Kirat You need look-around assertions. $a =~ s|(?<=<no> ).*(?= </no>)|000|gi; # $a is now “<no> 000 </no> ” Have you considered reading a Perl book or two? You are not learning effectively if you have to come to Stack Overflow to ask that sort of questions that can be easily answered by reading the fine documentation. … Read more
Convert the range-based for to loops using iterator Stop using auto and write the type manually code: #include <iostream> #include <map> #include <string> int main() { std::string input = “slowly”; std::map<char, int> occurrences; for (std::string::iterator character = input.begin(); character != input.end(); character++) { occurrences[*character] += 1; } for (std::map<char, int>::iterator entry = occurrences.begin(); entry != … Read more
First of all initiate the database instance FirebaseDatabase firebaseDatabase = FirebaseDatabase.getInstance(); get the reference of your DB where you want to perform the operation DatabaseReference dbRef = firebaseDatabase.getReference(NAME_OF_DATABASE); then use this to get all the user with the name equal to the editText text Query query = profileDbRef .orderByChild(“name”) .equalTo(edittext.getText().toString()); query.addValueEventListener(new ValueEventListener() { @Override public … Read more
newlist = [] for sublist in yourlist: already_in_list = False for index, newsublist in enumerate(newlist): if sublist == newsublist[:-1]: newlist[index][2] += 1 already_in_list = True if not already_in_list: newlist.append(sublist+[1]) – >>>newlist [[‘personA’, ‘banana’, 1], [‘personB’, ‘banana’, 2], [‘personA’, ‘grape’, 1], [‘personA’, ‘lemon’, 2]] solved Python count list and types [closed]
You seem to be asking about whether the above code is the correct way to write a method that overrides a method in its superclass. Yes it is the correct way to do it. Yes, that is a good way to “change behavior” … though you are only changing the behavior for the new class … Read more
.parent{ background:#fff; height:40vh; width:50vw; border: 2px solid black; margin:auto; display: flex; flex-direction: row; justify-content: flex-end; padding:10px; } .child1, .child2{ height:25vh; width: 30px; border: 2px solid red; margin:5px; } <div class=”parent”> <div class=”child1″>1</div> <div class=”child2″>2</div> </div> Check whether it’s working for you. And the same I’ve written in codepen too. https://codepen.io/ak228212/pen/QWajNzj 2 solved Positioning two child … Read more
The top level object in your JSON file is an array so: class letsRead { public static void main(String [] args) { String inline = “”; try { URL url = new URL(“https://gist.githubusercontent.com/anubhavshrimal/75f6183458db8c453306f93521e93d37/raw/f77e7598a8503f1f70528ae1cbf9f66755698a16/CountryCodes.json”); HttpURLConnection conn = (HttpURLConnection)url.openConnection(); conn.setRequestMethod(“GET”); conn.connect(); int responsecode = conn.getResponseCode(); System.out.println(“Response code is: ” +responsecode); if(responsecode != 200) throw new RuntimeException(“HttpResponseCode: ” … Read more
Assuming you want to stick to arithmetic operations (and not strings), use the modulo operator with 10 to get the remainder of division by 10, i.e. the unit: 12345%10 output: 5 For an arbitrary number, you need to compute the position, you can use log10 and ceil: from math import log10, ceil N = 5 … Read more
Just try to correct indentation like shown below: …. try: subdomain = row.find_all(‘td’)[4].text subdomain = subdomain.replace(“*.”,””) if subdomain not in self.foundURLsList: self.foundURLsList.append(subdomain) except Exception as e: pass … Current version of bs4 does not support python 2 Beautiful Soup’s support for Python 2 was discontinued on December 31, 2020: one year after the sunset date … Read more
First thing, the doc name does not have any impact on what you have typed inside the file. So you can either use index.html or Index.html. But it is good practice to use index.html. And another good practice is to have all the .html files are in lowercase. And I can see that the name … Read more
If I clearly understand you, then you need just add $(‘#dayofweek’).val(arDate[0]); after this line const arDate = e.date.toString().split(‘ ‘);. Here is an example: let restaurantReserve = { init: function() { let _self = this; $(‘#reservation-date’).datepicker({ startDate: ‘+0d’ }).on(‘changeDate’, function(e) { const arDate = e.date.toString().split(‘ ‘); $(‘#dayofweek’).val(arDate[0]); filterTimes(); let input = $(‘[name=”RestaurantReservationForm[date]”]’); input.val(arDate[3] + ‘-‘ + … Read more
Ok I think the answer to the specific question is just down to rounding but I don’t need to chase that one as, in the last month or so, Google has decouple its rehoming of the markers from the smooth pan test. It is now an arbitrary 100000px limit before it stops maintaing the DOM … Read more
Your a is a temporary object in fun(). I fyou want fun() to change the pointer to a you’ll need to take the pointer as reference: int fun(int*& a) { a = fun2(); } Note that this interface is probably severely broken. solved I lose pointer or an address? It acts like never happen [closed]
You should change this: @Override public Object getItem(int position) { return position; } @Override public long getItemId(int position) { return position; } solved Simple Displaying a list of Items Parsed from JSON [closed]
In first example you are reading it as ’20’ and ‘3’ -> So not equal. In second exmple you are reading it as ’20’ and ‘ 3’-> note space. Its not 2 vs 3. It is 20 vs 3. %d will read whole string. You may want to check with %1d Return from strcmp Returns … Read more