[ad_1] First – find out how to run this code under a debugger. Then it’ll just stop on the line where the segfault occurs, which should make it more-obvious what the problem is. Given that you’re saying “segfault”, it’s probably safe to assume you’re running some unix-variant, in which case, “gdb” is probably your debugger. … Read more
[ad_1] Your pop function destroys the entire stack. It deletes the tmp node (by calling the Stack destructor), which still points to the new next. And since the Stack destructor calls delete on next, you get a mess of multiple destructor calls on the same objects. JMA beat me to it by a few seconds, … Read more
[ad_1] This is a subjective question. Personally I would tend to agree that having class here at all is poor form, and typename should have been the only keyword allowed. But that’s just my opinion. Perhaps this usage of class will be deprecated in the future; perhaps there are sufficient people who like to write … Read more
[ad_1] I think the issue is that you have an extra space after the inserted text in the SQL. This means that you are effectively searching for “lblheader.text ” (with a space after it) everytime, which I doubt is what you want. In the SQL statement , change LIKE ‘%”+ lblheader.Text +” %’ “; To … Read more
[ad_1] vector: There are vectors in functional languages too, like this package unordered_set – Unordered/ordered refers to the underlying implementation; how the elements are actually stored. vector.cend – cend is a constant iterator pointing to the end. Constant iterators don’t let you modify the value pointed to by the iterator. emplace – Emplace is like … Read more
[ad_1] unsigned long long a; // bits 1 and 2 assuming 0 indexed int first = static_cast<int>((a & (3ULL<<1))>>1); // bits 3 and 5 assuming 0 indexed int second = static_cast<int>((a & (3ULL << 3)) >> 3); // bits 6 and 7 assuming 0 indexed int third = static_cast<int>((a & (3ULL << 5)) >> 5); … Read more
[ad_1] The value is passed by value to the Add method; however, if you pass a reference type (a class is always a reference type), then the value itself is a reference. So the question is not so much whether the value is passed by value or by reference, but if the type is a … Read more
[ad_1] Try this: void bubble_sort(int m, int a[100000]) { int i, ok = 0, v, n = m; while ( !ok ) { ok = 1; for ( i=0; i < m-1; ++i ) { if ( *(a+i) > *(a+i+1) ) { v = *(a+i); *(a+i) = *(a+i+1); *(a+i+1) = v; ok = 0; } … Read more
[ad_1] You should know that the easiest way to get information about the C standard library is by using manual pages on a Linux/UNIX system. Manual chapter 3 is where you’ll find manual pages regarding the standard library. To get documentation for rand, type man 3 rand at a shell prompt. In case you don’t … Read more
[ad_1] Nay sayers and doom mongers, behold! using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Security.Cryptography; using System.IO; using System.Web; namespace EncryptData { class EncryptData { private static readonly Encoding ASCII_ENCODING = new System.Text.ASCIIEncoding(); private static string md5(string text) { return BitConverter.ToString(new MD5CryptoServiceProvider().ComputeHash(ASCII_ENCODING.GetBytes(text))).Replace(“-“, “”).ToLower(); } public abstract string nonce(); public abstract string salt(); public … Read more
[ad_1] First of all, they all have undefined behavior for the same reason: They will read a number of characters you can’t know in advance, but through your pointer, you provide storage where to store this data, and this storage has some fixed size. Therefore, there are always inputs possible that will overflow your buffer. … Read more
[ad_1] Technically, no. But why are you using htons? It changes the endianess of a 16 bit datum to big-endian (that is, network byte order). First is your variable not 16 bit but 32 bit, so uint16_t acc = 0xBBD1 would be more appropriate. Second, as your on a little-endian machine, the bytes are exchanged, … Read more
[ad_1] I thought ternary operators were some kind of eye-candy. This really reminds me of some sort of eye-cancer (no offense). Better solution (with any count of variables) If I’m right you want to extract the second greatest number from a, b, c and d and save it in k. Try this: int compare_int(const void* … Read more
[ad_1] You could try using ternary operators. It makes the readability of your code more difficult (my opinion, but some people like it), but you put everything inside your for statement. For the numbers that can be divided by 3, for instance: for (int i = 1; i < N; i = (((i+1)%3 == 0) … Read more
[ad_1] The open() system call returns a file descriptor, which may not be 1, so your termination condition, while(infile==1){ is compeletely bogus. You should test if the read() call read any input (the return value is the number of bytes read, which is zero when it hit end-of-file.) Please read the read man page… pun … Read more