Kirat Import picasso library to your project: implementation ‘com.squareup.picasso:picasso:2.71828’ Use picasso instead of Glide: Picasso.get().load(currentUser.getPhotoUrl()).into(navUserPhoto); Go through picasso documentation if you require extra modifications. 0 solved How to implement Picasso image loading library in android?
If you want to open a new form from button click of another form then you can do it like this. //Will be called on button click buttonClickEvent() { NewForm objectForm = new NewForm(); objectForm.Show(); } This will bring other form in foreground. If you are having another query then please try to share some … Read more
You can compile the program with Visual Studio 2019 (Community Edition will be good) The published github is not friendly…you have to create the project from scratch, follow those steps Create a new WPF project (WPF App (.NET Framework)) Copy all files in the project folder (overwrite MainWindow.xaml and MainWindow.xaml.cs) Add all .cs file to … Read more
Very short and simple example: <?php $text = “Hello World”; $i=0; while ($i<strlen($text)) { echo substr($text,$i,1); $i+=2; } ?> 4 solved show every second symbol of a string
The latest pro model. I always choose to buy the latest pro model. Also, I recommend buying the largest hard drive you can afford, that might mean the 250gb. The reason I say the latest model is because it’s an investment for your career. Even if you don’t realize it, your computer will generally generate … Read more
Simpson Try sololearn app After getting the certificate Then re-take the course from W3shools but always remember to practice and inverting the codes you learn R. i. P English solved What are some good learning resources? [closed]
482/10/5/2.0*2+14/5 48/5/2.0*2+14/5 9/2.0*2+14/5 4.5*2+14/5 9.0+14/5 9.0+2 11.0 Divisions go from left to right, addition comes last. An integer is only converted to double in an arithmetic operation with a double. That only happens three times: In step 3 (9/2.0), step 4 (4.5*2) and step 6 (9.0+2). All other operations are pure integer operations. 0 solved … Read more
Try this if result is an array len = result[0].origin; alert(len); 7 solved How to access the JSON data?
You can use MVEL API. MVEL is a hybrid dynamic/statically typed, embeddable Expression Language and runtime for the Java Platform. It is an open source. 0 solved Parse the Some User Define boolean Expression String in java [closed]
char name[30]; /* pre-allocated memory of stack */ Then scan that value in. or char *name = malloc(sizeof(char) * 30); /* run-time allocation on heap */ I am just using 30 here assuming the input string fits in 30 char’s you can increase or decrease it , it is up to your wish. 9 solved … Read more
You’re right, C does not support passing by reference (as it is defined by C++). However, C supports passing pointers. Fundamentally, pointers are references. Pointers are variables which store the memory address at which a variable can be located. Thus, standard pointers are comparable C++ references. So in your case, void Foo(char *k, struct_t* &Root) … Read more
in your data ‘2,2’ is one string. But csv reader can deal with this: import csv result = [] with open(“data”, ‘r’) as f: r = csv.reader(f, delimiter=”,”) # next(r, None) # skip the headers for row in r: result.append(row) print(result) [[“‘1′”, “‘2′”, “‘3′”], [“‘1”, “1′”, “‘2”, “2′”, “‘3”, ‘3’]] 3 solved CSV IO python: … Read more
You can’t perform addition on NSnumber for this NSNumber * totaldur =[NSNumber numberWithInteger:20]; totaldur = [NSNumber numberWithInteger:([number1 integerValue] + [[dict valueForKey:@”tracktime”] integerValue])]; //// first of all convert both numbers to same data type like (nsinteger,int,float) and then apply addition on them and in the end save sum in nsnumber object Hope it helps 2 solved … Read more
I’m taking a gamble by answering this.. but I’m assuming that you want to keep on adding two indexes within your array that are next to each other, to see if they’d equal any value in your second array? Also, I have no idea why you’re using a nested loop. You only need to traverse … Read more
Bootstrap 5 removed the dependency on jQuery. You don’t need jQuery to use Bootstrap any more, and Bootstrap no longer provides instructions on including it (because there’s no need). If you want to write your own code that uses jQuery, then follow the instructions on jQuery’s website. (Note, however, that there isn’t very much left … Read more