An attacker cannot “escape” a PHP array, because the contents of the array are not executed as code. It may contain a string of PHP, but that string is not executed. What may be insecure is how your PHP code handles the user input later on. If you are outputting the data without sanitising it, … Read more
Even though this is a very specific problem, here’s a solution: var array1 = new[] { 2, 5, 7, 8, 9, 4 }; var array2 = new [] { 4, 8, 2, 1, 5, 8 }; array1 = array1.Select((i, index) => i % 2 == 1 ? array2[index] : i).ToArray(); //result: int[6] { 2, 8, … Read more
You are passing the arrays to sameNumberCheckOfTwoArrays as pointers. In this process, the “array-ness” is dropped. Your function only sees an int* and reports the size accordingly. 3 solved Something went wrong with passing pointer to a function
As 4castle suggest, you should really have a custom class – which looking at the properties you are interested in, you might want to name “CallLogEntry” and then have properties for this class. Here is an example of such a custom class. public class CallLogEntry { String number; String type; String date; String duration; //this … Read more
Should really be trying this yourself mate, but this should help: $arr = array( 1=>’xyz’, 2=>’abc’, 3=>’pqr’ ); $MultiArr = array(); $i = 0; foreach($arr as $ID=>$Name){ $MultiArr[$i][‘id’] = $ID; $MultiArr[$i][‘name’] = $Name; $i++; } print_r($MultiArr); 3 solved create multidimetional array associative array
What you are looking for is called Recursion. Below is a recursive function that calls itself if the value of the array key is also an array. function printArrayList($array) { echo “<ul>”; foreach($array as $k => $v) { if (is_array($v)) { echo “<li>” . $k . “</li>”; printArrayList($v); continue; } echo “<li>” . $v . … Read more
Shift all the items from the midpoint to the right, and then add the midpoint. If i were you i’d iterate in reverse. for (int i = array.length – 1; i > midpoint; i–) { array[i] = array[i-1]; } array[midpoint] = somenumber solved Adding a number to midpoint af an array [closed]
This works for me. public class PersonService { protected int lastItemInPersonArray = 0; private Person[] persons = new Person[100]; public void addPersonToPersonArray(Person personToAdd) { persons[lastItemInPersonArray++] = personToAdd; } public static void main(String[] args) { PersonService ps = new PersonService(); ps.addPersonToPersonArray(new Person(“P 1”)); ps.addPersonToPersonArray(new Person(“P 2”)); ps.addPersonToPersonArray(new Person(“P 3”)); System.out.println(ps.persons[0].nome); System.out.println(ps.persons[1].nome); System.out.println(ps.persons[2].nome); } } class Person{ … Read more
While this question is poorly worded, I think I understand what you are asking for. Here’s what you should do. I am not all that fluent in php so please make sure that you look over the code snippets that I write instead of copy/pasting them. Find the maximum X and Y values. Instantiate and … Read more
function yymmddToString(yymmdd) { var months = [‘January’, ‘February’, ‘March’, ‘April’ …..]; var x = yymmdd.split(‘-‘); return months[parseInt(x[1], 10)] + ‘ ‘ + x[0]; } var result = data1.reduce(function(result, datum) { var x = result[datum.name] = result[datum.name] || {}; x[yymmddToString(datum.time)] = datum.value; return result; }, {}); 6 solved Converting an array object to another object-Part 2 … Read more
Similar to previous answer but with the following suggestions Initialize longest and shortest. Ignore case when comparing. Could still do this with SequenceEqual instead of comparing strings. May not be needed if you know you won’t be comparing Anna to annA. When checking if you found the shortest you need to remember that shortest.Length with … Read more
