There are a few tricks you can use to speed this up. The nth triangle number is n*(n+1)/2. For all integers n, n and n+1 are co-prime. This means that the number of divisors of n*(n+1) is the number of divisors n multiplied by the number of divisors of n+1. For an even number k, … Read more
This is not going to be the fastest data structure & algorithm for your particular purpose I guess, but it may be fast enough. Test it yourself. Note that a std::forward_list or even a std::vector might be faster depending on the actual scenario (-> constant factors in big-O-notation). tmyklebu mentioned another approach in the comments: … Read more
This is a compact version by using a closure for the sorted character array. var array = [‘car’, ‘incl’, ‘arc’, ‘linc’, ‘rca’, ‘icnl’, ‘meta’, ‘tame’], result = Object.values( array.reduce( (r, s) => (a => ((r[a] = r[a] || []).push(s), r))([…s].sort()), {} ) ); console.log(result); 1 solved Split arrays into multiple arrays based on string characters … Read more
There are several ways to do this. But since the size of the array is always 6×7, you can actually create a kind of template array as an array literal, which starts with 0. Then the rest is a piece of cake: just add the argument to all the values: function snakeArray(start) { return [ … Read more
How to make an algorithm to get all column names from across tables that relations with their primary key in SQL Server and C#? solved How to make an algorithm to get all column names from across tables that relations with their primary key in SQL Server and C#?
You could create recursive function with for…in loop and first calculate total sum and total number of nodes and then use those 2 values to calculate average. var graph_structure = {“val”:74,”child”:[{“val”:17,”child”:[{“val”:34,”child”:[{“val”:34,”child”:[{“val”:65,”child”:[{“val”:28,”child”:[{“val”:85},{“val”:30,”child”:[{“val”:68},{“val”:10,”child”:[{“val”:100,”child”:[{“val”:21,”child”:[{“val”:21},{“val”:64}]},{“val”:86}]}]}]}]}]},{“val”:22,”child”:[{“val”:17,”child”:[{“val”:65}]}]}]},{“val”:53,”child”:[{“val”:3,”child”:[{“val”:98,”child”:[{“val”:90,”child”:[{“val”:76,”child”:[{“val”:87,”child”:[{“val”:52,”child”:[{“val”:56}]}]},{“val”:47},{“val”:40,”child”:[{“val”:80,”child”:[{“val”:34}]},{“val”:23,”child”:[{“val”:47},{“val”:92}]},{“val”:98,”child”:[{“val”:89},{“val”:16},{“val”:10}]}]}]}]},{“val”:35,”child”:[{“val”:89,”child”:[{“val”:76,”child”:[{“val”:50,”child”:[{“val”:51},{“val”:90}]},{“val”:69,”child”:[{“val”:93},{“val”:98},{“val”:62}]}]}]}]}]}]}]}]}]},{“val”:98,”child”:[{“val”:85},{“val”:85,”child”:[{“val”:58,”child”:[{“val”:81,”child”:[{“val”:36,”child”:[{“val”:45,”child”:[{“val”:96,”child”:[{“val”:15,”child”:[{“val”:11,”child”:[{“val”:96}]}]},{“val”:48,”child”:[{“val”:4,”child”:[{“val”:74},{“val”:1}]},{“val”:7}]}]},{“val”:84,”child”:[{“val”:9},{“val”:81,”child”:[{“val”:10,”child”:[{“val”:67}]}]}]}]},{“val”:85,”child”:[{“val”:53},{“val”:7,”child”:[{“val”:47,”child”:[{“val”:74,”child”:[{“val”:30},{“val”:7},{“val”:12}]},{“val”:22}]},{“val”:56,”child”:[{“val”:51,”child”:[{“val”:45}]},{“val”:54,”child”:[{“val”:20},{“val”:62}]}]}]}]}]}]}]},{“val”:62,”child”:[{“val”:36,”child”:[{“val”:39,”child”:[{“val”:20}]},{“val”:10,”child”:[{“val”:91,”child”:[{“val”:81,”child”:[{“val”:59,”child”:[{“val”:19,”child”:[{“val”:59},{“val”:16}]},{“val”:35,”child”:[{“val”:30}]},{“val”:6,”child”:[{“val”:27}]}]},{“val”:89,”child”:[{“val”:60,”child”:[{“val”:59}]}]}]}]}]}]}]}]}]},{“val”:8,”