Instead of forEach, use map. The map() method creates a new array with the results of calling a provided function on every element in this array. return array.map(logArrayElements); 0 solved Produce an ordered HTML list using JavaScript
just add a test : String firstWords = “”; if(splitVideoTitle.length>1){ firstWords = splitVideoTitle[0] + ” ” + splitVideoTitle[1]; } else firstWords=splitVideoTitle[0]; 0 solved Splitting a string caused ArrayIndexOutOfBoundsException [duplicate]
claim is not an array, but another object. If you want it to be an array, it should be something like this: “claim”: [ “date”: “2015-08-06”, “comments”: “Some comments” ] (notice the [ ] instead of { }) If it’s meant to be an object, then the code should read: JSONObject claims = c.getJSONObject(TAG_CLAIM); 4 … Read more
In your conditional statement, you’re assigning space to s[ i ] (operator =). You want to compare them (operator ==). Try if (s[ i ] == ‘ ‘) s[ i ] = ‘ ‘ is always true because the result of an assignment is the value assigned (space). This value is implicitly converted to a … Read more
a[i] = Double.toString(a[i]); The left-hand side, a[i], is a variable of type double. The right-hand side, Double.toString(a[i]), is a value of type String. So you’re trying to assign a String to a variable of type double, hence the error: you can’t store a String in a variable of type double, because a String is not … Read more
Here is the simplest version using your original line of thoughts Implementing a range function can be more complex than this, but since this works, I suggest it for now function buildArray(a, b) { var arr = []; for (var i = a; i <= b; i++) { arr.push(i); } return arr; } console.log(buildArray(5, 10)); … Read more
There is a huge mess there, you need to get used to pointers! Ok so your function gets g and p which are int *. What you give them is &g and &p, where g and p are also int *. So you pass to your function type int **. Also g[i+3] is *(g+i+3) so … Read more
If I understand your question correctly, this should do the trick. arr = [] for z in np.arange(0, 0.5, 0.01): Q = a + z t = b + z # here I would like to store Q and t in an array arr.append([t,Q]) for item in arr: i = item[0] j = item[1] It … Read more
There is a problem in this line: double v[k] = log(log(sqrt(e[k]+1)+1)+1); in the first iteration k == 0 so you are trying to declare a zero sized array. I dont understand the code enough to tell you how to fix it, but a zero sized array is definitely not what you want in that place. … Read more
use JSON_ENCODE first before saving the array to DB ,then use JSON_DECODE if you want to get again the contents $arr = array( “item_number1” => “1”, “payment_date” => “04:21:34 Dec 06, 2014 PST”, “payment_status” => “Completed”, “first_name” => “sdfsd”, “last_name” => “parsdfsdandekar”, “quantity1” => “1” ); echo json_encode($arr); Result after JSON_ENCODE (Array to JSON String): … Read more
If your first two arrays has the same length, you can use a loop to get the array you want: <?PHP $arr1= array(“A”,”B”,”C”); $arr2= array(“1″,”2″,”3″); $arr3=[]; for($i = 0; $i < count($arr1); $i++) array_push($arr3, $arr1[$i], $arr2[$i]); ?> It will return: $arr3= array(“A”,”1″,”B”,”2″,”C”,”3″); 1 solved Combine PHP array as something [duplicate]
I would first start with sorting the list using b_sorted=sorted(b) solved Finding smaller numbers in an array
array is not out of bound Correct. The program has undefined behavior for another reason. I assume you are confused about this part: arr[1, 2] The 1,2 is comma seperated expressions, i.e. 1 and 2. The rule of the comma operator is that the result is the result of of the right operand. So 1,2 … Read more
value is an array of integer, it can’t be zero. Any element in the array could be zero. If you are trying to determine if the array is null, then you could change the check to be: if (value == null) { Environment.Exit(1); } 1 solved Define if statement for property in C# [closed]
Simple solution with two map() operations: const data = [{ “week”: 1, “lost”: 10, “recovery_timespan”: [{ “week”: 2, “count”: 1 }, { “week”: 3, “count”: 0 }] }, { “week”: 2, “lost”: 7, “recovery_timespan”: [{ “week”: 3, “count”: 1 }, { “week”: 4, “count”: 3 }] }, { “week”: 3, “lost”: 8, “recovery_timespan”: [{ “week”: … Read more