The type of 0.5 in C++ is double. If you want a float you need to say 0.5f . This is part of the definition of C and C++. Implied in your question is some desire for automatic type selection based on the number of digits in the value, e.g. we could use float for … Read more
Assuming I understand your need, you could try something like the following: /* Create a mock-up table with sample data */ DECLARE @Data TABLE ( InstrumentID INT, InstrumentType VARCHAR(50), InstrumentNumber INT, NANumber INT, DateTimeFiled DATETIME, [Name] VARCHAR(255) ); INSERT INTO @Data ( InstrumentID, InstrumentType, InstrumentNumber, NANumber, DateTimeFiled, [Name] ) VALUES ( 1625168, ‘ACCOUNTS RECEIVABLE’, 1, … Read more
The following code adds an text box to the form using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace WindowsFormsApplication3 { public partial class Form1 : Form { TextBox txtBox; public Form1() { InitializeComponent(); } private void button1_Click(object sender, EventArgs e) { txtBox = new TextBox(); txtBox.Location … Read more
Although it would be easier to help you if you were to post a minimal reproducible example, as text, formatted as a code sample, I think I still understand what you’re asking. This looks like a learning exercise that you want to solve on your own. But I can give some advice. What you want … Read more
You can use a Count variable. int count=0; Loop() { count++; } if (count==1) do something; else do something else; if (count%2==0) //count is even do this; else //count is odd do that; solved Adding conditional statement to the number of times a loop is executed [closed]
Your void Write(const std::string& inString) function of OutputMemoryStream should not store additional byte of buffer for null terminator because std::string will not contain null terminator but if you use c_str(), a null terminator will be included in the return from this method. Don’t get confused with the internal structure of the memory. std::string stores the … Read more
Your problem is here: for(int i =2;i<=n-1;i++) { if(n%i != 0) { break; } else { sum = sum + i; } } With break you are stopping the whole iteration of you for loop, meaning after the first number which is not a divisor, i.e. where n%i != 0 equals true you are breaking … Read more
Since after one day all the comments and answers so far obviously could not help you, see the following simple solution. The exercise targets people starting with C++, so I suppose it is better to use basic constructs like arrays and loops. The array counts holds the counts of the digits, one for each possible … Read more
when call an btn click method on enter key press Error accured ” An Obeject reference is required for non-static field, method or property” [duplicate] solved when call an btn click method on enter key press Error accured ” An Obeject reference is required for non-static field, method or property” [duplicate]
try something like this using System; public class RemoveTest { public static void Main() { string name = “Michelle Violet Banks”; Console.WriteLine(“The entire name is ‘{0}'”, name); // remove the middle name, identified by finding the spaces in the middle of the name… int foundS1 = name.IndexOf(” “); int foundS2 = name.IndexOf(” “, foundS1 + … Read more
You can update your crawler list from an XML source like http://www.user-agents.org/ solved C# get list bots dynamic [closed]
Hi Gailen use the following method: File.ReadAllLines(@”location”); If location is correct then this will work Assign to variable, for example 0 solved Reading a text file with c# [closed]
This all depends on the functionality of your Connections class. The easiest answer I can give is that you can make the individual methods static, assuming they don’t require instance specific data. If your individual methods require instance specific data, then you could possibly make the instance a singleton instance (either through have an Instance … Read more
You are asking printf() to represent the numbers as hexadecimal. Try using %d or %i instead of %x. This will show them as decimal numbers. solved Why does C code return numbers greater than 10 as letters?
In ASCII character 2 has code 50. So 50 – 47 will result in 3. Thus if in statement cin>>s; you enetered 2 then in statement cout<<(*s.begin())-47; expression *s.begin()-47 that is equivalent to ‘2’ – 47 is converted to type int due to the integer promotion and is equal to 3 ( ‘2’ – 47 … Read more