The easiest way to get the result you expect is in my opinion this way: $data = array( array( ‘domain’ => ‘messages’, ‘key’ => ‘test.testik’, ‘message’ => array() ), array( ‘domain’ => ‘messages’, ‘key’ => ‘test2313.tes31231tik’, ‘message’ => array() ), array( ‘domain’ => ‘validators’, ‘key’ => ‘valid.validik’, ‘message’ => array() ), array( ‘domain’ => ‘validators’, … Read more
You could create recursive function with for…in loop and first calculate total sum and total number of nodes and then use those 2 values to calculate average. var graph_structure = {“val”:74,”child”:[{“val”:17,”child”:[{“val”:34,”child”:[{“val”:34,”child”:[{“val”:65,”child”:[{“val”:28,”child”:[{“val”:85},{“val”:30,”child”:[{“val”:68},{“val”:10,”child”:[{“val”:100,”child”:[{“val”:21,”child”:[{“val”:21},{“val”:64}]},{“val”:86}]}]}]}]}]},{“val”:22,”child”:[{“val”:17,”child”:[{“val”:65}]}]}]},{“val”:53,”child”:[{“val”:3,”child”:[{“val”:98,”child”:[{“val”:90,”child”:[{“val”:76,”child”:[{“val”:87,”child”:[{“val”:52,”child”:[{“val”:56}]}]},{“val”:47},{“val”:40,”child”:[{“val”:80,”child”:[{“val”:34}]},{“val”:23,”child”:[{“val”:47},{“val”:92}]},{“val”:98,”child”:[{“val”:89},{“val”:16},{“val”:10}]}]}]}]},{“val”:35,”child”:[{“val”:89,”child”:[{“val”:76,”child”:[{“val”:50,”child”:[{“val”:51},{“val”:90}]},{“val”:69,”child”:[{“val”:93},{“val”:98},{“val”:62}]}]}]}]}]}]}]}]}]},{“val”:98,”child”:[{“val”:85},{“val”:85,”child”:[{“val”:58,”child”:[{“val”:81,”child”:[{“val”:36,”child”:[{“val”:45,”child”:[{“val”:96,”child”:[{“val”:15,”child”:[{“val”:11,”child”:[{“val”:96}]}]},{“val”:48,”child”:[{“val”:4,”child”:[{“val”:74},{“val”:1}]},{“val”:7}]}]},{“val”:84,”child”:[{“val”:9},{“val”:81,”child”:[{“val”:10,”child”:[{“val”:67}]}]}]}]},{“val”:85,”child”:[{“val”:53},{“val”:7,”child”:[{“val”:47,”child”:[{“val”:74,”child”:[{“val”:30},{“val”:7},{“val”:12}]},{“val”:22}]},{“val”:56,”child”:[{“val”:51,”child”:[{“val”:45}]},{“val”:54,”child”:[{“val”:20},{“val”:62}]}]}]}]}]}]}]},{“val”:62,”child”:[{“val”:36,”child”:[{“val”:39,”child”:[{“val”:20}]},{“val”:10,”child”:[{“val”:91,”child”:[{“val”:81,”child”:[{“val”:59,”child”:[{“val”:19,”child”:[{“val”:59},{“val”:16}]},{“val”:35,”child”:[{“val”:30}]},{“val”:6,”child”:[{“val”:27}]}]},{“val”:89,”child”:[{“val”:60,”child”:[{“val”:59}]}]}]}]}]}]}]}]}]},{“val”:8,”child”:[{“val”:56,”child”:[{“val”:55,”child”:[{“val”:41,”child”:[{“val”:17,”child”:[{“val”:15,”child”:[{“val”:40,”child”:[{“val”:55,”child”:[{“val”:50},{“val”:99,”child”:[{“val”:86},{“val”:90}]}]}]},{“val”:85,”child”:[{“val”:36,”child”:[{“val”:39,”child”:[{“val”:45}]}]}]},{“val”:78,”child”:[{“val”:24,”child”:[{“val”:93,”child”:[{“val”:8}]},{“val”:26,”child”:[{“val”:5}]}]},{“val”:36}]}]},{“val”:13}]}]},{“val”:10,”child”:[{“val”:0,”child”:[{“val”:77,”child”:[{“val”:46,”child”:[{“val”:72,”child”:[{“val”:17,”child”:[{“val”:10},{“val”:67}]},{“val”:48},{“val”:60}]},{“val”:98,”child”:[{“val”:12,”child”:[{“val”:61},{“val”:27}]}]}]}]}]}]}]}]}]}]} function calc(data) { return (function repeat(data, res) { for(let i in data) { if(data.val) { res.nodes++; res.total += data.val if(!res.min) res.min = data else … Read more
To echo: echo $_POST[‘events’][0]; To assign it to a variable: $eventid = $_POST[‘events’][0]; To assign the array to a variable and get the value from the new array: $events = $_POST[‘events’]; $eventid = $events[0]; [0] represents the key of the first value since it is set to be 0. 4 solved How to get value … Read more
This is not the proper way, but you can do something like this, ArrayList<Object> objects = new ArrayList<>(); objects.add(1); objects.add(“asd”); The better way is to create a different class with the attributes with Strings and int values you want. Then create an array with the type of that class and add those objects to the … Read more