arrays

[Solved] Java program. How do I loop my “isLucky” method through my array? Also, how do I print my results correctly in the main method?

by

Your compiler error, ‘else’ without ‘if’ is because you have something like this: if(isOkay) doSomething(); andThenDoSomethingElse(); else doAnotherThing(); andEvenSomethingElse(); And you must put each block in curly braces, like this: if(isOkay) { doSomething(); andThenDoSomethingElse(); } else { doAnotherThing(); andEvenSomethingElse(); } I strongly recommend using curly braces in all ifs (and whiles and fors and everything … Read more

[Solved] Alphabetically sorting the words

by

This statement if(words[j+1].(int)name[0]<words[j].(int)name[0]){ is syntactically invalid. The correct statement will look the following way if( ( int )words[j+1].name[0]<( int )words[j].name[0]){ However there is no any sense to make such a record because (the C++ Standard) The usual arithmetic conversions are performed on operands of arithmetic or enumeration type On the other hand if type char … Read more

[Solved] Output contents of array in reverse in Java [closed]

by

I’m not completely sure what you are looking for. Could you specify a bit more? I’m completing your code to match the provided output anyway: import java.util.Scanner; public class Activity7 { public static void main(String[] args) { Scanner keyboard = new Scanner(System.in); System.out.println(“How many numbers?”); int quantityOfNumbers = keyboard.nextInt(); int[] numbers = new int[20]; //making … Read more

[Solved] Sorting the array using keys [closed]

by

Two things are important here. You need to preserve the key to value relationship. That implies that you use array sorting functions like uasort() instead of usort(). The next thing is, that you have to use a user-defined sorting function, which expresses your sorting algo. It describes how you want to sort your routes. It’s … Read more

[Solved] How to store array in table split by array_chunk in php? [closed]

by

You need to change your foreach to this to allow for the creation of new Model instance for each record set. foreach ($matches as $value) { $share_holder_info = new ShareHolderInfo(); $share_holder_info->trad_id = $rand_id; $share_holder_info->name = $value[0]; $share_holder_info->address = $value[1]; $share_holder_info->shares = $value[2]; $share_holder_info->save(); } You will need to change it to what ever your actual … Read more

[Solved] How do I make a string a string array?

by

String text = “The Three Pigs”; String[] array = text.split(” “); EDIT: If you want to let the user to enter a line of text rather than a single word, then use: String O = S.nextLine(); instead of: String O = S.next(); 3 solved How do I make a string a string array?

[Solved] I want to print only the repeated values once from an associative array

by

Use filter and map, with a Set to remove the repeated values: var employee=[{“firstName”:”Zahir”,”lastName”:”Alam”,”Age”:25,”Company”:”Switchme”,”Role”:”Developer”,”Department”:”Tech”,”Head”:{“Id”:3,”Name”:”Sourasis Roy”}},{“firstName”:”Amith”,”lastName”:”Manniken”,”Age”:25,”Company”:”Switchme”,”Role”:”Developer”,”Department”:”Tech”,”Head”:{“Id”:3,”Name”:”Sourasis Roy”}},{“firstName”:”Sourasis”,”lastName”:”Roy”,”Age”:28,”Company”:”Switchme”,”Role”:”CTO”},{“firstName”:”Aditya”,”lastName”:”Mishra”,”Age”:29,”Company”:”Switchme”,”Department”:”Tech”,”Role”:”CEO”},{“firstName”:”Priti”,”lastName”:”Lata”,”Age”:24,”Company”:”Switchme”,”Role”:”HR”},{“firstName”:”Sumita”,”lastName”:”Nath”,”Age”:24,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”},{“firstName”:”Tarini”,”lastName”:”Khanna”,”Age”:22,”Company”:”Switchme”,”Role”:”Content Writer”},{“firstName”:”Abhisek”,”lastName”:”Soni”,”Age”:23,”Company”:”Switchme”,”Role”:”HLA”,”Department”:”Crm”,”Head”:{“Id”:5,”Name”:”Sumita Nath”}},{“firstName”:”Ankit”,”lastName”:”Pump”,”Age”:23,”Company”:”Switchme”,”Role”:”HLA”,”Department”:”Crm”,”Head”:{“Id”:5,”Name”:”Sumita Nath”}},{“firstName”:”Pogo”,”lastName”:”Laal”,”Age”:23,”Company”:”Switchme”,”Role”:”Designer”},{“firstName”:”Sabina”,”lastName”:”Sekh”,”Age”:28,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”},{“firstName”:”Sanjay”,”lastName”:”Poudal”,”Age”:24,”Company”:”Switchme”,”Role”:”HLA Head”,”Department”:”Crm”,”Head”:{“Id”:10,”Name”:”Sabina Sekh”}}]; var repeated = […new Set(employee.map(({ Department }) => Department).filter(Boolean))]; $(“div.all”).text(repeated.join(“, “)); <script src=”https://code.jquery.com/jquery-3.3.1.js”></script> <h3>2. List out all department name </h3> <div class=”all”></div> 7 solved I want to print only the repeated values … Read more

[Solved] If linked lists have many functional advantages over arrays, what advantages do arrays have over linked lists? [closed]

by

Because there is no free lunch. In general, if a data structure is more powerful than another, you will have to pay for that additional power somehow. Sometimes you will not be willing to pay that price. As for lists, you are correct, in terms of functionality, they are way better than arrays: You can … Read more

[Solved] Android : parse a JSONArray

by

Here is your code to parse data, private void parseData(){ try { JSONArray jsonArray=new JSONArray(response); JSONObject jsonObject=jsonArray.getJSONObject(0); JSONArray jsonArrayNid=jsonObject.getJSONArray(“nid”); JSONArray jsonArrayUid=jsonObject.getJSONArray(“uid”); JSONArray jsonArrayField_image=jsonObject.getJSONArray(“field_image”); for(int i=0;i<jsonArrayNid.length();i++){ JSONObject jsonObjectNid=jsonArrayNid.getJSONObject(i); String value=jsonObjectNid.getString(“value”); //here you get your nid value } for(int i=0;i<jsonArrayUid.length();i++){ JSONObject jsonObjectUid=jsonArrayUid.getJSONObject(i); String target_id=jsonObjectUid.getString(“target_id”); //here you get your uid target_id value String url=jsonObjectUid.getString(“url”); //here you get your … Read more