[Solved] Explain the output when a integer is given as input [closed]

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In ASCII character 2 has code 50. So 50 – 47 will result in 3.
Thus if in statement

   cin>>s;

you enetered 2

then in statement

    cout<<(*s.begin())-47;

expression *s.begin()-47 that is equivalent to '2' - 47 is converted to type int due to the integer promotion and is equal to 3 ( ‘2’ – 47 => 50 – 47 == 3).

Take into account that call s.begin() returns iterator that points to the first character of the string and *s.begin() yields the character itself.

solved Explain the output when a integer is given as input [closed]