[ad_1] A MS SQL Server database, by default, only has a single schema (dbo). You can add schemas to group things for either security or organizational purposes. In your case, the schema apbd was created and Student was created on that schema not the dbo schema. So, to reference that table, you need to use … Read more
[ad_1] In this case, you can consider using the Microsoft Graph – Create Group First, ensure you have assigned the “Microsoft Graph” > “Read and write all groups” permission to app in Azure AD. Code for your reference: string authority = “https://login.windows.net/yourdomain.onmicrosoft.com”; string clientId = “{client_id}”; Uri redirectUri = new Uri(“http://localhost”); string resourceUrl = “https://graph.microsoft.com”; … Read more
[ad_1] There are numerous errors in the program although it compiled without any warnings. Chiefly the pointer types for your array, and the memory allocated. Secondly the function does not know how many words is allowed, and does not return how many were read – your method did not work at all (as in comments). … Read more
[ad_1] Try this: #include <stdio.h> void getInput(int sizeOfInput, int arr[]) { int i = 0; printf(“IN”); for(; i < sizeOfInput – 1; ++i) { scanf(“%d, “, &arr[i]); } scanf(“%d”, &arr[i]); printf(“OUT”); } main(){ int sizeOfInput = 0; printf(“Enter how many numbers do you want to enter?”); scanf(“%d”, &sizeOfInput); int arr[sizeOfInput]; getInput(sizeOfInput, arr); } Sorry I … Read more
[ad_1] Its so simple buddy. I found a simple solution using the reflection and extnetion method just follow as below Create a static class with the name “CompareTwoObjects” and add the code to it. public static object CompareEquals(this T objectFromCompare, T objectToCompare)//Generic method { if (objectFromCompare == null && objectToCompare == null) return true; else … Read more
[ad_1] To group characters by 3, first count how many there are: int num_of_binary_digits = strlen(binarni); This may not be divisible by 3. For example: Binary string: 00001111 Subdivided into groups of 3: 00|001|111 To count the number of octal digits, divide by 3 with rounding up: int num_of_octal_digits = (num_of_binary_digits + 2) / 3; … Read more
[ad_1] It would be better if you could use separate variables for total score, total even score and total odd score. Then in the condition check update the corresponding total variables. int total_fh = 0, total_es = 0, total_os = 0; if (score >=50 && score <= 100) { total_fh += score; if (score % … Read more
[ad_1] You would utilize the alloc and init (or more specialized initializer) provided by NSObject. For example, something like the following should work: int fromuser, a; NSMutableArray objectArray = [[NSMutableArray alloc] initWithCapacity:fromuser]; for (a = 0; a < fromuser; a++) { MyObject *obj = [[MyObject alloc] init]; [objectArray addObject:obj]; [obj release]; //If not using ARC … Read more
[ad_1] I recommend using a C-Style string containing the vowels, then using strchr to search it: const char vowels[] = “aeiou”; const size_t length = strlen(cString); unsigned int vowel_count = 0; for (unsigned int i = 0; i < length; ++i) { if (strchr(vowels, cString[i]) != NULL) { ++vowel_count; } } There are other methods, … Read more
[ad_1] Something like as follows. Hope that its understandable. Output:https://www.ideone.com/EnP40j #include <iostream> #include <iomanip> #include <cmath> int main() { float num1 = 95.345f; float num2 = 95.344f; num1 = roundf(num1 * 100) / 100; //rounding two decimals num2 = roundf(num2 * 100) / 100; //rounding two decimals std::cout << std::setprecision(2) << std::fixed << num1 << … Read more
[ad_1] There is no standard deviation function C++, so you’d need to do write all the necessary functions yourself — Generate random numbers and calculate the standard deviation. double stDev(const vector<double>& data) { double mean = std::accumulate(data.begin(), data.end(), 0.0) / data.size(); double sqSum = std::inner_product(data.begin(), data.end(), data.begin(), 0.0); return std::sqrt(sqSum / data.size() – mean * … Read more
[ad_1] The problem is that you’re acting like each character is the number it looks like. But ASCII 0 is not int 0. You might want something like this: selected[i] = number[j] – ‘0’; /* convert ASCII to int */ 1 [ad_2] solved Maximum product of 13 adjacent digits – Project Euler
[ad_1] From the NSUserDefaults Class Reference: A default object must be a property list, that is, an instance of (or for collections a combination of instances of): NSData, NSString, NSNumber, NSDate, NSArray, or NSDictionary. If you want to store any other type of object, you should typically archive it to create an instance of NSData. … Read more
[ad_1] It is a nuisance when we have to create an MCVE from fragments of a program. However, it’s doable — it’s a pain, but doable. Here’s my variation on your code. Of the 115 lines shown, 35 are what you wrote in the question — roughly. So, I had to create twice as much … Read more
[ad_1] A Linked List is a data structured used for collecting a sequence of objects. The “Head” is the very first item in the sequence. The “Tail” is the last object in the sequence. Each item in the linked list (a node) will have a property called Next (and Previous if it is doubly linked) … Read more