Kirat Your count variable is named Q. You increment it on each loop in the increment statement Q = Z + y Where you have Z = text.length(); and y = user.length(); Now, since you don’t add those value to the previous Q value, you simply have Z + y so you only get the length … Read more
You error has nothing to do with the shown regex. The problem is because you use the matched result values as a parameter to replaceAll(), and those parameters are also regular expressions. Since you don’t want them to be interpreted as regex, you need to escape them, or rather “quote” them, like this: str = … Read more
Shoe roshe = new Nike(“roshe”, 11, “black”, “fashion”, 129.0, false) String literals should be enclosed in double quotes. As for your change in size type, pass int array instead of int int s[] = {11,12,13}; Shoe roshe = new Nike(“roshe”, s, “black”, “fashion”, 129.0, false) or Shoe roshe = new Nike(“roshe”,new int[]{11, 12, 13} , … Read more
You have to initialize your spinner in the onCreate method, so move CARS_TYPE = (Spinner)findViewById(…); inside onCreate() after setContentView one more thing, CARS_TYPE should not be a constant, better if you call it carsType instead 0 solved why this runtime is occured :Unable to instantiate activity ComponentInfo?
Since pointers are assigned in run-time and addresses are handed out in run-time, it makes no sense whatsoever to store/load a binary image containing pointers inside a file, because addresses will vary each time your program is executed. Therefore you cannot load this struct. You’ll have to re-write your whole program from scratch as it … Read more
I Fixed it my self this this code here: public class SplashScreen extends Activity { // Splash screen timer private static int SPLASH_TIME_OUT = 3000; private SessionManager session; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); // Session manager session = new SessionManager(getApplicationContext()); // Check if user is already logged in or not if (session.isLoggedIn()) { … Read more
Although, I didn’t get what exactly your question is, still I’ll try to help. What exactly this code does is, on clicking the button on top an new layout(one that you wanted) will add to the activity screen at runtime, i.e an edittext with a button, and when you click on that button, A toast … Read more
You need to use a like and concatenate a wildcard on the column value. Something like: select * from table where ? like concat(‘%’, mobile) I think will do it. 3 solved How to match column value from right using PHP and MySQL
The condition in both the for loops are wrong, it must be for(int j = 0; j < 9; j++) for(int i=0; i < 9; i++) if (array2[j][i] != array[j][i]&& array2[j][i] == 0) return false; return true; solved Validity check method not working
You can use custom fonts in pygame. Just find one that uses the Greek alphabet and use that. Use pygame.font.SysFont() and load your new font and enjoy. 1 solved Is it possible to use greek letters in pygame?
Make a function that returns the string given the position you want “T” to be in. function positionT(index, length){ var str=””; for(var i=0; i< length; i++){ if(i===index){ str+=’T’ } else { str+=’_’ }} return str; } positionT(1,5) // returns “_T___” positionT(2,5) // returns “__T__” solved How to make a letter move foward by one space … Read more
you should define your vector variable first : std::vector<string> mylist (5); then use a reverse_iterator for it : std::vector<string>::reverse_iterator rit = mylist.rbegin(); update: if you put using namespace std; then when you compile your code you will find that the problem with list={} because list is reserved class in namespace std so you can’t use … Read more
Swift’s substring is complicated: let str = “12:345” if let range = str.range(of: “:”) { let startIndex = str.index(range.lowerBound, offsetBy: 1) let endIndex = str.index(startIndex, offsetBy: 2) print(str[startIndex..<endIndex]) } 2 solved How can I substring this string?
This code extracts that particular site’s content a little better. def keyInfo(div): print(div.find(“h1”).get_text()) article = div.find(“article”) divText = article.find(“div”, id=”storytext”) [a.extract() for a in divText.findAll(“aside”)] [d.extract() for d in divText.findAll(“div”)] print(divText.get_text()) Approach After looking at the structure of the content using Chrome dev tools, I noticed the story content was in article > div[id=storytext], but … Read more
Use ConnectivityManager class.. OR Follow this link You will get What you want. Connectivity Manager 2 solved I want to print the status of connection. like my phone is connected in wifi or gprs. in android studio [closed]