When you create a new Dataset in a folder, the default namespace of the dataset is the folder name. So where you want to use it, you need to use the full foldername as the namespace, like this: FolderName.SubFolderName.DataSet1 ds = new FolderName.SubFolderName.DataSet1(); Or at the top of the class where you’re trying to use … Read more
jsFiddle Demo This looks like a situation where you are going to have to do some custom formatting based on knowing the exact format of the input. You should probably take a sliding window approach using substring with a hardcoded knowledge of the format. (I used jQuery here for brevity in the demo. Note that … Read more
If you want to read the text file and split the values to columns in a table try this: <?php $handle = @fopen(“domarr.txt”, “r”); while (!feof($handle)) { $buffer = fgets($handle, 4096); if (strlen(trim($buffer)) > 0){ list($a,$b,$c,$d,$e,$f,$g,$h,$i,$j)=explode(“,”,$buffer); $items[] = array(‘col1′ => $a,’col2′ => $b,’col3′ => $c,’col4′ => $d,’col5′ => $e,’col6′ => $f,’col7′ => $g,’col8′ => $h,’col9’ … Read more
This is not especially easy. I have a work-in-progress component in my CWAC-RichEdit project for this. In the end, you need to be able to apply CharacterStyle subclasses to the content of the EditText, typically when the user highlights some text. This involves getting the Spannable out of the EditText via getText(), getting selection information … Read more
It takes a few steps, for example: list all elements of a directory filter for directories get file creation time save up the path + time combo in a list find the minimum of the list with respect of time import java.io.IOException; import java.nio.file.Files; import java.nio.file.Path; import java.nio.file.Paths; import java.nio.file.attribute.BasicFileAttributes; import java.nio.file.attribute.FileTime; import java.util.ArrayList; import … Read more
Code it from scratch. If you’re not going to use an external library, that is by definition pretty much your only option. You’ll want to become an expert in the formal specifications for both PDF and MS Word. Given the complexity and history of each of those, I expect a senior developer will want 6-12 … Read more
Logical OR (||) works here Do this <script> if(window.location.href == ‘https://www.example.com/2021/05/test-post.html’ || ‘https://www.example.com/2021/05/test-post.html?m=1’) { window.location=”https://www.website.com/2021/12/official-post.html”; } </script> 0 solved How two different URLs can be forwarded to a single URL with single JavaScript? [closed]
I believe you are almost there. When comparing typeof val === “object”, please note that null is also treated as a object type in Javascript. So please make sure you do a null check on your solution. If you try to do Object.entries(null), it gives Uncaught TypeError: Cannot convert undefined or null to object var … Read more
Check your $perpage variable. I think you are getting 5 in it. Changing it will give you correct result. solved i should change I want to increase the number of news on the page with Php (codeigniter)
Using implode and array_map $input = [13 => 500, 16 => 1000]; $output = implode(‘, ‘, array_map( function ($v, $k) { return $k . ” ” . $v; }, $input, array_keys($input)) ); var_dump($output); Using foreach $input = [13 => 500, 16 => 1000]; $output = “”; foreach ($input as $k => $v) { $output .= … Read more
You can use Array.prototype.map for this. In your case: suspects.map((name) => { let suspectObj= CreateSuspectObjects(name); suspectsList.push(suspectObj); }); If you need the index in the future you can also do: suspects.map((name, idx) => { let suspectObj= CreateSuspectObjects(name); suspectsList.push(suspectObj); }); 4 solved I want to loop through an array but I don’t want to use for
This error occurs because you have not installed the Java JDK. How to use Kotlin in VS code First you need to install the following programs on your machine Install Java JDK on the computer system Install Kotlin on your computer system VS code install plugin Kotlin Language VS code install plugin Code Runner installation … Read more
You can use str.format, and str.join to get your required output. Ex: fruits = [‘banana’, ‘apple’, ‘plum’] mystr=”i like the following fruits: \n\n{}”.format(“\n”.join(fruits)) print(mystr) Output: i like the following fruits: banana, apple, plum 3 solved Concatenate string & list [duplicate]
Because the value represented by an octal literal is being printed out as decimal value on the standard output. If you want to output the octal literal value you should use the std::oct stream manipulator: std::cout << std::oct << number; Integer values are represented by integer literals. They can be octal such as 0437, decimal … Read more
It looks like that call validates the values that the user entered into the form, before sending those values to the server to create an account with them. This type of client-side validation can improve the experience of the users of the app, since they get more immediate feedback in case they entered some invalid … Read more