An array is a series of values with no defining keys: [‘one’, ‘two’, ‘three’] An object uses keys which have values which can be anything within the scope of the language. eg: boolean, integer, string, object, array or event functions: { one: { two: ‘three’ }, four: [‘five’, ‘six’], seven: ‘eight’, nine: 10, eleven: function … Read more
I suppose you intended this: function run{ Structure[0]() // <— notice the parentheses. } Without the parentheses, the function run does not do anything. It just references the function, without invoking it. solved Java Script function does not work [closed]
Just had to limit the inner loop to <9. The fixed code: for(int i=0;i<10;i++) //1st array, ascending { for(int j=0;j<9;j++) { if(array1[j]>array1[j+1]) { int temp=array1[j]; array1[j]=array1[j+1]; array1[j+1]=temp; } } } //Over for(int i=0;i<10;i++) //2nd array, descending { for(int j=0;j<9;j++) { if(array2[j]<array2[j+1]) { int temp=array2[j]; array2[j]=array2[j+1]; array2[j+1]=temp; } } } //Over Thank you guys! solved Sorting … Read more
If you do not care about destroying arr2, neither about having a deep copy of arr1[0], a simple unshift() can do that: const arr1 = [[1, 2, 3, 4], [5, 6, 7, 8]]; const arr2 = [[‘some1’, ‘some2’], [‘some3’, ‘some4’]]; arr2.unshift(arr1[0]); console.log(JSON.stringify(arr2)); Of course those are really some conditions which may not fit your case. … Read more
Assuming your ArrayList is this: List<String[]> arrayList = new ArrayList<>(); arrayList.add(new String[]{“R111″,”Red”,”50000″}); arrayList.add(new String[]{“R123″,”Blue”,”50000″}); you can do something like: for (Iterator<String[]> iterator = arrayList.iterator();iterator.hasNext();) { String[] stringArray = iterator.next(); if(“R111”.equals(stringArray[0])) { iterator.remove(); } } You can safely remove an element using iterator.remove() while iterating the ArrayList. Also see The collection Interface. An alternative shorter approach … Read more
You can use json to convert it to an array. class T require ‘json’ def array_detect(array_string) begin json = JSON.parse array_string if json.is_a? Array # is an array else # not an array end rescue JSON::ParserError => e puts e.message # not a valid json string end end end solved How to convert a string … Read more
“Better” is a subjective term. Some points to consider: Yes, if you had a Map or an object keyed by id for patients, beds, and departments, in general looking up patients, beds, and departments by id would be faster using that Map/object instead of a linear searches of those arrays. But, presuming that you need … Read more
Try this, I tested it and it works, you should use the remainder operator %: public class Array { public static void main(String[] args) { int[] arr = {2, 3, 5, 7, 11}; System.out.println(is235Array(arr)); } public static int is235Array(int[] a) { int countOne = 0; int countTwo = 0; for (int i : a) { … Read more
We can see this problem as an instance XOR-SAT problem, though it is more general than the problem posed here, that’s one way to go. Just to gain some intuition I provide a very simple example. Suppose you have systems of three switches and three bulbs like this: S B 1 1, 3 // toggles … Read more
You have the equal elements in array, when m=8 and l=6=>i=l: in first loop, i=6, condition is i<m, then the execution of next for loop starts and in the second for loop, till j=5<6 condition, there are no equal elements so codes continue with if(i==j){ //i =6, j =6 count++; } in the next execution … Read more
Visual Studio 2015 doesn’t support the C++17 standard. Prior to C++17 standard you can’t have the std::shared_ptr<T[]> pointer. But even in C++17 the std::make_shared function doesn’t support array types so you would have to use the boost::make_shared instead. Another alternative is to use the unique pointer in combination with the std::make_unique which does support the … Read more
Use Array.filter var clubs = [ {id: 1, name : ‘chelsea’}, {id: 2, name : ‘city’}, {id: 3, name : ‘liverpool’} ]; clubs = clubs.filter(function(item){ return item.id !== 2; }); console.log(clubs); 12 solved How can I remove a index in the array on the javascript?
Both will give the same result, but I’d choose the | always, because you are dealing with bits, not numbers. In order to understand why they are equivalent you first have to understand binary numbers and binary maths: var b = 0b0011; //binary 0011 Ok, lets do something similar to your code: var s = … Read more
you need to write service to check if current call is ended or not. after disconnection of one call you can dial next number from your array in onRecieve method of BroadcastReceiver. code to check call is disconnected or not. switch(state) { case TelephonyManager.CALL_STATE_IDLE: Log.d(“Call”,”Outgoing Call finished”); break; case TelephonyManager.CALL_STATE_OFFHOOK: Log.d(“Call”,”Outgoing Call Starting”); break; } … Read more
[ { ‘one’: ‘8b45544b-6d35c53c3d423’ }, { ‘two’: ‘5a509481-a43k4d40r4c44’ } ].map(o => Object.keys(o)[0]) 1 solved turn array with object to array [closed]