Create basic elements like this: var myTable = document.createElement(‘table’); var tbody = document.createElement(‘tbody’); myTable.appendChild(tbody); then you can go in loop and append cells to tbody like this: var numberOfRows = 2; var numberOfCellsInRow = 5; for (var i = 0; i < numberOfRows; i++) { var tempRow = document.createElement(‘tr’); for (var j = 0; j … Read more
Luckily my crystal ball is working today so I can guess what you mean when you say it isn’t working. Of course, you might have made it easier by actually explaining, but there we go. If you just want a list of (x, y) pairs then zip is the way to go. The syntax you … Read more
It looks like you need a doctype http://validator.w3.org/check?uri=http%3A%2F%2Fdev.ux-pm.com%2F&charset=%28detect+automatically%29&doctype=Inline&group=0 This will probably clear up quite a few issues with things looking wrong on older versions of IE but this won’t necessarily fix everything. Validating is not a cure all but I do find that the more compliant the code is then the less likely bugs occur. … Read more
Your problem is because you’re not waiting for the DOM to be ready, try moving the div like this (http://jsfiddle.net/icodeforlove/68gGS/) <body> <div class=”container”></div> <script type=”text/javascript”> var SearchView = Backbone.View.extend({ el: ‘.container’, initialize: function() { this.render(); }, render: function() { $(this.el).html(“hello”); //tried both but not working. this.$el.html(“hello”); } }); var search_view = new SearchView(); </script> </body> … Read more
“Hello World” is a constant so it is O(1) whereas string str is variable of length n so the complexity is O(n) 2 solved Time complexity difference in System.out.println() [closed]
121 = 11 * 11 would be the first non-prime listed as prime by your code. So your code is only a solution up to n = 120. I.e.: No. 3 solved Is this a good approach for finding number of prime numbers within a certain range? [closed]
I went through all the below answers. But none of them produced the solution. The problem in all solution is the array is printed on same cell, leaving the other cell empty(including the answer provided by Vadian – it will give error because it is printing all the value in same row.). While printing an … Read more
If I understand correctly, you want to count how many 0 values you have in each column? If so, you can use apply function for each of the columns: data <- data.frame( a = c(1,2,0,3), b = c(0,0,0,2) ) apply( data , 2 , function(x) sum ( x == 0 ) ) a b 1 … Read more
my %counts; for (values(%hash)) { # Iterate over the values of the hash, the references to the arrays. for (@$_) { # Iterate over the values of the referenced array. ++$counts{$_}; } } or my %counts; ++$counts{$_} for map @$_, values %hash; 3 solved perl: How to I count multiple values in hash into a … Read more
…without having to bother with the code behind. The code is only one aspect. …like to be able to edit the text content of the site… Does your client know how to write for the web? Does she know how to use data from analytics, surveys, and user testing to optimize that content? …change the … Read more
Any of the following solutions will work: Remove the keyword, public from the definition of the classes, Circle and Square Write the classes, Circle and Square as they are (i.e. with public keyword) in separate files. The reason is that Java supports only one public class in a source file. A couple of more points: … Read more
What’s your larger goal? It seems like this would make the site unusable for mobile devices, which I’m sure is not the result you’re aiming for. While I don’t see this being used when I inspect the site, I know you can use the viewport meta tag to control default zooming on websites. 0 solved … Read more
Check the last two line of your code. Where the break is out of any loop. Put it in the specific loop, if you need it, otherwise remove it. 5 solved Why got syntax error ‘break’ outside loop? [closed]
For getting output what you need ,first table record you need to de-concatenate, i mean single rows record make multi rows record and then put inner join. then again you need to apply concatenation on result using stuff function in sql server. 2 solved how to replace values in sql
you should import your Module or external library first. and random module dose not have random.str() function! Try This : import random a = [‘blue’, ‘red’, ‘green’, ‘yellow’, ‘brown’, ‘black’] print(random.choice(a)) Good Luck. 1 solved How to generate a random word