You should write inbracket = list(newstrlist); for the assignment, otherwise your lists will be pointers to the same actual element, and modifying newstrlist will modify inbracket. 3 solved Python trying to clear and reuse list [duplicate]
Looks like Microsoft’s Segoe UI. Check out a preview of the same: 1 solved What is this font in the image [closed]
var myJSON = JSON.parse(‘{“Record_0”:[{“Status”:”CREATED”,”CreatorLoginId”:”sandhya”,”Name”:”G1″}],”Record_1″:[{“Status”:”CREATED”,”CreatorLoginId”:”San”,”Name”:”G2″}]}’); for(var pr in myJSON) { console.log(myJSON[pr][0].Status); console.log(myJSON[pr][0].CreatorLoginId); console.log(myJSON[pr][0].Name); } 3 solved How can iterate over JSON object and print its properties and their values?
According to your code you can replace : bool IsAVowel (char ch) { { if ((ch >= ‘A’ ) && (ch <= ‘Z’)) return true; else return false; } by bool isUpper(const char ch) { return (ch >= ‘A’) && (ch <= ‘Z’); } 3 solved how to write a c++ code to make function … Read more
library(ggplot2) ggplot(dat, aes(x = Experiment, y = Mean, colour = Method, linetype = as.factor(Values), shape = as.factor(Values))) + geom_line() + geom_point() where dat is the name of your data frame. 3 solved comparing two protocol for different values in R [closed]
Beside the problem with while(isspace(ch)); that should probably be replaced with while(!isspace(ch)); you need to add a null character at the end of your string before sending it to your insert() function and this function should also return a new value for the root variable: string[i]= 0; i=0; root=insert(string,root); You should also make sure that … Read more
First of all whenever you want to disable back press just override onBackPressed() method and remove super. like this: @Override public void onBackPressed() { //super.onBackPressed(); } Second you’r using application context to show toast. use activity context. Toast.makeText(this or YourActivity.this, “Setup Complete!”, Toast.LENGTH_LONG).show(); Third just add this attribute into your manifest class. This will avoid … Read more
Your code appears Fine. A simple logic modification that you can do is instead of using count++ for every repeated values,just put the integers from Array A to your ArrayList<> and when putting the next integer from Array A just parse through the ArrayList<> to check whether we have the number already present. Then same … Read more
You almost got it, change it to like this var grades = [100, 90, 100, 50, 80, 60]; function countFailing(gradesArr){ var counter = 0; for (var i = 0; i < gradesArr.length; i++){ if (gradesArr[i] < 70 ) counter++; } return counter; } alert(countFailing(grades)); DEMO HERE solved How to make a function take in an … Read more
So you open the outside the while loop but you keep closing it inside the while loop try this code: echo ‘<ol>’; $i = 0; while ( $cat_posts->have_posts() ) { $cat_posts->the_post(); ?> <li><div class=”a”><?php echo $i++ + 1; ?> </div> <a class=”post-title” href=”https://stackoverflow.com/questions/26014814/<?php the_permalink(); ?>” rel=”bookmark” title=”<?php the_title_attribute(); ?> Apk Android Download”><font color=”#000″><?php the_title(); ?></font></a> … Read more
5th or 6th or 7th argument passed to calcola_cedimento is empty string, i.e. at least one of following returned empty string finestra_ag.get() finestra_ss.get() finestra_st.get() If user is allowed to let said entries empty you should provide default values for this case. If for example ag value should be “1” in such case, you might do … Read more
Each website on browser save their own session and each browser save their own too. So the answer is you can not do this except of using cookie to access data from another browser, but i think it is not a brilliant idea to do. Just use session and cookie as the way they born, … Read more
IIUC, this is a classical groupby+agg. You need to set the dates to a datetime type for meaningful comparisons: (df .assign(DATE_1=pd.to_datetime(df[‘DATE_1’]), DATE_2=pd.to_datetime(df[‘DATE_2’]) ) .groupby(‘ID’) .agg({‘DATE_1’: ‘min’, ‘DATE_2’: ‘max’}) ) output: DATE_1 DATE_2 ID 12 2012-01-01 2021-01-01 13 2010-01-01 2021-01-01 14 2012-01-01 2021-01-01 0 solved Group by ID and select rows with the newest DATE1 and … Read more
A value of type ‘Null’ can’t be assigned to a parameter of type ‘Key’ in a const constructor. Try using a subtype, or removing the keyword ‘const’ solved A value of type ‘Null’ can’t be assigned to a parameter of type ‘Key’ in a const constructor. Try using a subtype, or removing the keyword ‘const’
Inside the Setter for the SoundLocation property is an interesting check: set { if (value == null) { value = string.Empty; } if (!this.soundLocation.Equals(value)) { this.SetupSoundLocation(value); this.OnSoundLocationChanged(EventArgs.Empty); } } You can see that it looks to see if the new location differs from the old one. If it does, then it does some setup work. … Read more