[ad_1] Translate to: for (int i = 0; i< n; i++) { int temp1 = arr[i]; int temp2 = temp1%k; int temp3 = arr[temp2]; arr[temp2] = temp3+k; } Edit: thanks for the correction @R Sahu 1 [ad_2] solved What does a[a[]] do in C?
[ad_1] Use URLEncoder to encode your URL params such as student_name[k] and roll_no[k]: final String queryString = “student_name=” + URLEncoder.encode(student_name[k], “UTF-8”) + “&roll_no=”+ URLEncoder.encode(roll_no[k], “UTF-8″); Use equals() and not == or != for comparing Strings: if(!””.equals(queryString)) 2 [ad_2] solved running application it’s showing this error in android
[ad_1] I’m not exactly sure what you are trying to accomplish…maybe this? StreamReader reader = new StreamReader(“C:/tut.txt”); String data = reader.ReadLine(); List<String> tok = new List<string>(); foreach (char s in data) { Console.WriteLine(s); tok.Add(s.ToString()); } 1 [ad_2] solved Problems With List [closed]
[ad_1] You should empty the stdin buffer before read something else. void emptyBuffer() { char c=”a”; while (c != ‘\n’ && c != EOF) { c = getchar(); } return; } This function empty the stdin buffer. printf(“Enter your name: “); scanf(“%s”, &string); emptyBuffer(); fprintf(fw, “%d\n%s\n”,p, string); printf(“Enter your telephone number: “); scanf(“%d”,&cislo); emptyBuffer(); fprintf(fw, … Read more
[ad_1] It is simple, but you must provide the user way enter that value. For example by the GET parameter number$userInput = $_GET[‘number’]; Then you only need to create basic if statement. You can read about it at http://php.net/manual/en/control-structures.if.php $somma = $bxs+$bs+$bm+$bl+$bxl+$b2xl+$nxs+$ns+$nm+$nl+$nxl+$n2xl; if($userInput <= 30){ $somma *=$m1; }else if($userInput >30) { $somma *=$m2; } else … Read more
[ad_1] Notice: Undefined variable: message in /Users/kobigo/Sites/yedikitamuhendislik.com/sendEmail.php on line 61 Look at what appears to be line 61: $message .= “Gönd.: ” . $name . “<br />”; You’re trying to append to $message, but you never defined it in the first place. You can append to it after it’s been defined, but on this first … Read more
[ad_1] Check out: RandomStringUtils and pick the most appropriate method! I would suggest: RandomStringUtils.randomAlphanumeric(8) 1 [ad_2] solved Generate a alphanumeric random and unique string with size of 8 in java(uppercase letter required)
[ad_1] ID of an element must be unique, so need to use class to group similar elements, also in the click handler you need to find the title element which is a descendant of the clicked li jQuery(‘#restaurant-menu-content-tab’).on(‘click’, ‘#res-menu-filters li’, function(e) { var value = jQuery(this).find(‘.menu-extend-title’).text(); jQuery(‘#menu-title-layout-text’).text(value); return false; }); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js”></script> <div id=”restaurant-menu-content-tab”> <div … Read more
[ad_1] Your use of for does not behave as you expect. You’re using this for-comprehension: for (data <- category(i)) { if (data.startsWith(x)) true else false } This expression “desugars” into (i.e. is shorthand for): category(i).foreach(data => { if (data.startsWith(x)) true else false }) foreach returns Unit, and therefore the type of this expression (and the … Read more
[ad_1] I do not use Java, but I will try to explain what is happening. The value 8188 is 0x1ff8 in big-endian hex. When your program is run the result is actually 8188 – 65536 = -57348. That is why you got the result you did. Because the input is big-endian binary, only the first … Read more
[ad_1] Extract the number from the string then increment it and put it back, e.g. using String.replaceXxx() and Integer.parseInt() etc. If you want to increment multiple independent numbers, try this: String input = “ABC999DEF999XYZ”; //find numbers Pattern p = Pattern.compile( “[0-9]+” ); Matcher m = p.matcher( input ); StringBuffer sb = new StringBuffer(); //loop through … Read more
[ad_1] First you split the string into an array: String str = “1.2, 3.1, 5.3, 4.5”; String[] arrOfStr = str.split(“,”); Then you loop through the array and convert to floats: import java.util.ArrayList; ArrayList <Double> volts = new ArrayList<Double>(); for (int i = 0; i < arrOfStr.length; i++) { volts.add(Double.parseDouble(arrOfStr[i])); } System.out.println(volts); 4 [ad_2] solved How … Read more
[ad_1] If what you want is to split the string at the first space, then you can use the string.split(s, maxsplit=n) where s is the string to split by and maxsplit=n is the number of splits to stop at. If you do not give any value for s that is only call the function as … Read more
[ad_1] You can not cast double[] to an Double, because of the obvious reason that they are just not COMPATIBLE. If you are storing the double values in double[] and want to convert individual double to Double, you need not to typecast explicitly. Autoboxing works by default. double[] val = {1.01, 3.09}; for(Double d : … Read more
[ad_1] If you read about __builtin_clzll in http://gcc.gnu.org/onlinedocs/gcc-4.1.2/gcc/Other-Builtins.html — Built-in Function: int __builtin_clzll (unsigned long long x) Returns the number of leading 0-bits in x, starting at the most significant bit position. If x is 0, the result is undefined. From https://cs.stackexchange.com/a/29510, The maximum possible XOR of any two integers from an interval [l, r] … Read more