The main problem here is that you are calling functions as they were variables Here is your code with the functions being called correctly: import math print(‘input your height and weight to find BMI.’) num_a = int(input(“feet==”)) num_b = int(input(“inches==”)) num_c = int(input(“weight(lbs)==”)) def weight(): return int(num_c) * 2.2 def height(): return (int(num_a)) * 12 … Read more
As @BigBen said in the comments, it is down to your use of If…Else…If twice. The first correction is: If Result = True And Worksheets(“Sheet3”).Range(“C4”, Range(“C4”).End(xlDown)) <> “” Then Worksheets(“Sheet1”).Range(“C4”, Range(“C4”).End(xlDown)).Value = Worksheets(“Sheet1”).Range(“C4”, Range(“C4”).End(xlDown)). _ Value + Worksheets(“Sheet3”).Range(“C4”, Range(“C4”).End(xlDown)).Value ElseIf Result = True And Worksheets(“Sheet3”).Range(“D4”, Range(“D4”).End(xlDown)) <> “” Then Worksheets(“Sheet1”).Range(“D4”, Range(“D4”).End(xlDown)).Value = Worksheets(“Sheet1”).Range(“D4”, Range(“D4”).End(xlDown)). _ … Read more
Thanks for all responses The Lambda expression query is correct only. db.Companies.where(Company => (Compare(Convert(Company.Name), “Test”) > 0)) db.Companies.where(Company => (Compare(Convert(Company.Name), “Test”) >= 0)) I changed the “right arg” value to “Test”. I have one record ‘Name’ with Test. executed the following query. db.Companies.where(Company => (Compare(Convert(Company.Name), “Test”) > 0)) and shown the results 105(here Name with … Read more
I believe you want a dictionary with a single key and a list: l = [1,2,3,4,5] d = {l[0]:l[1:]} Output: {1: [2, 3, 4, 5]} 0 solved Turning a list into a dictionary?
It’s null coalesce operator. It will return $_GET[‘page’] unless it’s null. In case it’s null it would return default value ‘home’. It has same meaning as: !is_null($_GET[‘page’]) ? $_GET[‘page’] : ‘home’ 1 solved PHP syntax ?? meaning,can somebody explain? [duplicate]
If you are trying to parse single or double quoted strings, it should be done in two steps. Validation, then parse for values. You could probably do both in a single regex with the use of a \G anchor, validating with \A\G and parsing with just the \G. If you are sure its valid, you … Read more
Any better solution? Taking your question literally, no. There is no better solution. This will create a default constructed, and therefore empty std::map<int,int>. std::map<int,int> m; solved How to create an empty std::map object? [closed]
There is unlikely to be an objective answer to this, as both the K&R and 1TBS styles emerged in the context of the C programming language, where there were no class definitions. Since derivative languages of C that support classes (e.g., C++, Java, etc.) share most of the syntax, it is only natural that the … Read more
You selector is wrong . var adElem = $(‘.ad.spf-nolink’).removeClass(‘ClassName’); . class-selector # id-selector .removeClass() solved JQuery remove div class [duplicate]
First, I do not really know which is the default OUTER JOIN in T-SQL (I’d bet FULL), but in any case, I think it is unclear – it is best to use LEFT, RIGHT, OR FULL JOIN explicitly when you need one. JOIN joins tables. Already existent ones or subqueries. APPLY applies (duh) a table-valued … Read more
You can’t override operators for pre-existing classes. The closest you can get is to make an extension method: public static bool EqualsCaseInsensitive(this String a, String b) { return String.Equals(a, b, StringComparison.OrdinalIgnoreCase); } You can use it like so: var areSame = stringA.EqualsCaseInsensitive(stringB); That being said, it’s considered bad practice to add extension methods to core … Read more
The =-symbol allocates the value of the arithmetic expression on it’s right to the variable on it’s left It assigns the result. Allocation is something different, and it’ll be important to remember the difference later (dynamic allocation in particular will be really confusing if you conflate it with assignment). But if i have an expression … Read more
If you use Python3 then input(question) returns string ‘1’, ‘2’, etc. You have to convert it into number int(input(question)). 6 solved Python Type Error Unsupported Operand [duplicate]
Yes, it will. Although it is going through an upcast, you will find that for the upcasted (Mammal) instance, the following condition still holds: (myMammal is Horse) == true But actually doing this is an anti-pattern. Go for an architecture using interfaces instead. solved What class does this variable belong to?
You did char * response. This makes a pointer variable to a character. Right now it is not pointing to any memory(it is some garbage value). scanf stores user input in consecutive memory addresses starting from the one pointed by response. as response is uninitialised, the input may not necessarily be stored on the stack(Don’t … Read more