Use readlines and output the lines according to their index. with open(‘addon/entertainment.txt’) as f: lines = f.readlines() for line in lines: print(“{}. {}”.format(lines.index(line) + 1, line)) desired_lines = [3, 5] output = [] for desired in desired_lines: output.append(lines[desired – 1]) for o in output: print(“{}. {}”.format(output.index(o) + 1, o)) Alternatively, if you want to select … Read more
The right way to do it is straight-forward: int hours = /*some_number*/; int wage = 100*hours; if (hours > 40) wage += 50 * (hours-40); To squeeze it to a single expression, the example takes advantage of the fact that a boolean is either 1 or 0. So x*some_bool evaluates to either x or 0. … Read more
To solve the array issue you just need to make a few small changes. int stop=0,d,*t; // Declare an uninitialized pointer to int float f(float x) { int loop,loopa; float add=0.0,sum=0.0; for(;stop==0;) { int p ; cout << “Enter the degree of the poly. eq. (+ve integer)” << endl; cin >> d ; t = … Read more
You could do this: df <- data.frame(date=c(“18MAY2013:00:00:00″,”19MAY2013:00:00:00″)) df$year <- format(as.Date(df$date,”%d%B%Y”),”%Y”) df$month <- format(as.Date(df$date,”%d%B%Y”),”%m”) date year month 1 18MAY2013:00:00:00 2013 05 2 19MAY2013:00:00:00 2013 05 1 solved How can I create a new column for month and year from datetime and logically compare date time in R [closed]
You cannot find a control in the GridView directly when its in the row, you have to find it in the row of the gridview. Use either: GridView1_RowDataBound event if(e.Row.RowType == DataControlRowType.DataRow) { FileUpload fileupload = (FileUpload)e.Row.FindControl(“fileupload1”); } OR DataRow r = (DataRow)sender; FileUpload fileupload = (FileUpload)r.FindControl(“fileupload1”); solved FileUpload Error? [duplicate]
Looks like you’ve been relying on the ancient, long-deprecated behaviour that methods named the same as the class act as the constructor. This behaviour has finally been thrown out in PHP 8: Methods with the same name as the class are no longer interpreted as constructors. The __construct() method should be used instead. 0 solved … Read more
First, it would be impossible to create a map of parentId to each childId if there is a list of children in each node because in general case a parentId key may have multiple childId values and this conflict has to be resolved somehow. So, either a Map<Integer, List<Integer>> where List<Integer> contains ids of all … Read more
Here I address you questions: 1. Any way to check the size of existing databases in CloudSQL instances? Yes, there is. This depends on the database engine you are using(mysql, postgres or mssql) For mysql, you can run: SELECT table_schema “DB Name”, ROUND(SUM(data_length + index_length) / 1024 / 1024, 1) “DB Size in MB” FROM … Read more
Slices are references to arrays. When modifying a slice without copying it, the underlaying array will be modified. Therefore, all slices that point to the same underlaying array will see this change. solved Why does this goroutine behave like it’s call by reference?
I think it is better store it in a database’s table. If you store it in a enum, when you add, change or delete a fruit you have to compile your code again. In case of change, you will have to update all places (tables columns) where this fruit’s name is store. In the database … Read more
You don’t have to use imagecreatefromstring in your code. You can encode/decode with php base64 functions. $imageEncoded = base64_encode($your_image); $imageDecoded = base64_decode($imageEncoded); 3 solved How can I encode/decode to base64?
You can use sub to get only the number from DF1$A and use %in%to test if the number is present in DF2$A. DF1$C <- “” i <- !sub(“\\D*”, “”, DF1$A) %in% DF2$A DF1$C[i] <-DF1$A[i] DF1 # A B C #1 ABC 1 AA ABC 1 #2 ABC 2 AB #3 ABC 3 AC #4 ABC … Read more
If you use input() your example works. If you have a string variable like your example and you want to “turn it” to a raw string-like string (double escapes, in your case), you can use str.encode() path.encode(‘unicode_escape’) converts “C:\path” to “C:\\path” 1 solved Read a path from variable [closed]
Assuming that class CatchesItem has time field defined as LocalDateTime, the check for today’s timestamp may be implemented as follows: import java.time.*; // … LocalDate today = LocalDate.now(); for (CatchesItem item : items) { if (today.equals(item.getTime().toLocalDate())) { item.setAmount(item.getAmount() + 5); // add some value to amount } } items.forEach(System.out::println); Output (for the input data as … Read more
Sometimes you need to incrementally build a new string, i.e. character per character. In order to do this efficiently many programming languages add the so-called string builders. This allows to essentially modify an array of characters rather than recreating a new string every time. Check the official example: package main import ( “fmt” “strings” ) … Read more