child”:[{“val”:56,”child”:[{“val”:55,”child”:[{“val”:41,”child”:[{“val”:17,”child”:[{“val”:15,”child”:[{“val”:40,”child”:[{“val”:55,”child”:[{“val”:50},{“val”:99,”child”:[{“val”:86},{“val”:90}]}]}]},{“val”:85,”child”:[{“val”:36,”child”:[{“val”:39,”child”:[{“val”:45}]}]}]},{“val”:78,”child”:[{“val”:24,”child”:[{“val”:93,”child”:[{“val”:8}]},{“val”:26,”child”:[{“val”:5}]}]},{“val”:36}]}]},{“val”:13}]}]},{“val”:10,”child”:[{“val”:0,”child”:[{“val”:77,”child”:[{“val”:46,”child”:[{“val”:72,”child”:[{“val”:17,”child”:[{“val”:10},{“val”:67}]},{“val”:48},{“val”:60}]},{“val”:98,”child”:[{“val”:12,”child”:[{“val”:61},{“val”:27}]}]}]}]}]}]}]}]}]}]} function calc(data) { return (function repeat(data, res) { for(let i in data) { if(data.val) { res.nodes++; res.total += data.val if(!res.min) res.min = data else … Read more
What is a good non-recursive algorithm for deciding whether a passed in amount can be built additively from a set of numbers? solved What is a good non-recursive algorithm for deciding whether a passed in amount can be built additively from a set of numbers?
Your algorithm is incorrect. You basically only check middle of the sequence, which doesn’t make any sense. Instead you should start with both indexes at the beginning of the array and increment right as long as sum of subrange is smaller than K. When it gets bigger start incrementing left until it is smaller again. … Read more
You don’t need to store ranges, only probabilities, or in your case the number of balls they have. Player 1 has 60 balls. You can store that directly as an int 60. Player 2 has 20, so store 20. And so on. Then count the total number of balls (once, or hardcode it if it … Read more
You should provide inner class instance into Arrays.sort to compare points from view of parent class instance. To do it you should not create new instance in main() function, but get it from Point instance. So, in main function you should use something like this: Point pivot; … // set up pivot point here Arrays.sort(myPoints, … Read more
BigInteger has the divideAndRemainder(…) method, one that returns a BigInteger array, the first item the division result, and the second, the remainder (which is what mod really does in Java). Update Including comment by Mark Dickinson to other answer: There’s a much simpler linear-time algorithm: set acc to 0, then for each digit d in … Read more
These two questions typically differ based on how they’re framed. Usually, the string permutation question is asked as Given a string w and a string x, check whether w is a permutation of x. In that sense, you know what both strings are, and you just need to see whether the character counts match (or … Read more
It should be: [array[j], array[j + 1]] = [array[j + 1], array[j]]; instead of: [array[j], array[j + 1] = array[j + 1], array[j]]; Pay close attention to where the square brackets begin and end. Your current code: assigns one array index to itself creates an array with 3 elements and throws it away immediately What … Read more
Let’s consider your example… A = (5, 5, 1, 2, 3, 4, 5) If you consider the first element – 5 – then we know any solution must have one non-5 value at the other end, so we work backwards to find the first non-five, keeping track of the “front” and “back” locations we’re working … Read more
I would read this paper “Robust Real-Time Face Detection” to get started also this one is interesting 0 solved how face recognition works in real time [closed]