[Solved] Overlay appear above a button

Sorry for being so general on my question. The following is some code I did to get a positive result: <html> <head> <META HTTP-EQUIV=”EXPIRES” CONTENT=”-1″ /> <script type=”text/javascript”> function setVisibility(id) { if(document.getElementById(‘bt1′).value==’Hide Layer’){ document.getElementById(‘bt1’).value=”Show Layer”; document.getElementById(id).style.display = ‘none’; }else{ document.getElementById(‘bt1’).value=”Hide Layer”; document.getElementById(id).style.display = ‘inline’; } } </script> <style type=”text/css”> #container { width:1px; height:1px; position: relative; … Read more

[Solved] How can i create an new activity on imagebutton click? [closed]

Try this, ImageButton mainButton = (ImageButton) findViewById(R.id.mainButton); mainButton.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { Intent intent=new intent(this,NewActivityname.class); startActivity(intent); } });} Add your newactivity class in androidmanifest file solved How can i create an new activity on imagebutton click? [closed]

[Solved] How to merge two buttons into one?

Instead of merging the two buttons, the same could be performed using JSX callback. See solution on the other posting at Conditional disabling of button The undefined return came from the callback. It needs to be bound before (in this case) passing to the button. See some of the other approaches suggested: How to use … Read more

[Solved] Follow Button issue [closed]

The “follow” button is meant to be used for personal accounts, e.g. to follow status updates of a user on Facebook. What I think you are looking for is the “Like” button, which is meant to allow people to show their interest in a page, which is what your site on Facebook is. An example … Read more

[Solved] disable buttons permanently throughout the aplication in android

define the behavior in SharePreferences: for example use this in onResume: SharedPreferences pref = PreferenceManager.getDefaultSharedPreferences(context); boolean enabled = pref.getBoolean(“isEnabled”,true); myButton.setEnabled(enabled); in onClick event of the button do this: SharedPreferences pref = PreferenceManager.getDefaultSharedPreferences(context); pref.edit().putBoolean(“isEnabled”,false).commit(); myButton.setEnabled(false); 2 solved disable buttons permanently throughout the aplication in android

[Solved] Error PHP Twitter share [closed]

You either need to escape all of the single quotes in that string or don’t use PHP to output that code (recommended): <?php //some php code ?> <a href=”https://twitter.com/share” class=”twitter-share-button” data-via=”User” data-size=”large”>Tweet</a> <script>!function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0],p=/^http:/.test(d.location)?”http’:’https’;if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src=p+’://platform.twitter.com/widgets.js’;fjs.parentNode.insertBefore(js,fjs);}}(document, ‘script’, ‘twitter-wjs’);</script> <?php // more PHP code ?> Escaped quotes: <?php echo ‘<a href=”https://twitter.com/share” class=”twitter-share-button” data-via=”User” data-size=”large”>Tweet</a> <script>!function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0],p=/^http:/.test(d.location)?\’http\’:\’https\’;if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src=p+\’://platform.twitter.com/widgets.js\’;fjs.parentNode.insertBefore(js,fjs);}}(document, \’script\’, \’twitter-wjs\’);</script>’; … Read more

[Solved] Click the button and it sends that info into another box on the page [closed]

Using html, css and jQuery you can get your desired output. Please check below code. function getHtml() { var test = $(“#input”).text(); $(“#output”).show(); $(“#remove”).show(); $(“#output”).text(test); } function remove() { $(“#output”).hide(); $(“#remove”).hide(); } #output { display: none; } #remove { display: none; } <script src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js”></script> <div id=”input”> Input: welcome </div> <button onClick=”getHtml()”>Click</button> <div id=”output”> </div> <button … Read more

[Solved] Calling a function and text box from a button

You probably don’t want to return an exception from that method. It could use a void return type instead. For example: private void button1_Click(object sender, EventArgs e) { Student student = new Student();//set up student obj… string city = “Foo”; searchCity(student, city); } public void searchCity(Student student, string searchCity) { //Do your search… //set the … Read more

[Solved] How disable a button if there is no text in multiple textboxes in VB?

Change all of your “And” in your if statement to “Or” Private Sub BtnStart_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BtnStart.Click If TxtBox1.Text = “” Or TxtBox2.Text = “” Or TxtBox3.Text = “” Or TxtBox4.Text = “” Or TxtBox5.Text = “” Or TxtBox6.Text = “” Or TxtBox7.Text = “” Or TxtBox8.Text = “” … Read more

[Solved] Trigger callback after clicking N times

Without jQuery: document.addEventListener(“DOMContentLoaded”, function(event) { var button = document.getElementById(‘click_me’); var elem = document.getElementById(‘message’); var count = 0; button.addEventListener(‘click’, function(e) { e.preventDefault(); count++; if(count == 5){ elem.style.display = ‘block’; } }, false); }); #message { background: #0f0; display: none; padding: 10px; } <button type=”button” id=”click_me”>Click Me</button> <div id=”message”>Hello World</div> With jQuery: $(function() { var count = … Read more

[Solved] Button to show previous string

create a new member for your Activity like: int actual = 0; Then create a ‘next’ button: nextButton = (Button) findViewById(…); nextButton.setOnClickListener(new OnClickListener() { @Override public void onClick(View arg0) { actual = actual < countires.length – 1 ? actual + 1 : actual; String country = countires[actual]; btn1.setText(country); } }); Same goes for the previous … Read more

[Solved] the inner java script is override the css property on this html code

function myFunction(){ document.getElementById(“bad”).style.display=”block”; } #good{ width: 100%; height: 100%; } #bad{ position:absolute; width: 15%; height: 100%; background-color: #023b3b; top:0%; display: none; } #vahid{ float: left; width: 7%; height: 100%; background-color: #023b3b; } #isnani{ float: left; width: 93%; height: 100%; background-color: bisque; } #one { display:block; background-color: #023b3b; /* width:60px; height: 867px;*/ } #boom{ margin-top: 30%; … Read more

[Solved] How to destroy widgets?

Try this: import tkinter as tk root = tk.Tk() root.geometry(“500×300+10+13”) root.title(“Test”) b = tk.Button(root, text=”click me”) def onclick(evt): w = evt.widget w.destroy() b.bind(“<Button-1>”, onclick) b.pack() root.mainloop() 13 solved How to destroy widgets?