you will require 2 loops, 1 will go through each element of Array3 and Second loop will be used to find the index value will be compared with Array2 to find index of Array 1 and then that index value will be saved in Array4 from Array1 for (var i = 0; i < Array3.length; … Read more
You don’t need to wait or something as the method shuffle is synchronous , which means next line will run after it finishes shuffling var arr = [“1″,”2″,”3”] arr.shuffle() print(arr) // [“2”, “1”, “3”] solved check when the array has finished shuffling to do some operation
You can try using list comprehensions with a combination of joining and splitting: your_list = [[int(j) for j in i.split()] for i in ‘ ‘.join(data).split(‘<>’)] 6 solved breaking a list in to lists in python?
Replace $list_per[$item] = $nama; With $list_per[$nama[‘id_perusahaan’]] = $nama[‘name_perusahaan’]; 0 solved How to change this array key based on this mysql result
String[] strarray = new String[0]; will create empty array. You need change to String[] strarray = new String[1]; or add strarray.length > 0 to if condition if (strarray.length > 0 && strarray[0].isEmpty()) to prevent array out of bounds exception Update: it throw null pointer exception if you did init array. String[] strarray = new String[1]; … Read more
This is mostly syntax errors. If you want to declare an array, you either use array() or the shorthand []: $Config[‘URL’] = array( ‘Default’ => array( ‘Require.www’ => false, // www.example.com ‘SSL.enabled’ => true, // https:// ‘Server’ => ‘***’, // public server ‘Lang’ => ‘en_US’ // GLOBAL. ) , ‘Other’ => ” //’example.com’ => [‘Require.www’ … Read more
Use the following code. const number = [“1”, “2”, “3”]; const name = [“car”, “airplane”, “train”]; const animal = [“dog”, “cat”, “hamster”]; for (var i=0; i < number.length; i++) { document.write ( number[i] + ” ” + name[i] + ” ” + ” ” + animal[i] + “<br />” ) } solved How to show … Read more
You can simply get the data by key: data.performance.fundBtcArr ,data.performance.fundUsdArr,data.performance.btcUsdArr var data={“performance”: {“datesArr”: [“2018-04-30”, “2018-05-07”, “2018-05-14”, “2018-05-21”, “2018-05-28”, “2018-06-04”, “2018-06-11”, “2018-06-18”, “2018-06-25”, “2018-07-02”, “2018-07-09”], “fundBtcArr”: [1, 0.956157566, 0.988963214, 0.992333066, 1.118842298, 1.064376568, 1.109733638, 1.082080679, 1.142624866, 1.1107828743809005, 1.0626307952408292], “fundUsdArr”: [1, 0.974710531, 0.944055086, 0.903073518, 0.869041365, 0.870284702, 0.815468401, 0.789070479, 0.777083258, 0.8027552300742684, 0.7766297878480255], “btcUsdArr”: [1, 1.019403669, 0.954590699, 0.910050818, 0.77673267, 0.81764737, … Read more
Just use a regular for loop to iterate over all arrays at once: String[] item ={“[1]hotdog”, “[2]eggpie”,”[3]menudo”,”[4]pizza”,”[5]lumpia”}; int[] cost = {5, 10, 15, 20, 25}; int[] selling = {10,15,20,25,30,}; int[] qty = {2,4,6,8,10}; for (int i = 0; i < item.length; i++) { System.out.println(” ” +item[i]+”\t”+cost[i]+”\t\t”+selling[i]+”\t\t”+qty[i]); } I would recommend putting all of these fields … Read more
The string you have mentioned is a JSON string. JSON (JavaScript Object Notation) is a lightweight data-interchange format. It is easy for humans to read and write. It is easy for machines to parse and generate. It is based on a subset of the JavaScript Programming Language, Standard ECMA-262 3rd Edition – December 1999. JSON … Read more
An external frame means that you have to add two rows/columns each (left and right/ upper and lower), so you need to increase the size of your new matrix by an additional row and column. The loops for setting the frame to 0 were fine. At the last inner loop you set the reduced size … Read more
Can anyone show me an algorithm to create a function that returns all possible partitions of an array into n subsets while maintaining order of array? solved Can anyone show me an algorithm to create a function that returns all possible partitions of an array into n subsets while maintaining order of array?
Have to copy contents of array into another array in order to compare otherwise you end up refering to same array. import java.util.Arrays; public class Test { public static void main(String[] args) { int[] sizebefore = { 3, 5, 1, 8 }; int[] sizeafter = new int[sizebefore.length]; System.arraycopy(sizebefore, 0, sizeafter, 0, sizebefore.length); Arrays.sort(sizeafter); System.out.println(“your array … Read more
You can use the function reduce. This alternative stores the previous emails to increment the count. var array = [{ “_id”: “5aaa4f8cd0ccf521304dc6bd”, “email”: “[email protected]” }, { “_id”: “5aaa50a0ac40d32404c8bab7”, “email”: “[email protected]”, }, { “_id”: “5aa8ace3323eeb001414a2c5”, “email”: “[email protected]” }, { “_id”: “5aa86645323eeb001414a2af”, “email”: “[email protected]” }, { “_id”: “5aa92c7d66c8820014813ed8”, “email”: “[email protected]” }]; var count = array.reduce((a, c) => … Read more
Because there is no value set in int a,b, int ArrayA[a][b] doesn’t do whatever you expected it to do. Give a and b some value, like int a=2, b=2 or something, then it will work. 1 solved c++ Multidimensional array second row overwriting the first row