[Solved] How to make button do 2 events? [closed]

Try this; Button btn; btn.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Toast.makeText(MainActivity.this, “abc….”, Toast.LENGTH_LONG).show(); mTextView.setTextColor(Color.parseColor(“#bdbdbd”)); } }); solved How to make button do 2 events? [closed]

[Solved] How to get text value of HTML label in c# in ASP.NET WebForms [closed]

As you are using WebForms the easiest is to change your ASPX to: <label ID=”myLabel” runat=”server” ClientIDMode=”Static” for=”Rdb_1″>No</label> and then in code behind: myLabel.InnerText However I would suggest you investigate using a label control as that would be even easier to use. solved How to get text value of HTML label in c# in ASP.NET … Read more

[Solved] Convert integer to string

<?php $integers=”1,5,8,4,3″; //Convert into String $arr = explode(‘,’, $integers); // String to Array Conversation foreach ($arr as $key => $value) { $val[] = “‘”.$value.”‘”; // add your requirements here } $finalvalue = implode(‘,’, $val); // Array to string echo $finalvalue; // your final result ?> solved Convert integer to string

[Solved] How do I rewrite this code to accept user input? [closed]

A naïve approach would be to do the following. Console.WriteLine(“Add integer X: “); int x = Convert.ToInt32(Console.ReadLine()); Console.WriteLine(“Add integer Y: “); int y = Convert.ToInt32(Console.ReadLine()); Triangle Tri1 = new Triangle(x, y); Console.WriteLine(“Area 1=” + Tri1.TriArea()); A more robust approach would be to validate user input and have an input loop so that the user can … Read more

[Solved] c# faster way to read all textboxes/labels [closed]

You can create an array with the references to the labels: Label[] labels = { eLabel1, eLabel2, eLabel3, … }; Producing an array with the texts from the labels would be a one-liner: string[] values = labels.Select(l => l.Text).ToArray(); solved c# faster way to read all textboxes/labels [closed]

[Solved] Why is my compiler giving me these two errors in Java?

So I see two glaring errors, the first of which is what the compiler is telling you, namely that real and imaginary have not been declared anywhere. In Java, you cannot use a variable unless you have previously declared it. You probably want to have a real and imaginary component of your ComplexNumber, so you … Read more

[Solved] can not find error in java [closed]

If you do not have a constructor the Java compiler will create a no-arguments constructor for you. As soon as you provide a constructor which has arguments the no-argument constructor does not get created by the compiler. So if you add a no-arguments constructor to InVoice (like below) it should work. public InVoice() { } … Read more

[Solved] In a 2-dimensional array of integers, how can we place a new integer at a completly random spot in the 2-d array?

static void placeRandomly2D(int[][] arr, int limit) { // generates value [0…limit) half-interval and places it into the 2D array arr // at random position; limit must be positive Random rand = new Random(); int value = rand.nextInt(limit); int pos1 = rand.nextInt(arr.length); int pos2 = rand.nextInt(arr[pos1].length); arr[pos1][pos2] = value; } And, just in case, version for … Read more

[Solved] calling an activity from fragment activity through Intent [closed]

the Intent constructor accepts two arguments. first argument is your Context and the second one is your Activity class. in your fragment, you can access your Context via getActivity method. here is what you should do : Intent i = new Intent(getActivity(), MyActivity.class); 0 solved calling an activity from fragment activity through Intent [closed]