Kirat It doesn’t work because .next() returns a String. Instead, read the first character of the string returned. Scanner input = new Scanner(System.in); String temp = input.nextLine(); char ch = temp.charAt(0); int a = (int) ch; System.out.println(a); 0 solved java convert a english letter to unicode [closed]
It seems that calling $( ‘.none’ ).hide(); twice is unnecessary. Since this is the same type of functionality, add the same class to each of the elements for the click function. Then you want to match it to the list, one way to do this is through a matching attribute so it can be selected. … Read more
For example if this is frontend and their are checkboxes and their are UNchecked atm Size (group_id) 10m (option_id: 52) (21 products) 20m (option_id: 51) (1 product) Color (group_id) Green (option_id: 49) (22 products) Black (option_id: 38) (1 product) SELECT COUNT(DISTINCT CASE WHEN option_id = 52 THEN product_id END) p52, COUNT(DISTINCT CASE WHEN option_id = … Read more
Button and TextView are class names. When I type: private Button myButton; I create a reference to an object of type button that points to an empty address location. If I then instantiate an object as follows: myButton = new Button(); myButton will refer to a newly created Button object in the program’s memory. For … Read more
y = rand(20,3); Creates a matrix of uniformly distributed random numbers, y. aa= unidrnd(2,20,3) – 1; Creates a matrix of uniformly distributed random integers, that goes from 1 to 2, and then subtract one. Thus, aa is a matrix of 0s and 1s. val = ( aa & y<1.366e-04) | (~aa & y<8.298e-04); This line … Read more
Something like this worked for me, I hope it helps: ([0-9]+ [+,\-,*,\/])/g This way it will return every occurance that matches [number][whitespace][operator]. Tested here Regex Tester 0 solved How do I setup regex to accept only [digit][white space][operator]?
Your problem is a very specific one. I don’t see how this will be of any use to anybody but yourself. There is no ‘one line solution’. There are many ways to approach indexing problems, I like to use scalar indexing when possible: Ncolumns = size(Matrix,1); Nblocks = floor(Ncolumns/4); %number of 4-line blocks (excluding the … Read more
You have not set a LayoutManager to your RecyclerView: use this to set LayoutManager to your RecyclerView: mRecyclerView.setLayoutManager(new LinearLayoutManager(this)); in oncreate 10 solved Arraylist become null
Use Linkedin V2 API.Below code will upload the image. curl -i –upload-file /Users/peter/Desktop/superneatimage.png –header “Authorization: Bearer redacted” ‘https://api.linkedin.com/mediaUpload/C5522AQGTYER3k3ByHQ/feedshare-uploadedImage/0?ca=vector_feedshare&cn=uploads&m=AQJbrN86Zm265gAAAWemyz2pxPSgONtBiZdchrgG872QltnfYjnMdb2j3A&app=1953784&sync=0&v=beta&ut=2H-IhpbfXrRow1’ I suggest you to use Guzzle HTTP client to exicute this in your PHP application solved How can i upload and post an image to linkedin using api?
You might want to try future statements. Basically, keep the code the way it is, and backport features to 2.7. I already see the print statements causing problems, so at the top just add from __future__ import print_statement. This will cause Python 2.7 to read print as if it were running in 3.x. Running the … Read more
If you are iterating over an object, you need to use the each key, value in obj notation: each key, city in cities h2 asdf each foo in city .col-md-4 .row.bottomPadding .col-md-3 img(src=foo.logo_image_url) .col-md-9.text-nowrap p.nav.hide-overflow= foo.name solved How to render array of array of objects in Jade
It is not possible to have a form in a form. Split the forms, and if you want to access an input field outside the form tags use it as this: <input type=”checkbox” name=”product” value=”1″ form=”pushForm”> <form id=”pushForm” role=”form” method=”POST” action=”/products/add”></form> solved Get the value of a form in bootstrap
Oslo: http://www.microsoft.com/soa/products/oslo.aspx Dublin: http://www.microsoft.com/NET/Dublin.aspx 5 solved Microsoft Codename? [closed]
Here’s a method using Array.forEach(): const number = 165; const candidates = [2, 42, 82, 122, 162, 202, 242, 282, 322, 362]; //looking for the lowest valid candidate, so start at infinity and work down let bestCandidate = Infinity; //only consider numbers higher than the target const higherCandidates = candidates.filter(candidate => candidate > number); //loop … Read more
You need to convert the calculated number into a string before performing string methods on it. This might help: (“Celcius is:” + str(celcius)) You could also use the following method if you do not want to convert float to string: (“Celcius is: {}”.format(celcius)) 0 solved python，typeerror：cannot concatenate ‘str ‘and ‘float’ objects