the ISO 8859-1 character encoding; that is each byte is one Latin1 character. Characters not in Latin1, and certain special characters, are represented in keys and elements using Unicode escapes as defined … Read more
Kindly go through following R console code snippet: > dates <- c(“10/23/16”, “10/24/16”) > dates [1] “10/23/16” “10/24/16” > Dates <- as.Date(dates, + format = “%m/%d/%y”) > Dates [1] “2016-10-23” “2016-10-24″ Hope it works for you! solved Fix incomplete character string for year “2016” from “0016” in R [closed]