Please look at the formatting tips, it will help you display your code as you wish. that said, I think this is what you want. The following code will iterate through each character in your list string. If it finds a match, it will print success list = “9876554321” for char in list: if char … Read more
Use this query SELECT MIN(s.Payment), e.EmpName, e.EmpID FROM dbo.Employee e INNER JOIN Salary s ON e.EmpID = s.EmpID WHERE e.EmpID IN (SELECT TOP 2 EmpID FROM dbo.Salary ORDER BY Payment DESC) 5 solved find 2nd highest salary in sql [closed]
Why your proposed result is invalid Your proposed result is invalid. It can never exist. Objects (as indicated by curly braces {…}) are essentially dictionaries. They map keys to values. It is therefore invalid to not specify any keys (as you did). The data structure you are seeking for are arrays, which are indicated by … Read more
To avoid cross-domain issues, you can do this using JSONP: $.getJSON(“http://en.wikipedia.org/w/api.php?action=query&prop=extracts&exintro&format=json&callback=?&titles=Google”, function(data){ var page = data.query.pages; var intro = “”; for (var key in page) { var obj = page[key]; intro = obj.extract; } console.log(intro); }); 1 solved Is there a way to get the main paragraph from Wikipedia using JavaScript only? [closed]
Basically it downloads a file from; http://dl.dropboxusercontent.com/s/nldqctnbvlez42b/******.dat?dl=1 (obfuscated link, don’t want anyone downloading it by mistake) …to c:\temp and registers it in the system using; regsvr32 /s <filename> The real evil is probably in the downloaded file (which I’m not going to download 🙂 ) 3 solved Code inside this undetectable malware [closed]
There are a few ways to interpret your question, // this was missing a size. So we need to add one. int x = 10; String []s = new String[x]; String s[] = new String[x]; // This is the same as the previous line. The other form type of question is this, //These are two … Read more
I have fiddled the code try it. using jquery var diva = $(‘div.a’), divb = $(‘div.b’) divb.hide(); diva.on(‘mouseover’, function(){ divb.show(); }); diva.on(‘mouseout’, function(){ divb.hide(); }); http://jsfiddle.net/6fff9/1/ 3 solved Hide div on mouseout [closed]
It seems like you’re confused about a basic part of html, and programming languages in general: Contexts. html is constructed out of tags. A tag may contain attributes, which may have a value. In a tree-like form: tag | attribute = value | attribute tag | attribute = value tag tag | attribute … Or … Read more
It seems that this declaration: int scores[5]; Is incorrect. This creates an array with 5 numbers in it, indices from scores[0-4], however, you constantly refer to score[5], the sixth element of the array throughout your program. I recommend changing to int scores[6]; 2 solved Error when accessing array – stack around the variable ‘scores’ was … Read more
First of all: var username = $(“username”).val(); var password = $(“password”).val(); Should be: var username = $(“#username”).val(); var password = $(“#password”).val(); data: “email=”+email+”&username=”+username+”&password=”+password Should be: data: {email: email, “username”: username, password: password} And $username $_POST[“username”]; $password $_POST[“username”]; Should be: $username = $_POST[“username”]; $password = $_POST[“password”]; 1 solved Ajax is not sending data to PHP
Create a class that contains both items, and then sort that list: class Item { public int Id {get;set} public string Text {get;set;} } var unsorted = new List<Item> { new Item{Id = 3, Text = “eg3”}, new Item{Id = 1, Text = “eg1”}, new Item{Id = 2, Text = “eg2”}, } var sorted = … Read more
You can use the Regex pattern: (?:[A-Za-z.]*/PERSON\s*)+ [A-Za-z.]* matches zero or more of [A-Za-z.] /PERSON\s* matches /PERSON followed by zero or more whitespace The above is put in a non-captured group and the group is matched one or more time by the + token. Example: In [9]: re.search(r'(?:[A-Za-z.]*/PERSON\s*)+’, ‘Leo/PERSON Messi/PERSON hello’).group() Out[9]: ‘Leo/PERSON Messi/PERSON ‘ … Read more
At the end I found a solution to my problem: text = “‘my_home1’ in houses.split(‘,’) and ‘2018’ in iphone.split(‘,’) and 14 < mask” dict = {‘house’ : ‘my_home1,my_home2’, ‘iphone’ : ‘2015,2018’, ‘mask’ : ’15’ } expression = ‘false’ for key in dict.keys(): if isinstance(dict.get(key), str): text = re.sub(key, ‘\'{}\”.format(dict.get(key)), text) else: text = re.sub(key, dict.get(key), … Read more
You need to add main_panel.revalidate(); before the repaint() call in order to instruct the Swing layout manager to re-layout newly added components again. 3 solved problems with java layout manager
On RosettaCode you have implemented generating combinations in many languages, choose yourself. solved How to choose all possible combinations?