[Solved] Can someone explain this? [C++]

[ad_1] operator>> have only 2 operands and return value, so when you write: std::cin >> v1 >> v2 it means: result = std::cin >> v1 result >> v2 here other example: a + b + c is result = a + b result + c 4 [ad_2] solved Can someone explain this? [C++]

[Solved] error: ‘Board::Board’ names the constructor, not the type Board::Board; C++ [closed]

[ad_1] In C++, methods and functions have the following syntax: <return-type> <class-name> :: <method-name> ( <arguments> ) { <statements> } Constructors don’t have a return type. Other than that, how does your function definition match the syntax or does it? Hint: Board::Board() { } Note: C++ is picky about its symbol characters. The ( is … Read more

[Solved] Implementing with quadratic probing [closed]

[ad_1] With this code you are doing linear probing index = hash(entry.key); while (!is_vacant(index)) index = next_index(index); template <class RecordType> inline std::size_t table<RecordType>::next_index(std::size_t index) const // Library facilities used: cstdlib { return ((index+1) % CAPACITY); } Say your map is nearly full and hash returns 23, then the next slots you are going to test … Read more

[Solved] What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ?

[ad_1] What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ? [ad_2] solved What is the difference between char *exp=”a+b” and char exp[]=”a+b”? Are they stored the same way in memory or they differ?

[Solved] C’s strange pointer arithmetics [closed]

[ad_1] As pointed out by others, this statement suffers from undefined behavior: *(&x+5) += 7; Memory address &x+5 is outside the bounds of variable x. Writing to that address is a very bad idea. OP’s code sample exploits certain C compiler implementation details. Probably educational; it can be used to demonstrate how hackers can exploit … Read more

[Solved] How a fread function work? [closed]

[ad_1] To print all bytes in an int? Remember that an int is 32-bit, which is four bytes. Reading it into a char buffer makes it easier to access those four bytes in the int. Edit: Little explanation of the int type… Lets say you have an int: int someIntValue = 0x12345678; This is stored … Read more

[Solved] C read file in byte chunks [closed]

[ad_1] Well if you can’t use man, why not just search for it? Anyway you are using it wrong. If you want to read it by chunks you should do it like this // consider that we allocated enough memory for buffer // and buffer is byte array ssize_t r = 0, i = 0; … Read more