Kirat var ws=”Hello World” var w=’Hello World the weather is fine.’ var ss=w.split(ws); for(i=0;i<ss.length;i++){ if(ss[i].length>0) console.log(ss[i]); } 2 solved How to get the last part of a string in Javascript
Be aware that this is a multi-step process and can take a long time. Make sure to test for bugs after accomplishing each step since they’ll definitely appear. The first step is migrating from Rails 2.3 to Rails 3.0. Second you want to upgrade to Ruby 1.9.3. Pushing from Rails 3.0 to Rails 5.x is … Read more
If your URL looks like an actual URL (with the http:// part) then you could use Uri class: private static void Extract() { Uri uri = new Uri(“http://somesite/somepage/johndoe21911”); string last = uri.Segments.LastOrDefault(); string numOnly = Regex.Replace(last, “[^0-9 _]”, string.Empty); Console.WriteLine(last); Console.WriteLine(numOnly); } If it’s exactly like in your example (without the http:// part) then you … Read more
To apply the logic of “not any” you would want to check if it is any of the valid results then invert. (NOR) if not (diff == “1” or diff == “2” or diff == “3”): Or applying DeMorgan’s theorem this would be equivelent to “not equal to 1 AND not equal to 2 AND … Read more
In fragment you inflate the layout not setContentView the code maybe look like this @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { View rootView = inflater.inflate(R.layout.fragment1_layout, container, false); // Put your fragment code here return rootView; } 9 solved error: cannot find symbol method setContentView(int) [duplicate]
Use Counter >>> from collections import Counter >>> c=Counter() >>> for d in l: … c.update(d) … >>> dict(c) {‘a’: 30, ‘b’: 15} 1 solved python : Get the sum of values of a key in list of dictionaries [duplicate]
It seems to me like it should be. foreach($result[‘currency’]as $item) { print $item[‘value’]; } Because each currency is 0,1,2 and so on. And in the item 0,1,2 there is the “value”. 1 solved Parse JSON object with PHP [duplicate]
Add printTwice(‘bruce’) on a new line after the function, with no indentation like so: def printTwice(bruce): print(‘bruce’) print(‘bruce’) printTwice(‘bruce’) This line will call your printTwice function, passing the value ‘bruce’ to the variable bruce, which is not used. 1 solved User-Defined Functions and Learning to Think Like a Computer Scientist with Python [closed]
Try this way its working for me public class MainActivity extends Activity { @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); String sHtmlTemplate = “<html><head></head><body><img src=\”file:///android_asset/ic_launcher.png\”><p>Hello Webview.</p></body></html>”; WebView wb = new WebView(this); wb.loadDataWithBaseURL(null, sHtmlTemplate, “text/html”, “utf-8”,null); setContentView(wb); } } Output: 2 solved android: how to using image in asset folder in html to load in … Read more
Your problem is here: //push single code on the block func (s *SmartContract) pushCode(APIstub shim.ChaincodeStubInterface, args []string) sc.Response { hsCode := args[0] lenChk := checkHashLen(hsCode) if lenChk == false { fmt.Println(“Length should be 32”) continue } codeBytes, _ := json.Marshal(hsCode) APIstub.PutState(strconv.FormatInt(makeTimestamp(), 10), codeBytes) return shim.Success(nil) } The error explains what is going wrong. You’re using … Read more
Your code has three issues: 1. if (a == “david”) a decays to a pointer to the first element of array a. “david” is a string literal. With the if Statement, you attempt to compare the address of the array a by the address of the string literal “david”. String comparison dies not work that … Read more
However, I do include a main class, in a class I call Hash.cpp In C++, you need to have a main function, not class or a method in a class as it appears in other OOP languages. That is the entry point for your program. That is not quite fair, since there is some preprocessing … Read more
This code should do the work: bytes = [i for i in range(2**(n))] AB= [] for obj in bytes: t = str(bin(obj))[2:] t=”0″*(n-len(t)) + t AB.append(t.replace(‘0′,’A’).replace(‘1′,’B’)) n being the string size wanted solved The Concept Behind itertools’s product Function
Why not preselect your random celebrities, one per round? import random celebs = [ “a”, “b”, “c”, “d”, “e”, “f”, “g”, “h”, “i”, “j”, “k”, “l”, “m”, “n”, “o”, “p”, “q”, “r” # need at least 15 ] chosen = random.sample(celebs, 15) for round,celeb in enumerate(chosen, 1): print(“{}: {}”.format(round, celeb)) which gives 1: j 2: … Read more
Possible Solution 1 You can have two data templates which share some UI, and one has some more elements than the other. The issue you will have is how to update to a different template on click on the fly. I recently answered a question here which solves this issue by subscribing to the IsSelected … Read more